square
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Calculus
Integration
AP Calculus BC
Unit 6: Integration and Accumulation of Change
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sĀ²
equilateral triangle
\frac{\sqrt{3}}{4}sĀ²
semicircle
\frac{\pi}{2}\cdot{(\frac{diameter}{2})Ā²}
isosceles right triangle
\frac{hypotenuseĀ²}{4}