P3: Chemical Kinetics

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Last updated 4:30 PM on 5/10/26
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13 Terms

1
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<p>What is the rate coefficient k, Integrate it from t=0 corresponding to A0, to t corresponding to concentration A, draw the van’t hoff plot and state what order is this rxn, rearange to A</p>

What is the rate coefficient k, Integrate it from t=0 corresponding to A0, to t corresponding to concentration A, draw the van’t hoff plot and state what order is this rxn, rearange to A

2
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State the :

1st,Reaction, rate law and integrated rate equation

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3
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State the :

the 2nd A=B

Reaction, rate law and integrated rate equation

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4
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<p>solve</p>

solve

yh with the (-)ive

<p>yh with the (-)ive </p>
5
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what do these equal to:

lnx + lny

lnx - lny

=ln(xy)

=ln(x/y)

e^0 = 1

6
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State the :

2nd for A does not equal B

Reaction, rate law and integrated rate equation

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7
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<p>i</p>

i

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8
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<p>Give the rate law , integrated equation , what kind of rxn is it </p>

Give the rate law , integrated equation , what kind of rxn is it

concurrent reaction , electrophelic substitution rxn

<p>concurrent reaction , electrophelic substitution rxn</p>
9
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<p>what order is a consecutive rxn, writ ethe method to finding the rate of change and do the 1st step here</p>

what order is a consecutive rxn, writ ethe method to finding the rate of change and do the 1st step here

1st order usually so use its equation for integrated

the rxn goes A → B → C with the arrows being k1, k2, and k3 if not given.

after the step in the image we will sub in 7 and 8 into 6

<p>1st order usually so use its equation for integrated </p><p> the rxn goes A → B → C with the arrows being k1, k2, and k3 if not given.</p><p>after the step in the image we will sub in 7 and 8 into 6</p>
10
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What is the key feature of telling the difference between protic and aprotic solvents by only looking at the molecule

Protic solvents contain NH and OH (acidic Hs), dissolve both charges

Aprotic solvents DO NOT CONTAIN (OH) NOR (NH), only dissolves positive charges

11
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state Eyring equation for TS

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12
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Calculate the Free E of activation for 2 different solvents

we isolate G from eyring

Kb( boltzmann constant in JK-1

room T in K , 25celicius → 298K

h plank constant in Js

we know ln(x/yz)= ln(x/y) - lnz

we can sub in for k (rate coeffecient) in M-1s-1

for eg. acetone and then for benzene

then delta delta G dash = delta G dash (Benzene)- delta G dash (acetone)

answer in Jmol-1 we should turn it to KJmol-1

We find rxn favours Polar solvents such as acetone coz they reduce TS free E and stabilise it

<p>we isolate G from eyring</p><p>Kb( boltzmann constant in JK-1</p><p>room T in K , 25celicius  → 298K</p><p>h plank constant in Js</p><p>we know ln(x/yz)= ln(x/y) - lnz</p><p>we can sub in for k (rate coeffecient) in M-1s-1</p><p>for eg. acetone and then for benzene</p><p>then delta delta G dash = delta G dash (Benzene)- delta G dash (acetone)</p><p>answer in Jmol-1 we should turn it to KJmol-1</p><p>We find rxn favours Polar solvents such as acetone coz they reduce TS free E and stabilise it </p>
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