AP Calc AB - AP calc memorization flash cards

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58 Terms

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Limit definition of a derivative

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Intermediate Value Theorem (IVT)

If the function f(x) is continious on [a,b] and y is a number between f(a) and f(b) then there exists at least one number x = c in the open interval (a,b) such that f(c ) = y

<p>If the function f(x) is continious on [a,b] and y is a number between f(a) and f(b) then there exists at least one number x = c in the open interval (a,b) such that f(c ) = y</p>
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Mean Value Theorem (MVT)

If the function f(x) is continuous on [a,b] AND the first derivative exists on the interval (a,b) then there is at least one number x = c in (a,b) such that f’(c ) = f(b) - f(a) / b - a

<p>If the function f(x) is continuous on [a,b] AND the first derivative exists on the interval (a,b) then there is at least one number x = c in (a,b) such that f’(c ) = f(b) - f(a) / b - a</p>
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Rolle’s Theorem

If the function f(x) is continuous on [a,b] AND the first derivative exists on the interval (a,b) AND f(a) = f(b) then there is at least one number x = c in (a,b) such that f’(c ) = 0

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Extreme Value Theorem

If the function f(x) is continuous on [a,b], then the function is guaranteed to have an absolute maximum and an absolute minimum on the interval.

<p>If the function f(x) is continuous on [a,b], then the function is guaranteed to have an absolute maximum and an absolute minimum on the interval.</p>
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d/dx (x^n)

nx^(n-1)

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d/dx(sinx)

cos x

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d/dx(cos x)

-sin(x)

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d/dx(tanx)

sec²x

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d/dx(cotx)

-csc²x

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d/dx(sec x)

secx * tan x

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d/dx (cscx)

-cscx * cotx

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d/dx (ln u)

1/u * du/dx

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d/dx(e^u)

e^u du/dx

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chain rule

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product rule

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Quotient Rule

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Derivative of an Inverse function

if f has an inverse function g then:

derivatives are reciprocal slopes

<p>if f has an inverse function g then:</p><p>derivatives are reciprocal slopes</p>
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Implicit Differentiation

You will have dy/dx for each y in the original function or equation

  1. Isolate the dy/dx

  2. if taking second derivative d²y/dx², you will substitute expression you found for first derivative somewhere in the process

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Average Rate of Change / AROC

f(b) - f(a) / b - a

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Instantaneous Rate of Change / IROC

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Curve Sketching an Analysis

y = f(x) must be continuous at each:

  1. Critical Point: dy/dx = 0 or undefined

    1. LOOK OUT FOR ENDPOINTS

  2. Local minimum

    1. dy/dx goes (- , 0, +) or (-, und, +) or d²y/dx²>0

  3. Local Maximum

    1. dy/dx goes (+,0,-) or (+,und,-) or d²y/dx²<0

  4. Point of Inflection: concavity changes

    1. d²y/dx² goes from (+,0,-), (-,0,+), (+,und,-) OR, (-,und+)

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First Derivavtive

f’(x) > 0 function is increasing

f'(x) < 0 function is decreasing

f’(x) = 0 or DNE: Critical Values at x

Relative Maximum: f’(x) = 0 or DNE and sign of f’(x) changes from + to -

Relative Minimum: f’(x) = 0 or DNE and sign of f’(x) changes from - to +

Absolute Max or Min - MUST CHECK ENDPOINTS ALSO:

the maximum value is a y-value

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Second Derivative

f’’(x) > 0 function is concave up

f’’(x) < 0 function is concave down

f’(x) = 0 and sign of f’’(x) changes, then there is a point of inflection at x

Relative Maximum: f’’(x) < 0

Relative Minimum: f’’(x) > 0

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Write the equation of a tangent line at a point:

You need a slope (derivative) and a point

y2 - y1 = m(x2-x1)

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Horizontal Asymptotes

<p></p>
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ONLY FOUR THINGS THAT YOU CAN DO ON A CALCULATOR THAT NEEDS NO WORK SHOWN

  1. Graphing a function within an arbitrary view window

  2. finding the zeros of a function

  3. computing the derivative of a function numerically

  4. computing the definite integral of a function numerically

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Distance, Velocity, and Acceleration

x(t) = position function

v(t) = velocity function

a(t) = acceleration function

Speed is |velocity|

<p>x(t) = position function</p><p>v(t) = velocity function</p><p>a(t) = acceleration function</p><p></p><p>Speed is |velocity|</p>
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Displacement

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Total Distance

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average velocity

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accumulation

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Logarithms Definitions

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Exponential Growth and Decay

When Solving a differential equation:

  1. seperate variables first

  2. integrate

  3. add +C to one side

  4. Use initial conditions to find “C”

  5. Write the equation in the form y = f(x)

<p>When Solving a differential equation:</p><ol><li><p>seperate variables first</p></li><li><p>integrate</p></li><li><p>add +C to one side</p></li><li><p>Use initial conditions to find “C”</p></li><li><p>Write the equation in the form y = f(x)</p></li></ol><p></p>
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Fundamental Theorem of Calculus

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Corallary to FTC

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Average Value

If the function f(X) is continuous on [a,b] and the first derivative exists on the interval (a,b) then there exists a number x = c on (a,b) such that favg= 1/(b-a) intab f(x)dx = intabf(x)dx/b-a

This value f(c ) is the “average value” of the ifunction on the integral [a,b]

<p>If the function f(X) is continuous on [a,b] and the first derivative exists on the interval (a,b) then there exists a number x = c on (a,b) such that f<sub>avg</sub>= 1/(b-a) int<sub>a</sub><sup>b</sup> f(x)dx = int<sub>a</sub><sup>b</sup>f(x)dx/b-a</p><p>This value f(c ) is the “average value” of the ifunction on the integral [a,b]</p>
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Riemann Sums

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Sin(0) Cos(0) tan(0)

0, 1, 0

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sin(pi/6), cos(pi/6), tan(pi/6)

1/2, sqrt(3)/2, sqrt(3)/3

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sin(pi/4), cos(pi/4), tan(pi/4)

sqrt(2)/2, sqrt(2)/2, 1

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sin(pi/3), cos(pi/3), tan(pi/3)

sqrt(3)/2, 1/2, sqrt(3)

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sin(pi/2), cos(pi/2), tan(pi/2)

1, 0, infinite

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sin(pi), cos(pi), tan(pi)

0, -1, 0

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Area of cross section for squares

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area between equilateral triangles

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area between isosceles right triangles

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area between curves rectangles

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area between semi-circles

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volume by washer method - about y and x axis

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Area Between Two Curves

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volume by disk method

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volume by washer method

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