AP Chem Unit 3 Test

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41 Terms

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Endothermic

  • Energy gained

  • Energy as reactant

  • ΔH positive

  • Bonds break

  • Reactants will have less PE than products

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Exothermic

  • Energy lost

  • Energy as product

  • ΔH negative

  • Bonds form

  • Reactants will have more PE than products

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temperature

How hot something is; reflects the average translational KE of molecules

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Heat

thermal energy transfer—flows thermodynamically favorably from hot to cold places

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On a heating curve, PE changes:

During the phase change (plateau)

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On a heating curve, KE changes:

During temperature changes

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Specific heat capacity

The energy required to raise the temperature of one gram of substance one degree Celsius

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Units of specific heat

J/g˚C

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Heat of formation (ΔHf)

The heat gained or lost when ONE mole of compound is formed from its elements under STANDARD conditions

*when balancing chemical equation, need to make sure products only have ONE mole of product

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What is the ΔHf and ΔGf of elements in their standard state?

0

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Hess’ Law

The total energy change in a chemical reaction will be the same if the reaction happens in one step or several steps

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ΔH

change in enthalpy

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ΔH units

kJ/mol, AKA Qsys/molsys

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qsys = ?

-qsurr

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H

enthalpy: the total heat content of a system

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S

Entropy: The measure of the dispersal of matter/energy

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The more possible microstates (arrangements), the _____ the entropy

higher

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What factors affect entropy (in order of importance)?

  1. Phase

  2. Moles

  3. Temperature

  4. Molecular complexity

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more moles = ____ entropy

higher

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higher temp = ___ entropy

higher

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larger molecules = ___ entropy

higher

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Positive ΔS

increase in entropy, increase in dispersal/randomness

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Negative ΔS

decrease in entropy, decrease in dispersal/randomness

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Second law of thermodynamics

The entropy of an isolated system does not decrease—”the entropy of the universe must increase”

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Third law of thermodynamics

The entropy of a perfect crystal at absolute zero (0 K) is exactly equal to zero. 

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Equation for ΔSsurr

ΔSsurr = -ΔH/T

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Spontaneity

A spontaneous reaction is thermodynamically favorable and proceeds to completion without any outside help.

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Is +ΔH favorable?

No, since energy needs to be put into the system

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Is -ΔH favorable?

Yes

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Is +ΔS favorable?

Yes, 2nd law of thermodynamics

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Is -ΔS favorable?

No

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Gibb’s Free Energy

The maximum amount of useful work that can be obtained from a process at standard conditions

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+ΔG

Reaction/process is NOT thermodynamically favorable/spontaneous

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-ΔG

Reaction/process IS thermodynamically favorable/spontaneous

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Relationship between ΔH, ΔS and ΔG

ΔG˚ = ΔH˚ - TΔS˚

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what units of temperature are used in big mama?

KELVIN

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Relationship between ΔG and equilibrium

At equilibrium, ΔG = 0, which means equilibrium is the point where a reaction will become thermodynamically favorable or not favorable

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Calculate the temperature at which a reaction becomes spontaneous

T = ΔH/ΔS (from big mama equation)

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Kinetic Energy (KE)

The energy an object has due to its movement

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Bond Dissociation Energy (BDE)

The energy gained/lost to break/form a specific chemical bond in a molecule

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How to calculate ΔHrxn using BDE

ΔHrxn = ∑bonds broken in reactants - ∑bonds formed in products