Gene Linkage and Gene Mapping

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63 Terms

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What is chiasma?

Site of crossover

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What is crossing over?

Reciprocal exchange of homologous chromatid segments

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What does crossing over result into?

Recombinant chromosomes

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How could a cross over not alter chromosome arrangement?

Crossover which occur outside the region between 2 genes will not alter their arrangement

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What are homologous chromosomes?

Paired chromosomes that carry the same genes but different alleles of those genes

  • 1 member of each homologous pair comes from mom and the other from dad

<p><strong><span style="color: purple">Paired chromosomes </span></strong>that carry the <strong><span style="color: purple">same genes</span> </strong>but <strong><span style="color: purple">different alleles</span> </strong>of those <strong><span style="color: purple">genes</span></strong></p><ul><li><p><strong><span style="color: purple">1 member</span> </strong>of <strong><span style="color: purple">each homologous pair</span> </strong>comes from <strong><span style="color: purple">mom</span> </strong>and the <strong><span style="color: purple">other</span> </strong>from <strong><span style="color: purple">dad</span></strong></p></li></ul>
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What are linked genes?

Genes that are close together on the same chromosome

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How are linked genes inherited?

Inherited as a unit together

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Therefore, what is genetic linkage?

Refers to the tendency of genes that are located close together on the same chromosome to be inherited together more often than would be expected

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So how can we see if 2 genes are linked and how tightly?

By using data from genetic crosses to calculate recombination frequency

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What are unlinked genes?

Genes that are on different chromosomes (non-homologous chromosomes) OR far apart on the same chromosome

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Therefore how are unlinked genes organized?

They are assorted independently

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What does independent assortment mean?

When genes go into gametes, the allele received for one gene doesn’t affect the allele received for the other

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Therefore for double heterozygous (AaBb) regardless on different chromosome or far apart on same chromosome, what is the result of gamete formation? And what is the ratio?

AaBb gamete results in 4 possible types of gametes with equal 25% frequency

Ratio: 1:1:1:1

<p><strong><span style="color: red">AaBb gamete</span> </strong>results in <strong><span style="color: red">4 possible types </span></strong>of <strong><span style="color: red">gametes</span> </strong>with <strong><span style="color: red">equal 25% frequency</span></strong></p><p><strong><u>Ratio:</u></strong><span style="color: red"> </span><strong><span style="color: red">1:1:1:1</span></strong></p>
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Why do AaBb on SEPARATE CHROMOSOMES results in 4 gametes with equal 25% frequency?

  • Assort independently

  • Due to the random orientation of homologous chromosomes pairs during meiosis

<ul><li><p><strong><span style="color: red">Assort independently</span> </strong></p></li><li><p>Due to the <strong><span style="color: red">random orientation </span></strong>of <strong><span style="color: red">homologous chromosomes pairs </span></strong>during meiosis </p></li></ul>
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Why do AaBb on SAME CHROMOSOME BUT VERY FAR APART result in 4 gametes with equal 25% frequency

  • Assort independently

  • Due to crossing over (homologous recombination)

  • Resulting in new alleles to be put together in combination on same chromosome

    • Causing them to go into same gamete

<ul><li><p><strong><span style="color: red">Assort independently</span></strong></p></li><li><p>Due to <strong><span style="color: red">crossing over </span></strong>(<strong><span style="color: red">homologous recombination</span></strong>) </p></li><li><p>Resulting in <strong><span style="color: red">new alleles </span></strong>to be put <strong><span style="color: red">together in combination</span> </strong>on <strong><span style="color: red">same chromosome </span></strong></p><ul><li><p>Causing them to go into <strong><span style="color: red">same gamete </span></strong></p></li></ul></li></ul>
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What is another way to represent the gamete percentage in unlinked genes?

  • 50% show similar phenotype of parent

  • 50% show recombinant phenotype

<ul><li><p><strong><span style="color: red">50%</span> </strong>show<span style="color: red"> </span><strong><span style="color: red">similar phenotype </span></strong>of <strong><span style="color: red">parent</span> </strong></p></li><li><p><strong><span style="color: red">50%</span> </strong>show<span style="color: red"> </span><strong><span style="color: red">recombinant phenotype </span></strong></p></li></ul>
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What does recombinant mena?

The production of new combinations of alleles at 2 or more loci

Mix of both parents chromosome

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What would the result be for crossing over that occurs in genes that are very close together on same chromosome?

Gamete types produced is different compared to unlinked chromosomes

  • DO NOT assort independently

  • Instead genes tend to stick together during meiosis

  • Causing it to be passed as a unit to gametes

  • Ratio of gametes are in unequal proportions

<p><strong><span style="color: blue">Gamete types</span> </strong>produced is <strong><span style="color: blue">different</span> </strong>compared to <strong><span style="color: red">unlinked chromosomes </span></strong></p><ul><li><p><strong><span style="color: red">DO NOT</span><span style="color: blue"> assort independently </span></strong></p></li><li><p>Instead <strong><span style="color: blue">genes</span> </strong>tend to <strong><span style="color: blue">stick together</span> </strong>during meiosis </p></li><li><p>Causing it to be passed<strong> </strong>as a <strong><span style="color: blue">unit</span> </strong>to <strong><span style="color: blue">gametes</span></strong></p></li><li><p><strong><span style="color: blue">Ratio</span> </strong>of <strong><span style="color: blue">gametes</span> </strong>are in <strong><span style="color: blue">unequal proportions</span></strong></p></li></ul>
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What are the 2 types of configuration does crossing over in linked chromosomes cause?

  • Parental configuration of alleles

  • Recombinant configuration of alleles

Therefore not what Mendel’s law predicted

<ul><li><p><strong><span style="color: green">Parental configuration</span> </strong>of alleles</p></li><li><p><strong><span style="color: yellow">Recombinant configuration</span> </strong>of alleles</p></li></ul><p>Therefore <strong><span style="color: red">not</span></strong> what <strong><span style="color: blue">Mendel’s law predicted </span></strong></p>
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Why did Mendel not discover linked and unlinked genes?

Because he only studied R (round vs wrinkled) and Gp (green vs yellow) genes which are both on chromosome V BUT are so far apart from each other

  • Thus, they segregate independently and there’s 1 cross over that occurs

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Give an example of pea genes that are linked (Mendel didn’t cross this)

Le (long vs short internode) and V (inflated vs constricted pod) are linked because =

  • Both are on chromosome III

  • They are close together

  • Very few crossover occurs

Thus, they do not segregate independently

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Which type of configuration is rare and when does it form?

Rare: Recombinant configuration of alleles

When: Only form if crossover (recombination event) occurs between genes which rarely happens

<p><strong><u>Rare:</u></strong> <strong><span style="color: yellow">Recombinant configuration</span> </strong>of <strong><span style="color: yellow">alleles</span></strong></p><p><strong><u>When:</u></strong> Only form if <strong><span style="color: yellow">crossover</span> </strong>(recombination event) occurs <strong><span style="color: yellow">between genes</span> </strong>which<span style="color: yellow"> </span><strong><span style="color: yellow">rarely happens</span></strong></p>
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What is parental configuration of alleles?

Alleles that are already together on the chromosome before meiosis

  • On chromosome it got from parents

<p><strong><span style="color: green">Alleles</span> </strong>that are <strong><span style="color: green">already together </span></strong>on the chromosome <strong><span style="color: green">before meiosis </span></strong></p><ul><li><p>On chromosome it got<span style="color: green"> </span><strong><span style="color: green">from parents </span></strong></p></li></ul>
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Therefore how does this relate to recombination frequency?

  • What is it?

The frequency of recombination events between 2 genes is used to estimate their relative distance apart on chromosome

  • Close-together genes = few recombination events

  • Slightly further apart genes = more recombination events (less tightly linked)

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Example of how to find recombination frequency

We want to see if 2 genes in fruit flies are linked and if so, how tightly linked =

  • Purple gene =

    • Dominant pr+ allele = Normal red eyes

    • Recessive pr allele = Purple eyes

  • Vestigial gene =

    • Dominant vg+ allele = Normal, long wings

    • Recessive vg allele = Short “vestigial” wings

Q: What is step 1 and why do we need to do it?

Step 1: Cross 2 homozygous flies together

Why: Produces a double heterozygous

  • In which we know which alleles are together on the chromosome

<p><strong><u>Step 1:</u></strong> <strong><span style="color: yellow">Cross 2 homozygous</span> </strong>flies together </p><p><strong><u>Why:</u></strong> Produces a <strong><span style="color: yellow">double heterozygous </span></strong></p><ul><li><p>In which we <strong><span style="color: yellow">know which alleles</span> </strong>are <strong><span style="color: yellow">together</span> </strong>on the <strong><span style="color: yellow">chromosome</span></strong></p></li></ul>
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Cont. example of how to find recombination frequency

Step 2: Cross double heterozygous with a tester

Q: Why does this need to occur and what is the tester?

Tester: A fly that is homozygous recessive for all genes

Why this occurs: Tester ensures that alleles from non-tester parent fully determines the phenotype

<p><strong><u>Tester:</u></strong> A fly that is <strong><span style="color: red">homozygous recessive</span> </strong>for all genes </p><p><strong><u>Why this occurs:</u></strong> <strong><span style="color: red">Tester</span> </strong>ensures that <strong><span style="color: yellow">alleles</span> </strong>from <strong><span style="color: yellow">non-tester</span> </strong>parent<span style="color: yellow"> </span><strong><span style="color: yellow">fully determines</span> </strong>the <strong><span style="color: yellow">phenotype</span> </strong></p>
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Cont. example of how to find recombination frequency

What is produced when double heterozygous is crossed with tester AND how can we tell that the purple and vestigial genes are linked?

Produced 4 different gametes each with different phenotypes

Genes are linked because: The 4 classes of offspring is not produced in equal numbers

  • Parental chromosome configurations (pr+ vg+/pr vg AND pr vg/ pr vg) = over-represented

  • Recombinant chromosome configurations (pr+ vg/pr vg AND pr vg+/pr vg) = under-represented

<p><strong><u>Produced</u> <span style="color: yellow">4 different gametes</span> </strong>each with <strong><span style="color: yellow">different phenotypes</span></strong></p><p><strong><u>Genes are linked because:</u></strong> The 4 classes of offspring is <strong><span style="color: yellow">not produced in equal numbers </span></strong></p><ul><li><p><strong><span style="color: green">Parental</span> </strong>chromosome configurations<strong> (<span style="color: purple"><mark data-color="purple">pr+</mark></span> <span style="color: blue"><mark data-color="blue">vg+</mark></span>/<mark data-color="purple">pr</mark> <mark data-color="blue">vg</mark></strong> AND <strong><mark data-color="purple">pr</mark> <mark data-color="blue">vg</mark>/ <mark data-color="purple">pr</mark> <mark data-color="blue">vg</mark>)</strong> = <strong><span style="color: green">over-represented</span> </strong></p></li><li><p><strong><span style="color: red">Recombinant</span> </strong>chromosome configurations<strong> (<span style="color: purple"><mark data-color="purple">pr+</mark> </span><mark data-color="blue">vg</mark>/<mark data-color="purple">pr</mark> <mark data-color="blue">vg</mark></strong> AND <strong><mark data-color="purple">pr</mark> <span style="color: blue"><mark data-color="blue">vg+</mark></span>/<mark data-color="purple">pr</mark> <mark data-color="blue">vg</mark>) </strong>= <strong><span style="color: red">under-represented </span></strong></p></li></ul>
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Why is red-eyed, vestigial-wing files (pr+ vg/pr vg) AND purple-eyed, long winged files (pr vg+/pr vg are recombinant?

2 reasons why:

  1. They inherited a chromosome from their mother that has undergone a recombination event

  2. They are the underrepresented classes

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Cont. example of how to find recombination frequency

As a result =

  • Parental chromosome configuration:

    • pr+ vg+/pr vg = 1339

    • pr vg/ pr vg = 1195

  • Recombinant chromosome configuration:

    • pr+ vg/pr vg = 151

      • Red eyed, vestigial winged flies

    • pr vg+/pr vg = 154

      • Purple eyed, long winged flies

Q: What is the equation for recombination frequency (RF) and use it to calculate the RF for this case

Equations: Recombinant frequency = Recombinants/Total Offspring x 100%

Calculate: (151 + 154)/(1339 + 1195 + 151 + 154) x 100% = 10.7%

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ANOTHER EXAMPLE OF GENETIC LINKAGE: MORGAN’S EXPERIMENT

There is a mutation that makes fly’s eyes white and their wings miniature (recessive) and is found only on X chromosome

Dominant:

  • (w+) red eye gene

  • (m+) normal wings gene

Recessive:

  • (w) white eye gene

  • (m) miniature wings gene

P generation =

  • w m/w m

    • Recessive female with white eyes and miniature wings

  • w+ m+/Y

    • Dominant male with red eyes and normal wings

    • Wild type

Q: What is the F1 generation as a result of the crossing of P generation?

  • w+ m+/w m

    • Dominant female with red and normal wings

  • w m/ Y

    • Recessive male with white and miniature wings

    • Hemizygous recessive (only has one member of chromosome pair)

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CONT. MORGAN’S EXPERIMENT

F2 generation

What are the genotypes

Which are parental and recombinant

So are genes linked or unlinked

Genotype:

  • w m/w m

  • w+ m+/Y

  • w m+/w m+

  • w+ m/Y

Parental:

  • w m/w m

  • w+ m+

Recombinant: Occurred about only 37% (below 50%)

  • w m+/w m+

  • w+ m

Genes are: Linked

<p><strong><u>Genotype:</u></strong></p><ul><li><p><strong><mark data-color="red">w m/w m</mark></strong></p></li><li><p><strong><span style="color: blue">w+ m+</span>/Y</strong></p></li><li><p><strong><mark data-color="red">w</mark> <span style="color: blue">m+</span>/<mark data-color="red">w</mark> <span style="color: blue">m+</span></strong></p></li><li><p><strong><span style="color: blue">w+</span> <span style="color: red">m/</span>Y</strong></p></li></ul><p><strong><u>Parental:</u></strong></p><ul><li><p><strong><span style="color: green">w m/w m</span></strong></p></li><li><p><strong><span style="color: green">w+ m+</span></strong></p></li></ul><p><strong><u>Recombinant:</u></strong> Occurred about only <strong><span style="color: yellow">37%</span> </strong>(below 50%)</p><ul><li><p><strong><span style="color: yellow">w m+/w m+</span></strong></p></li><li><p><strong><span style="color: yellow">w+ m</span></strong></p></li></ul><p><strong><u>Genes are:</u></strong> <strong><span style="color: yellow">Linked</span></strong></p>
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Therefore what acts like a test cross to discover whether genes are linked or not?

F1 interbreeding

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What type of chromosome configuration would meiosis with NO crossover result to?

All parental chromosome configuration

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What type of chromosome configuration would meiosis WITH crossover result to?

Parental and recombinant chromosome configuration

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What is the relationship between recombination frequency and distance between genes?

Increasing distances between genes = RF increases

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What do linkage (gene) maps determine?

Determines =

  • Order of genes

  • Relative distance between genes in map units

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What is the mapping function?

Shows the relation between genetic map distance and the frequency of recombination

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<p>Why is the <strong><span style="color: green">distances</span> </strong>in the<span style="color: red"> </span><strong><span style="color: red">physical map </span></strong>and the <strong><span style="color: green">genetic map different</span></strong>?</p>

Why is the distances in the physical map and the genetic map different?

Because there are recombination hotspot regions and regions that underestimate the genetic length

BUT THIS DOESN”T MEAN THE PHYSICAL LENGTH OF THE REGION IS ALSO AS LARGE

<p>Because there are <strong><span style="color: purple">recombination hotspot</span> </strong>regions<strong> </strong>and regions that <strong><span style="color: yellow">underestimate</span> </strong>the <strong><span style="color: green">genetic length</span></strong></p><p><strong>BUT THIS DOESN”T MEAN THE PHYSICAL LENGTH OF THE REGION IS ALSO AS LARGE</strong></p>
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What are recombination hotspot and how does this affect the genetic length?

Because there are recombination hotspots which are regions on a chromosome where the frequency of recombination is higher

  • Therefore, this region will appear larger on a genetic map since there are more recombination events detected

<p>Because there are <strong><span style="color: purple">recombination hotspots</span> </strong>which are regions on a chromosome where the <strong><span style="color: purple">frequency of recombination</span> </strong>is <strong><span style="color: purple">higher</span></strong></p><ul><li><p>Therefore, this region will appear <strong><span style="color: purple">larger</span> </strong>on a <strong><span style="color: purple">genetic map </span></strong>since there are <strong><span style="color: purple">more recombination events</span> </strong>detected</p></li></ul>
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What are the regions that underestimate the actual physical length and how does this affect genetic map?

Regions: Heterochromatin (tightly packed DNA) and centromeres

Result: These regions appear shorter

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Why is a linkage map is produced?

Because recombination frequency “maxes out” at 50%

  • So in order to figure out the map distance between genes further apart than 50%, we need to add up the RF of multiple pairs of genes

  • This builds a map

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Why is the maximum recombination frequency 50%?

Because it corresponds to genes being unlinked or assorted independently

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What is the importance of linkage maps?

  • Establish that chromosomes are linear

  • Established that each gene has its own specific place on chromosome

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What 2 ways can recombination frequency be used to build linkage maps?

  • Provides an estimate of physical distance of genes:

    • Larger RF = genes are farther apart

    • Smaller RF = genes are closer together

  • Used to figure out order of genes on chromosome

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How can recombination frequency be used to figure out order of genes and produce linkage maps? Examples uses 3 genes (A,B,C)

  • Genes with largest RF = outermost genes

    • RF (A-C)

  • Genes with inbetween RF = middle genes

    • RF (A-B)

  • Genes with smallest RF = innermost genes

    • RF (B-C)

<ul><li><p>Genes with <strong><span style="color: red">largest RF</span> </strong>= <strong><span style="color: red">outermost genes</span> </strong></p><ul><li><p><strong><span style="color: red">RF (A-C)</span></strong></p></li></ul></li><li><p>Genes with<span style="color: green"> </span><strong><span style="color: green">inbetween RF</span> </strong>= <strong><span style="color: green">middle genes </span></strong></p><ul><li><p><strong><span style="color: green">RF (A-B)</span></strong></p></li></ul></li><li><p>Genes with <strong><span style="color: blue">smallest RF</span> </strong>=<span style="color: blue"> </span><strong><span style="color: blue">innermost genes</span></strong></p><ul><li><p><strong><span style="color: blue">RF (B-C)</span></strong></p></li></ul></li></ul>
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How do you get the recombinant frequency for only 2 genes if 3 is present? (used to find the order of genes)

Add the number of recombinants for those genes together then use the normal equation (RF = RECOM/TOTAL OFFSPRING x 100%)

EX: Find the RF for Ab + aB from

  • AbD = 45

  • Abd = 89

  • aBD = 94

  • aBd = 40

ANS:

  1. (45 + 89) + (94+40) = 268

  2. 286/1448 (total) x 100% = 18.5mu

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What are the units in linkage maps and how can we convert RF to it?

Units: Centimorgan or map unit

Convert: No need to convert because 1 RF = 1 centimorgan

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Why is the direct RF is not the same as the map distance?

Because double crossovers can also occur

  • BUT they are invisible if only monitoring 2 genes because it would just put them back on original position

Therefore when there is more than 2 genes, double crossovers are detected making the direct RF measurement of 2 genes smaller than the map distance

<p>Because <strong><span style="color: purple">double crossovers</span> </strong>can<span style="color: purple"> </span><strong><span style="color: purple">also occur</span></strong></p><ul><li><p><strong> </strong>BUT they are <strong><span style="color: purple">invisible</span> </strong>if only monitoring <strong><span style="color: purple">2 genes</span> </strong>because it would just put them back on<span style="color: purple"> </span><strong><span style="color: purple">original position </span></strong></p></li></ul><p>Therefore when there is <strong><span style="color: purple">more than 2 genes</span>, <span style="color: purple">double crossovers</span> </strong>are <strong><span style="color: purple">detected</span> </strong>making the <strong><span style="color: yellow">direct RF measurement </span></strong>of <strong><span style="color: yellow">2 genes</span> <span style="color: red">smaller</span> </strong>than the<span style="color: green"> </span><strong><span style="color: green">map distance </span></strong></p>
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How can we minimize invisible double crossovers to occur?

When RF of closer-together genes pairs are added up because it is more rare

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A-B = 18.5mu

B-D = 6.4mu

A-D = 13.2mu

Q: What is the order of genes an why doesn’t 13.2 + 6.4 NOT equal to 18.5

Order: A——D—B

13.2 + 6.4 not equal to 18.5: Because invisible double cross over occurs

<p><strong><u>Order:</u></strong><span style="color: purple"> </span><strong><span style="color: purple">A——D—B</span></strong></p><p><strong><u>13.2 + 6.4 not equal to 18.5:</u></strong> Because invisible <strong><span style="color: purple">double cross over</span> </strong>occurs </p>
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What is chromosome interference?

Crossovers in one region decreases the probability of a second crossover close by

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What is coefficient of coincidence?

Observed number of double recombinants divided by the expected number

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Calculate the coefficient of confidence for the below when observed is only 8 double recombinants:

B-D = 0.064

A-D = 0.132

Expected:

  1. 0.132 × 0.064 = 0.008

  2. For every 1448 (total) progeny: (1448 × 0.008) = 12.23 double recombinants

Coefficient of coincidence: Observed / Expected

  • 8/12.23 = 0.65

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How to calculate the interference with the coefficient of coincidence

Equation: Interference = 1 - Coefficient of coincidence

Example: 1 - 0.65 = 0.35

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What 3 processes lead to the most genetic variation?

  • Independent assortment

  • Crossing over

  • Random fertilization

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When does crossing over occurs?

Prophase 1 in meiosis

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In a heterozygous with 2 loci, there are 2 arrangements of alleles. What are they?

  • Cis (coupling) arrangement

  • Trans (repulsion) arrangement

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What is the cis arrangement (coupling) of alleles?

  • Has both wild type alleles on one homologous chromosome

  • And both mutants on the other

EX: AB and ab

<ul><li><p>Has <strong><span style="color: yellow">both</span> <span style="color: purple">wild type alleles</span> </strong>on <strong><span style="color: yellow">one homologous chromosome</span> </strong></p></li><li><p>And <strong><span style="color: yellow">both </span><span style="color: green">mutants</span> </strong>on the <strong><span style="color: yellow">other</span> </strong></p></li></ul><p>EX: <strong><span style="color: yellow">AB</span> </strong>and <strong><span style="color: yellow">ab</span></strong></p>
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What is the trans arrangement (repulsion) of alleles?

Has one mutant and one wild-type on EACH chromosome

  • EX: Ab and Ba

<p>Has <strong><span style="color: green">one mutant</span> </strong>and <strong><span style="color: purple">one wild-type</span> </strong>on <strong><span style="color: red">EACH chromosome</span></strong></p><ul><li><p>EX: <strong><span style="color: red">Ab</span> </strong>and <strong><span style="color: red">Ba</span></strong></p></li></ul>
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What would each cross over result in?

  • Crossover between homologs in cis arrangement

  • Crossover between homologs in trans arrangement

Crossover cis arrangement: Results in homologous pair with trans arrangement

Crossover trans arrangement: Results in homologous pair with cis arrangement

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What would be the recombination frequency for linked genes?

RF that is less than 50%

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So if the recombination frequency is more than 50%?

Then the genes are unlinked

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When does recombination (crossing over) take place?

  • Prophase of meiosis 1 = high frequency

  • Interphase of mitosis = low frequency