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Resultant of a Force System: Components
Rx = ΣFcosα
Ry = ΣFsinα
α is angle wrt x-axis
Resultant of a Force System: Magnitude and Direction
R = √(Rx2 + Ry2)
Θ = tan-1(Ry / Rx)
α is angle wrt x-axis
Moment about a Point
M = Fd
Centroid and Effective Forces
Concentrated Load (Point): F = P
Uniformly Distributed Load: F = wL @ L/2
Uniformly Varying Load (Triangular): F = wL/2 @ L/3
Squared Property of Parabola (Parabolic Cable)
d12 / h1 = d22 / h2
d = distance from lowest point to support
h = height of supports from lowest point
Parabolic Cable: Minimum and Maximum Tension
Tmin = (w dmax2 / 2 hmax)
Tmax = √((Tmin)2 + (w dmax)2)
Length of Catenary Cable
S = (T0 / W0) sinh(W0 x / T0)
Catenary Cable: Tension at any Point
T = T0 cosh(W0 x / T0)
Catenary Cable: Vertical Distance of Lowest Point to any Point of the Cable
y = (T0 / W0) [cosh(W0 x / T0) - 1]
Friction Force
Ff = µs N (static friction)
Ff = µk N (dynamic friction)
Angle of Friction
tanΘ = F / N
when Θ = α, tanα = µ = F / N
Belt Friction
T2 / T1 = eµß
T2 > T1
ß = subtended angle in radians
Rectangle: Area, Centroid, Moment of Inertia
A = bh
Centroid = (b/2, h/2)
Ix = bh3 / 12
Iy = hb3 / 12
Triangle: Area, Centroid, Moment of Inertia
A = bh / 2
Centroid = (b/3, h/3)
Ix = bh3 / 36
Iy = hb3 / 36
Circle: Area, Centroid, Moment of Inertia
A = πr2 = πd2 / 4
Centroid = (d/2, d/2)
Ix = πd4 / 64
Iy = πd4 / 64
Quarter Circle / Spandrel
A = πr2 / 4
Centroid = (4r/3π, 4r/3π)
Ix = 0.055r4
Iy = 0.055r4
Rectilinear Motion: Uniform Motion
s = vt
a = 0
Rectilinear Motion: Uniformly Accelerated Motion
a = constant
v = v0 ± at
s = v0 t ± at² / 2
v² = v0² ± 2a (x - x0)
Rectilinear Motion: Instantaneous vs. Average
Instantaneous Velocity: v = dx / dt
Instantaneous Acceleration: a = dv / dt = d2x / dt2
Average Velocity: vave = (x - x0) / (t - t0)
Average Acceleration: aave = (v - v0) / (t - t0)
Rectilinear Motion: Free Fall
v2 = v1 ± gt
v22 = v12 ± 2gy
y = v1t ± gt2 / 2
t = √(2y / g)
ymax = v12 / 2g
(+) - upwards
(-) - downwards
Projectile Motion
v0x = v0 cosΘ
v0y = v0 sinΘ
x = v0x t
t = v0 sinΘ / g + √(2hmax / g)
hmax = ymax + h
ymax = v02sin2Θ / 2g
Projectile Motion: General Formula for height of projectile
y = xtanΘ - gx2 / (2v02cos2Θ)
Rotational Motion
ω = dΘ / dt
α = dω / dt
s = rΘ
v = rω
Rotational Motion: Acceleration Components
aT = αr
aN = ω2r = v2 / r
a = √(aT2 + aN2)
Work
W = F d
Power
P = W / t
Gravitational Potential Energy
PE = m g h
Spring Potential Energy
PE = kx2 / 2
Kinetic Energy
KE = mv2 / 2
Conservation of Mechanical Energy
PE1 + KE1 = PE2 + KE2
For PE = KE: m g h = mv2 / 2
v = √2gh
Linear Momentum and Impulse
p = m × v
Conservation: mv1 = mv2
J = F × t
Coefficient of Resitution
e = - (vB2 - vA2) / (vB1 - vA1)
Particle Kinetics: Centripetal Force
Fcf = mv2 / r
Particle Kinetics: Banked Curves
Friction is Considered: tan (Θ + Φ) = v2 / gR
Car is Slipping: tan (Θ - Φ) = v2 / gR
Design Angle of Banking: tan (Θ) = v2 / gR
Allowable vs. Ultimate
Allowable = Ultimate / Factor of Safety
Axial Stress
σ = P / A
(P = axial load, A = cross-sectional area where axial load is applied)
Axial Strain
ε = δ / L = σ / E
(δ = deflection/change in length, L = original length, E = modulus of elasticity)
Modulus of Elasticity
E = σ / ε
Axial Deformation/Deflection
δ = PL / AE = σL / E
Thermal Deformation
δT = αLΔT
(α = Coefficient of Thermal Expansion)
Shear Stress (General)
τ = V / As
(V = Shear Force, As = sheared area)
Shear Strain
γ = δs / L
Modulus of Rigidity
G = δs / γ
Shear Deformation
δs = VL / AsG
Bearing Stress
σb = Pb / Ab
Cylindrical Thin-Walled Pressure Vessels
Tangential/Hoop: σT = pD / 2t
Longitudinal/Axial: σL = pD / 4t
(p = internal pressure, D = diameter of vessel, t = thickness)
Spherical Thin-Walled Pressure Vessels
σ = pD / 4t
(p = internal pressure, D = diameter of vessel, t = thickness)
Torsional Shear Stress
τ = Tr / J
(T = torque, r = radius of curvature, J = polar moment of inertia)
Torsion: Angle of Twist
θ = TL / JG
(T = torque, L = length, J = polar moment of inertia, G = modulus of rigidity)
Polar Moment of Inertia
J = Ix + Iy
For circular solid shafts: J = πD4 / 32
For circular hollow shafts: J = π(Do4 - Di4)
Helical Springs: Approximate Maximum Shear Stress
Ss = 16PR/πd3 * (1 + d/4R)
(P = load applied, R = spring radius, d = diameter)
Helical Spring: AM Wahl’s Formula
Ss = 16PR/πd3 * ((4m - 1) / (4m+4) + 0.615/m)
m = 2R/d
(4m - 1) / (4m+4) = Wahl factor
Helical Springs: Deformation
δ = 64PR3n / Gd4
(n = number of turns, G = modulus of rigidity, R = spring radius, P = load applied, d = diameter of wire)
Flexure: Bending Stress
fb = My / I
(M = maximum moment, y = distance of point from NA, I = moment of inertia)
Flexural Shear Stress
fv = VQ / Ib
(V = maximum shear force, Q = A’y’, I = moment of inertia, b = width at section)
Note: A’ = area above/below NA, y’ = distance from centroid of A’ to NA
Shear Flow
q = VQ / I = fv b
(V = maximum shear force, Q = A’y’, I = moment of inertia)
Shear Connector
s = RI / VQ = R/q
(s = pitch of shear connector, R = total resistance of connectors within pitch length)
Flexure for Curved Beams
fb = Ey / ρ
(E = modulus of elasticity, y = point from NA, ρ = radius of curvature)
Flexure: Non-homogeneous beams
n = Es / Eb
b → nb
ftransformed = nMc / I
Combined Stresses
σ = ± P/A ± Mc/I
τ = V/A
τ = VQ/Ib + Tr/J
Mohr’s Circle: Sign Convention
Normal Stress: (+) Tension, (-) Compression
Shear Stress: (+) Clockwise, (-) Counterclockwise
Static Determinacy of Beams (Planar)
DI = R - 3 - C
R - external reactions, C - releases
Static Determinacy of Beams (3D)
DI = R - 6 - C
R - external reactions, C - releases
Static Determinacy of Frames (Planar)
DI = R + 3M - 3J - C
R - external reactions, M - members, J - joints, C - releases
Static Determinacy of Frames (3D)
DI = R + 6M - 6J - C
R - external reactions, M - members, J - joints, C - releases
Static Determinacy of Trusses (Planar)
DI = R + M - 3J
R - external reactions, M - members, J - joints
Static Determinacy of Trusses (3D)
DI = R + M - 2J
R - external reactions, M - members, J - joints
Equations of Conditions (C) for Internal Hinge
M = 0; 2 internal reactions (Fx, Fy)
Equations of Conditions (C) for Internal Roller
Fx = 0, M = 0; 1 internal reaction (Fy)
Equations of Conditions (C) for Internal Fixed
3 internal reactions (Fx, Fy, M)
Equations of Conditions (C) for Internal Slider
Fy = 0; 2 internal reactions (Fx, M)
DIM: Moment Equation
EI y” = M
E = modulus of elasticity, I = moment of inertia
DIM: Slope Equation
EI y’ = ∫ M dx + C1
E = modulus of elasticity, I = moment of inertia
DIM: Beam Deflection Equation
EI y’ = ∫ ∫ (M dx) dx + C1x + C2
E = modulus of elasticity, I = moment of inertia
Area-Moment for Cantilever → Moment at Free End
Area = bh (see figure for components)

Area-Moment for Cantilever → Point Load
Area = bh/2 (see figure for components)

Area-Moment for Cantilever → Uniformly Distributed Load
Area = bh/3 (see figure for components)

Area-Moment for Cantilever → Uniformly Varying Load (max at fixed end)
Area = bh/4 (see figure for components)

Area-Moment Method: Theorem 1
θAB = (Area)AB / EI
Area-Moment Method: Theorem 2
tB/A = (Area)AB / EI * x̄B

Area-Moment Method: Rotation at A
y’A = θA = tB/A / L = (tC/A + δC) / xC


Area-Moment Method: Rotation at B
y’B = θB = tA/B / L = (tC/B + δC) / (L - xC)


Superposition Method - Simply Supported Beam: Concentrated Load at Midspan


Superposition Method - Simply Supported Beam: Concentrated Load, General


Superposition Method - Simple Beam: Uniform Load over Entire Span


Superposition Method - Simple Beam: Uniformly Varying Load over Entire Span with Zero load at one end


Superposition Method - Simple Beam: Symmetrical Triangular Load over Entire Span


Superposition Method - Simple Beam: Moment Load at Right End


Superposition Method - Cantilever Beam: Point Load at Free End


Superposition Method - Cantilever Beam: Point Load, General


Superposition Method - Cantilever Beam: Uniform Load over Entire Span


Superposition Method - Cantilever Beam: Uniformly Varying Load over Entire Span with Zero Load at Free End

Three-Moment Equation: General

Three-Moment Equation: Constant E and I
M1L1 + 2M2 (L1 + L2) + M3L2 + 6A1a1 / L1 + 6A2b2 / L2 = 6EI (h1 / L1 + h3 / L2)

Values of 6Aa/L and 6Ab/L for Point Load, General
6Aa/L = Pa (L2 - a2) / L
6Ab/L = Pb (L2 - b2) / L


Values of 6Aa/L and 6Ab/L for Point Load at Midspan
6Aa/L = 3PL2 / 8
6Ab/L = 3PL2 / 8


Values of 6Aa/L and 6Ab/L for Uniform Load
6Aa/L = w0L3 / 4
6Ab/L = w0L3 / 4


Values of 6Aa/L and 6Ab/L for Triangular Load, 0 at left end
6Aa/L = 8w0L3 / 60
6Ab/L = 7w0L3 / 60


Values of 6Aa/L and 6Ab/L for Symmetric Triangular Load
6Aa/L = 5w0L3 / 32
6Ab/L = 5w0L3 / 32


Values of 6Aa/L and 6Ab/L for Moment
6Aa/L = -M/L × (3a2 - L2)
6Ab/L = M/L × (3a2 - L2)
