3.2 - Amount Of Substance In Relation To Masses Of Pure Substances

5.0(1)
studied byStudied by 16 people
call kaiCall Kai
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/6

Last updated 4:29 PM on 8/2/24
Name
Mastery
Learn
Test
Matching
Spaced
Call with Kai

No analytics yet

Send a link to your students to track their progress

7 Terms

1
New cards

What is Avogadro’s constant?

The number of atoms, molecules or ions in a mole of a given substance. The value of the constant is 6.02 × 1023.

2
New cards

What is the formula that links mass, molecular mass, and moles together?

mass = Mr × moles

3
New cards

What is the mass of 20 moles of calcium carbonate, CaCO3?

  • mass = Mr × moles

  • Mr = 100

  • 100 × 20 = 2000 g

4
New cards

Calculate the amount of carbon dioxide in moles in 0.32 g of carbon dioxide. Relative atomic masses (Ar): carbon = 12 || oxygen = 16

  • moles = mass ÷ Mr

  • 0.32 ÷ 44 = 0.007

5
New cards

Nitrogen and hydrogen form ammonia shown by the following equation:

  • N2 (g) + 3H2 (g) 2NH3 (g)

Calculate the mass of nitrogen needed to form 6.8 tons of ammonia. Relative atomic masses (Ar): H = 1 || N = 14

  • 6800000 ÷ 17 = 400000 moles of ammonia

  • The ratio of nitrogen to ammonia is 1:2

  • 200000 × 28 = 5600000 g = 5.6 tons

6
New cards

State what we mean by a limiting reactant in a chemical reaction.

  • In a chemical reaction involving two reactants, it’s common to use an excess of one of the reactants to ensure that all of the other reactant is used.

  • The reactant that’s completely used up is called the limiting reactant because it limits the amount of products.

7
New cards

Hydrogen peroxide decomposes in water and oxygen. How many grams of oxygen gas will be given off from 40.8 g of hydrogen peroxide?

  • 2H2O2 (l) → 2H2O + O2 (g) || M of HO = 34

  • Number of moles in 40.8 g: 40.8 ÷ 34 = 1.2 moles

  • Ratio in the balanced equation of H2O2 : O2 = 2:1

  • Therefore number of moles of = 0.6 moles

  • Mass of oxygen = 0.6 × 32 (Mr of O2) = 19.2

Explore top notes

Explore top flashcards

flashcards
vocabulario de vida saludable
41
Updated 330d ago
0.0(0)
flashcards
Honors Chemistry elements
57
Updated 177d ago
0.0(0)
flashcards
ECE3161
70
Updated 122d ago
0.0(0)
flashcards
E1a - Verbos regulares
43
Updated 1050d ago
0.0(0)
flashcards
#1/6
31
Updated 77d ago
0.0(0)
flashcards
Histology
57
Updated 1212d ago
0.0(0)
flashcards
WEEK 2.1: Computer Software
105
Updated 2d ago
0.0(0)
flashcards
vocabulario de vida saludable
41
Updated 330d ago
0.0(0)
flashcards
Honors Chemistry elements
57
Updated 177d ago
0.0(0)
flashcards
ECE3161
70
Updated 122d ago
0.0(0)
flashcards
E1a - Verbos regulares
43
Updated 1050d ago
0.0(0)
flashcards
#1/6
31
Updated 77d ago
0.0(0)
flashcards
Histology
57
Updated 1212d ago
0.0(0)
flashcards
WEEK 2.1: Computer Software
105
Updated 2d ago
0.0(0)