3.1.11 Electrode potentials & electrochemical cells

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Last updated 4:27 PM on 8/24/26
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What are electrochemical cells?

Two different metals dipped in salt solutions of their own ions & connected by a wire (the external circuit)

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<p>Describe this electrochemical cell </p>

Describe this electrochemical cell

  • Copper electrode is dipped in a solution of Cu2+(aq) ions & a zinc electrode is dipped in a solution of Zn2+(aq) ions

  • Zinc loses electrons more easily than copper, so in the left half-cell, zinc is oxidised to Zn2+(aq) ions, releasing electrons into the external circuit

  • In the right half-cell, the same number of electrons are taken from the external circuit, reducing the Cu2+ ions to copper atoms


<ul><li><p>Copper electrode is dipped in a solution of Cu<sup>2+</sup>(aq) ions &amp; a zinc electrode is dipped in a solution of Zn<sup>2+</sup>(aq) ions</p></li><li><p>Zinc loses electrons more easily than copper, so in the left half-cell, zinc is oxidised to Zn<sup>2+</sup>(aq) ions, releasing electrons into the external circuit</p></li><li><p>In the right half-cell, the same number of electrons are taken from the external circuit, reducing the Cu<sup>2+</sup> ions to copper atoms</p></li></ul><p></p>
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What connects the two solutions in an electrochemical cell?

A salt bridge:

  • a strip of filter paper soaked in potassium nitrate solution, KNO3(aq)

  • Allows the ions to flow between the half-cells & completes the circuit (balances out the charges)


<p><strong> A salt bridge:</strong></p><ul><li><p>a strip of filter paper soaked in potassium nitrate solution, KNO<sub>3</sub>(aq)</p></li></ul><ul><li><p>Allows the ions to flow between the half-cells &amp; completes the circuit (balances out the charges)</p></li></ul><p></p>
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Which way do electrons flow through the wire in an electrochemical cell?

From most reactive metal to the least reactive metal

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How is the voltage/cell potential between two half-cells measured?

By putting a voltmeter in the external circuit

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<p>Describe this half-cell </p>

Describe this half-cell

A half-cell with solutions of two aqueous ions of the same element:

  • a platinum electrode is dipped into the solution, as it is inert & conducts electricity

  • conversion from Fe2+(aq) to Fe3+(aq), or vice versa, happens on the surface of the electrode

  • the direction of the conversion depends on the other half-cell in the circuit

    • if the other cell contains a metal that is less reactive than iron, then Fe2+ will be oxidised to Fe3+ at the electrode

    • if the other cell contains a more reactive metal, Fe3+ will be reduced to Fe2+ at the electrode


<p> A half-cell with solutions of two aqueous ions of the same element:</p><ul><li><p>a platinum electrode is dipped into the solution, as it is inert &amp; conducts electricity</p></li><li><p>conversion from Fe<sup>2+</sup>(aq) to Fe<sup>3+</sup>(aq), or vice versa, happens on the surface of the electrode</p></li><li><p>the direction of the conversion depends on the other half-cell in the circuit</p><ul><li><p>if the other cell contains a metal that is less reactive than iron, then Fe<sup>2+</sup> will be oxidised to Fe<sup>3+</sup> at the electrode</p></li><li><p>if the other cell contains a more reactive metal, Fe<sup>3+</sup> will be reduced to Fe<sup>2+</sup> at the electrode</p></li></ul></li></ul><p></p>
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The reactions that occur at each electrode in a cell are reversible. What determines which direction each reactions goes in?

How easily each metal is oxidised (measured using electrode potentials):

  • a metal that’s easily oxidised has a very negative electrode potential

  • a metal that’s harder to oxidise has a more positive electrode potential


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<p>Which metals are reduced/oxidised &amp; why?</p>

Which metals are reduced/oxidised & why?

  • Oxidised: zinc (zinc half-cell has a more negative electrode potential)

  • Reduced: copper (copper half-cell has a more positive electrode potential)


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How are electrochemical cells drawn (conventional representation) ?

ROOR → Reduced I Oxidised II Oxidised I Reduced:

  1. Use the electrode potentials to work out which half-cell goes on the left & which goes on the right

  2. Write out the left-hand half-equation as an oxidation reaction. Then write out the right-hand half-equation as a reduction reaction

  3. Write out the reactants & products of the oxidation reaction, followed by the reactants & products of the reduction reaction

  4. Add in a salt bridge by drawing two vertical lines between the half-cells

  5. Draw a vertical line between any reagents that are in different phases. Put a comma between any reagents that are in the same phase

  6. If either of the half-cells have a separate electrode (e.g. platinum), put that on the outside & separate it from the half-cell with a vertical line


<p><strong>ROOR → Reduced I Oxidised II Oxidised I Reduced:</strong></p><ol><li><p>Use the electrode potentials to work out which half-cell goes on the left &amp; which goes on the right</p></li><li><p>Write out the left-hand half-equation as an oxidation reaction. Then write out the right-hand half-equation as a reduction reaction</p></li><li><p>Write out the reactants &amp; products of the oxidation reaction, followed by the reactants &amp; products of the reduction reaction</p></li><li><p>Add in a salt bridge by drawing two vertical lines between the half-cells</p></li><li><p>Draw a vertical line between any reagents that are in different phases. Put a comma between any reagents that are in the same phase</p></li><li><p>If either of the half-cells have a separate electrode (e.g. platinum), put that on the outside &amp; separate it from the half-cell with a vertical line</p></li></ol><p></p>
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<p>Draw the conventional representation of this electrochemical cell </p>

Draw the conventional representation of this electrochemical cell

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<p>Write half-equations for the reactions occurring at the positive &amp; negative electrodes of this cell </p>

Write half-equations for the reactions occurring at the positive & negative electrodes of this cell

Positive electrode is on the right-hand side & the negative electrode is on the left-hand side:

  • reduction occurs at the positive electrode: Pb2+ (aq) + 2e- → Pb (s)

  • oxidation occurs at the negative electrode: Al3+ (aq) → Al (s) + 3e-

    • remember → think “NO PRoblem”


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What is the equation to calculate the cell potential (Eθcell) ?

(will always be a positive voltage → more negative Eθ value is being subtracted from the more positive Eθ value)

<p>(will always be a positive voltage → more negative <span>E</span><sup><span>θ </span></sup><span>value is being subtracted from the more positive E</span><sup><span>θ </span></sup><span>value)</span></p>
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<p>Calculate the standard electrode potential of the aluminium half-cell </p>

Calculate the standard electrode potential of the aluminium half-cell

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What factors affect the electrode potential?

Temperature, pressure & concentration:

  • half-cell reactions are reversible → equilibrium position is affected by same changes just like any other reversible reaction


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Changing the equilibrium position changes the cell potential. What is done to get around this issue?

Standard conditions are used to measure electrode potentials:

  • you measure the electrode potential of a half-cell against a standard hydrogen electrode

    • hydrogen gas is bubbled through a solution of aqueous H+ ions

    • a platinum electrode is used as a platform for the oxidation/reduction reactions


<p>Standard conditions are used to measure electrode potentials:</p><ul><li><p>you measure the electrode potential of a half-cell against a standard hydrogen electrode</p><ul><li><p>hydrogen gas is bubbled through a solution of aqueous H<sup>+</sup> ions</p></li><li><p>a platinum electrode is used as a platform for the oxidation/reduction reactions</p></li></ul></li></ul><p></p>
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What are the standard conditions to be used when measuring electrode potentials using the standard hydrogen electrode?

  • Any solutions of ions (H+) must have a concentration of 1.00 moldm-3 (e.g. acid, such as HCl)

  • Temperature must be 298K

  • Pressure must be 100kPa


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What is the standard electrode potential of a half-cell?

The voltage measured under standard conditions when the half-cell is connected to a standard hydrogen electrode

<p>The voltage measured under standard conditions when the half-cell is connected to a standard hydrogen electrode </p>
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What is the electrode potential of the standard hydrogen electrode half-cell?

0.00V

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<p>What is the conventional representation of this electrochemical cell? </p>

What is the conventional representation of this electrochemical cell?

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What is an electrochemical series?

A list of electrode potentials in numerical order for different electrochemical cells:

  • electrode potentials are written starting from the most negative & going down to the most positive

  • half-equations are always written as reduction reactions

  • oxidising agents are on the left & reducing agents are on the right

  • best reducer is always the most negative (think if it’s negative, it’s reduced) & best oxidiser is always the most positive


<p>A list of electrode potentials in numerical order for different electrochemical cells:</p><ul><li><p>electrode potentials are written starting from the most negative &amp; going down to the most positive</p></li><li><p>half-equations are always written as reduction reactions</p></li><li><p>oxidising agents are on the left &amp; reducing agents are on the right</p></li><li><p>best reducer is always the most negative (think if it’s negative, it’s reduced) &amp; best oxidiser is always the most positive </p></li></ul><p></p>
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When two half-equations are put together in an electrochemical cell, which directions do they go in?

  • The half-equation with the more negative electrode potential goes in the direction of oxidation

  • The half-equation with the more positive electrode potential goes in the direction of reduction


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What is the equation to calculate the standard cell potential when two half-cell are connected together?

Work out which half-equation is going in the direction of oxidation & which half-equation is going in the direction of reduction

<p>Work out which half-equation is going in the direction of oxidation &amp; which half-equation is going in the direction of reduction</p>
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<p>Calculate the cell potential of an Mg/Ag electrochemical cell using the two redox reaction equations </p>

Calculate the cell potential of an Mg/Ag electrochemical cell using the two redox reaction equations

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How can electrode potentials be used to predict whether a redox reaction will happen & which direction it will go in?

  1. Find the two half-equations for the redox reaction & write them both as reduction reactions

  2. Use an electrochemical series to work out which half-equation has the more negative electrode potential

  3. Write out the half-equation with the more negative electrode potential going in the direction of oxidation & the half-equation with the more positive electrode potential going in direction of reduction

  4. Combine the two half-equations & write out a full redox equation

This is the feasible direction of the reaction & will give a positive overall Eθ value

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<p>Work out the direction of the reaction when a Zn/Zn<sup>2+</sup> half-cell is connected to a Cu<sup>2+</sup>/Cu half-cell</p>

Work out the direction of the reaction when a Zn/Zn2+ half-cell is connected to a Cu2+/Cu half-cell

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<p>Deduce whether the following redox reaction is feasible or not: Cu(s) + Ni<sup>2+</sup> (aq) → Cu<sup>2+</sup>(aq) + Ni(s)</p>

Deduce whether the following redox reaction is feasible or not: Cu(s) + Ni2+ (aq) → Cu2+(aq) + Ni(s)

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<p>Why do the half-equations have non-reversible arrows?</p>

Why do the half-equations have non-reversible arrows?

It’s impractical to reverse them in a battery:

  • they can be made to run backwards under the right conditions, but this can make the battery leak or explode

  • zinc electrode forms the casing of the battery, so becomes thinner as the zinc is oxidised


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How are batteries recharged?

  • A current is supplied to force electrons to flow in the opposite direction around the circuit & reverse the reactions

  • This is possible as none of the substances in a rechargeable battery escape or are used up


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What are fuel cells?

  • Re-chargeable batteries in which a fuel donates electrons at one electrode & oxygen gains electrons at the other electrode

  • As the fuel enters the cell it becomes oxidised, which sets up a potential difference/voltage within the cell


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What is an example of a fuel cell & how does it work?

The hydrogen-oxygen fuel cell:

  • hydrogen & oxygen gas are fed into two separate platinum-containing electrodes

  • electrodes are separated by an anion-exchange membrane that allows anions (OH⁻ ions) & water to pass through it, but not hydrogen & oxygen gas. The electrolyte is an aqueous alkaline solution (KOH). Hydrogen is fed to the negative electrode

  • reaction at negative electrode is: H2(g) + 2OH⁻(aq) → 2H₂O(l) + 2e⁻

  • the electrons flow from the negative electrode through an external circuit to the positive electrode. The OH⁻ ions pass through the anion-exchange membrane towards the negative electrode. Oxygen is fed to the positive electrode

  • reaction at positive electrode is: O₂(g) + 2H₂O(l) + 4e⁻ → 4OH⁻(aq)

  • overall reaction: 2H₂(g) + O₂(g) → 2H₂O(l)


<p><strong>The hydrogen-oxygen fuel cell:</strong></p><ul><li><p>hydrogen &amp; oxygen gas are fed into two separate platinum-containing electrodes</p></li><li><p>electrodes are separated by an anion-exchange membrane that allows anions (OH⁻ ions) &amp; water to pass through it, but not hydrogen &amp; oxygen gas. The electrolyte is an aqueous alkaline solution (KOH). Hydrogen is fed to the negative electrode</p></li><li><p>reaction at negative electrode is: H<sub>2</sub>(g) + 2OH⁻(aq) → 2H₂O(l) + 2e⁻</p></li><li><p>the electrons flow from the negative electrode through an external circuit to the positive electrode. The OH⁻ ions pass through the anion-exchange membrane towards the negative electrode. Oxygen is fed to the positive electrode</p></li><li><p>reaction at positive electrode is: O₂(g) + 2H₂O(l) + 4e⁻ → 4OH⁻(aq)</p></li><li><p>overall reaction: 2H₂(g) + O₂(g) → 2H₂O(l)</p></li></ul><p></p>
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What are the advantages of fuel cells?

  • Much more efficient than an internal combustion engine in machines (waste a lot of energy as thermal energy) → more energy is converted into kinetic energy

  • Unlike batteries, fuel cells don’t need to be recharged → just need a continuous supply of oxygen & hydrogen gas

  • The only waste product is water & no carbon dioxide is emitted directly from the cell, unlike a combustion engine


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What are the disadvantages of fuel cells?

  • Hydrogen is highly flammable & must be stored & transported correctly

  • It is expensive to transport & store hydrogen → storage of hydrogen is in pressurised containers

  • Energy is required to make the hydrogen & oxygen gas in the first place

    • fossil fuels are generally used to pass water through an electrolysis process → contributes to CO₂ emissions


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Describe the zinc-carbon fuel cell

Non-rechargeable battery:

  • uses Zn(s)/Zn2+(aq) & Cu(s)/Cu2+(aq) reactions

  • zinc rod is the negative electrode & copper rod is the positive electrode

  • at the negative electrode (oxidation): Zn(s) → Zn2+(aq) + 2e-

  • at the positive electrode (reduction): Cu2+(aq) + 2e- → Cu(s)

  • overall equation: Zn(s) + Cu2+(aq) ⇌ Zn2+(aq) + Cu(s)


<p><strong>Non-rechargeable battery:</strong></p><ul><li><p>uses Zn<sub>(s)</sub>/Zn<sup>2+</sup><sub>(aq)</sub>&nbsp;&amp; Cu<sub>(s)</sub>/Cu<sup>2+</sup><sub>(aq)</sub>&nbsp;reactions</p></li><li><p>zinc rod is the negative electrode &amp; copper rod is the positive electrode</p></li><li><p>at the negative electrode (oxidation): Zn(s) → Zn<sup>2+</sup>(aq) + 2e<sup>-</sup></p></li><li><p>at the positive electrode (reduction): Cu<sup>2+</sup>(aq) + 2e<sup>-</sup> → Cu(s)</p></li><li><p>overall equation: Zn(s) + Cu<sup>2+</sup>(aq) ⇌ Zn<sup>2+</sup>(aq) + Cu(s)</p></li></ul><p></p>
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How did Alessandro Volta discover non-rechargeable batteries?

  • Used alternating discs of copper & zinc with damp pads between them

  • Found that by connecting wires to the top & bottom disc, an electric charge passed around the external circuit

    • the voltage was proportional to the number of discs used → called this device a ‘pile’


<ul><li><p>Used alternating discs of copper &amp; zinc with damp pads between them</p></li><li><p>Found that by connecting wires to the top &amp; bottom disc, an electric charge passed around the external circuit</p><ul><li><p>the voltage was proportional to the number of discs used → called this device a ‘pile’</p></li></ul></li></ul><p></p>
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What is the dry cell?

Non-rechargeable battery:

  • contains a paste of manganese dioxide & ammonium chloride around a carbon rod (positive electrode)

  • surrounded by a zinc case (negative electrode)

  • Zn(s) → Zn2+(aq) + 2e-

  • MnO2 + H2O + e- → MnO(OH) + OH-

  • Overall equation: Zn + 2MnO2 + H2O → Zn2+(aq) + 2MnO(OH) + 2OH-


<p><strong>Non-rechargeable battery:</strong></p><ul><li><p>contains a paste of manganese dioxide &amp; ammonium chloride around a carbon rod (positive electrode)</p></li></ul><ul><li><p>surrounded by a zinc case (negative electrode)</p></li><li><p>Zn(s) → Zn<sup>2+</sup>(aq) + 2e<sup>-</sup></p></li><li><p>MnO<sub>2</sub> + H<sub>2</sub>O + e<sup>-</sup> → MnO(OH) + OH<sup>-</sup></p></li><li><p>Overall equation: Zn + 2MnO<sub>2</sub> + H<sub>2</sub>O → Zn<sup>2+</sup>(aq) + 2MnO(OH) + 2OH<sup>-</sup></p></li></ul><p></p>
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What is the lead-acid battery?

Re-chargeable battery:

  • acting as electrodes are plates that separate the cells, immersed in dilute sulphuric acid

  • negative electrodes are plates made from lead & positive electrodes are plates made from lead coated in lead (IV) oxide

  • negative electrode: Pb (s) + SO42- (aq) ⇌ PbSO4 (s) + 2e-

  • positive electrode: PbO2 (s) + SO42- (aq) + 4H+ (aq) + 2e- ⇌ PbSO4 (s) + 2H2O (l)


<p><strong>Re-chargeable battery:</strong></p><ul><li><p>acting as electrodes are plates that separate the cells, immersed in dilute sulphuric acid</p></li><li><p>negative electrodes are plates made from lead &amp; positive electrodes are plates made from lead coated in lead (IV) oxide</p></li><li><p>negative electrode: Pb (s) + SO<sub>4</sub><sup>2- </sup>(aq) ⇌ PbSO<sub>4 </sub>(s) + 2e<sup>-</sup></p></li><li><p>positive electrode: PbO<sub>2</sub> (s) + SO<sub>4</sub><sup>2- </sup>(aq) + 4H<sup>+ </sup>(aq) + 2e<sup>-</sup> ⇌ PbSO<sub>4 </sub>(s) + 2H<sub>2</sub>O (l)</p></li></ul><p></p>
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What are the simplified electrode reactions in a lithium cell?

  • Positive electrode: Li+ + CoO2 + e- → Li+[CoO2]-

  • Negative electrode: Li → Li+ + e-


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List the reactivity series & the mnemonic to remember it

(Most reactive)

  • Please → Potassium

  • Stop → Sodium

  • Calling → Calcium

  • Me → Magnesium

  • A → Aluminium

  • Careless → Carbon

  • Zebra → Zinc

  • Instead → Iron

  • Try → Tin

  • Learning → Lead

  • How → Hydrogen

  • Copper → Copper

  • Saves → Silver

  • Gold → Gold

(Least reactive)