calc final

on interval [0,2pi/5]

exam 1

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explain in depth, look at the exam you took and see where exact he wanted to expand, see and do it again……..exam1

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exam 2

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EXAM2, 1. the fraction is improper, because the top has degree 3 and the bottom has degree 2, So before partial fractions, you would need a polynomial part first……………………. 2. This is a product of distinct linear factors, and the fraction is proper since degree(top) =2=2=2 and degree(bottom) =3=3=3……………………3. So the given decomposition uses the wrong factors, Since x2+4x^2+4x2+4 is an irreducible quadratic, (x²+4) doesnt turn from (x+2)(x+2)

exam3,,, divide by the biggest power from denolomonator or numerator

EXAM3 i swear to god if you dont have +C…..

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use made up formula from sheet, exam 3………….

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exam3, REMINDBER THAT ITS ABSOULTLY CONVERGES FOR EVERYTHING BESIDES ALTERNATING SERIES TEST

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exam3, ABSOLUTY CONVERGES DONT FORGET

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exam 3, dont do integral test on others ever unless absoulty nesscessary, not cause its hard, but because hernendez requried to proof that its decasing by complicated derivaiites and continousing proof and this and that/………JUST AVIOD IT AT ALL COST, too risky

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exam4, center (2,-1), radius is 3

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