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Sinx Df
R
Sinx Ef
[-1;1]
Sinx dideja ^

Sinx mazeja v

Sinx periodas

Sinx>0

Sinx<0

Sin(-x)=
-sinx, nelyginė
Arcsin Df ir Ef

Sinx=0

Sinx=-1

Sinx=1

Nuo kokio tasko prasideda sinx?
(0;0)
Cos(-x)=
cosx, lyginė
Tg(-x)=
-tgx
Arcsin(-x)=
-arcsinx
Arccos(-x)=
Pi - arccosx
arccosx Df ir Ef

Cosx Df
R
Cosx Ef
[-1;1]
Cosx periodas

Cosx dideja ^

Cosx mazeja v

Cosx>0

Cosx<0

Cosx=-1

Cosx=0

Cosx=1

Cosx pradideda nuo tasko
(0;1)
Tgx periodas
T=pi
Tgx Df

Tgx Ef
R
Tgx dideja ^

Tgx mazeja v

Tgx>0

Tgx<0

Tgx=0
