square
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Calculus
Integration
AP Calculus BC
Unit 6: Integration and Accumulation of Change
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s2s²s2
equilateral triangle
34s2\frac{\sqrt{3}}{4}s²43s2
semicircle
π2⋅(diameter2)2\frac{\pi}{2}\cdot{(\frac{diameter}{2})²}2π⋅(2diameter)2
isosceles right triangle
hypotenuse24\frac{hypotenuse²}{4}4hypotenuse2