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the acidity of an aqueous soln depends on
concentration of hydronium ions
pH + pOH =
14.00
strong acids and bases
completely ionize in water
weak acids and bases
partially ionize in water
Ka
acid ionization constant ([A-][H3O+]/[HA]
larger Ka value means
stronger acid
for pH of weak acids
create a RICE table
Kb
base ionization constant, increases with base strength
[BH+][OH-]/[B]
for pH of very dilute solns of strong acids, we must consider
that H20 ā H+ and OH-, which means the pH=-log[H+] doesnāt make sense
polyprotic acids
more than 1 ionizable H atom per molecule
for polyprotic acidsā¦
the first proton comes off readily (strong acid, amphoteric species is created) and the 2nd proton is harder to remove
typically only the first
proton significantly affects pH
more difficult to remove an H+ ion from
a negatively charged anion
Ka for polyprotic acids
Ka1 > Ka2 > Ka3
acidic and basic salts
how do they react in water?
NaF is a basic salt bc
the anion makes OH- in water and the cation makes nothing bc NaOH is a strong base that dissociates
F- + H2O ā HF + OH-
weak acids only
ionize to a limited degree in water
salt hydrolysis occurs when
ions produced by the dissociation of a salt reac with water to produce either hydroxide ions or hydronium ions)
basic salts are
conjugates of weak acids
acidic salts are
conjugates of weak bases
NH4+ + H2O ā> NH3 + H3O+
NH4+ is from NH4Cl
how do we estimate pH of salt solutions?
determine if it is an acidic or basic salt (or neither)
steps to determine acidic or basic salt
split salt into anion + cation
add OH- to the cation and H+ to the anion
which resultant acid or base is stronger?
metal oxides (left)
are basic
nonmetal oxides (right)
are acidic
semi-metal oxides (btwn)
are either acidic or basic
common ion effect
the shift in position of an equilibrium caused by the addition of an ion taking part in the rxn
result of common ion effect
anything that drives eq away from H+ makes solution more basic
buffer
a solution that contains a weak acid and its conjugate base (or vice versa)
oxidation
loss of electrons
reduction
gain of electrons
redox rxn
sum of oxidation ½ rxn and reduction ½ rxn
oxidation number
charge an atom would have if electrons will be transferred completely (can determine which species gains/loses)
ON of atoms in pure elements
0
ON of single atom ions
charge on PT
ON of F
always -1
ON of O
almost always -2
ON of H
almost always +1
ON of neutral compounds
sums to 0
acitivity series for metals
can be used to rank the strength of the metals as reducing agents
a metal cation will oxidize any metal above it in the activity series
electrochem
branch of chem that examines transformations btwn chemical and electrical energy (electron flow)
reducing agent
is oxidized, reduces other species
oxidizing agent
is reduced, oxidizes other species
galvanic cells
use spontaneous rxns where electric current flows from anode ā cathode to harness energy
anode
where oxidation occurs
cathode
where reduction occurs
salt bridges
connect solns and prevent short circuiting
cell diagram (electrochemical cell arrangement)
anode on left, cathode on right, double line in middle for salt bridge
vertical lines to indicate phase or symbol changes of ions
[]s and pps if known
cell diagram example
Zn(s) l Zn2+(1.00M) ll Cu2+(1.00M) l Cu(s)
useful galvanic cells are thermodynamicaly favorable
delta G naught rxn is less than zero
standard reduction potential (E naught)
the potential of a reduction half rxn in which all reactants and products are in their std states at 25C
the more positive value of E naughtā¦
the greater probability it will be reduced
reactants at the top of the activity series are
among the strongest oxidizin agents (more +)
reactants at the bottom of the activity series are
strongest reducing (less +)
E naught cath - E naught an =
E naught cell
more positive E naught value
cathode - reduction
less positive (more negative) E naught value
anode (oxidation)
n for E naught equations
moles of electrons transferred
R for e naught eqns
8.314 (energy!)
F for e naught eqns
Farradayās constant (96,500)
nernst eqn
used to calculate E cell when non-std state conditions (Q = products/reactants)
henderson-hasselbach eqn is used for
determining pH of buffer solns
buffer
soln that resists changes in pH when small quantities of acids or bases are added to it
weak acid reacts with added base
HA + OH- ā H2O + A-
weak base (A-) reacts with added acid
A- + H3O+ ā HA + H2O
after H+ is consumedā¦
the system will react to reestablish equilibrium
for H-H calculations
look at concentrations after consumption of added acid or base!!!
buffer range
pH range within which a given buffer can provide pH protection
pKa ± 1
buffer capacity
quantity of acid or base that a buffer can neutralize while maintaining pH within a desired range
proportional to component concentrations
to make a buffer with a specific pH
pick a weak acid whose pKa is close to desired pH (±1)
substitute pH and pKa into eqn to obtain [conj base]/[weak acid] ratio
pH = pKa + log [A-]/[HA]
choose [buffer] (generally btwn 0.05M and 0.5M) and adjust pH w/ strong acid/base as necessary