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Last updated 1:14 PM on 3/14/26
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184 Terms

1
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Resultant of a Force System: Components

Rx = ΣFcosα

Ry = ΣFsinα

α is angle wrt x-axis

2
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Resultant of a Force System: Magnitude and Direction

R = √(Rx2 + Ry2)

Θ = tan-1(Ry / Rx)

α is angle wrt x-axis

3
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Moment about a Point

M = Fd

4
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Centroid and Effective Forces

Concentrated Load (Point): F = P

Uniformly Distributed Load: F = wL @ L/2

Uniformly Varying Load (Triangular): F = wL/2 @ L/3

5
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Squared Property of Parabola (Parabolic Cable)

d12 / h1 = d22 / h2

d = distance from lowest point to support

h = height of supports from lowest point

6
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Parabolic Cable: Minimum and Maximum Tension

Tmin = (w dmax2 / 2 hmax)

Tmax = √((Tmin)2 + (w dmax)2)

7
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Length of Catenary Cable

S = (T0 / W0) sinh(W0 x / T0)

8
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Catenary Cable: Tension at any Point

T = T0 cosh(W0 x / T0)

9
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Catenary Cable: Vertical Distance of Lowest Point to any Point of the Cable

y = (T0 / W0) [cosh(W0 x / T0) - 1]

10
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Friction Force

Ff = µs N (static friction)

Ff = µk N (dynamic friction)

11
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Angle of Friction

tanΘ = F / N

when Θ = α, tanα = µ = F / N

12
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Belt Friction

T2 / T1 = eµß

T2 > T1

ß = subtended angle in radians

13
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Rectangle: Area, Centroid, Moment of Inertia

A = bh

Centroid = (b/2, h/2)

Ix = bh3 / 12

Iy = hb3 / 12

14
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Triangle: Area, Centroid, Moment of Inertia

A = bh / 2

Centroid = (b/3, h/3)

Ix = bh3 / 36

Iy = hb3 / 36

15
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Circle: Area, Centroid, Moment of Inertia

A = πr2 = πd2 / 4

Centroid = (d/2, d/2)

Ix = πd4 / 64

Iy = πd4 / 64

16
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Quarter Circle / Spandrel

A = πr2 / 4

Centroid = (4r/3π, 4r/3π)

Ix = 0.055r4

Iy = 0.055r4

17
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Rectilinear Motion: Uniform Motion

s = vt

a = 0

18
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Rectilinear Motion: Uniformly Accelerated Motion

a = constant

v = v0 ± at

s = v0 t ± at² / 2

v² = v0² ± 2a (x - x0)

19
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Rectilinear Motion: Instantaneous vs. Average

Instantaneous Velocity: v = dx / dt

Instantaneous Acceleration: a = dv / dt = d2x / dt2

Average Velocity: vave = (x - x0) / (t - t0)

Average Acceleration: aave = (v - v0) / (t - t0)

20
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Rectilinear Motion: Free Fall

v2 = v1 ± gt

v22 = v12 ± 2gy

y = v1t ± gt2 / 2

t = √(2y / g)

ymax = v12 / 2g

(+) - upwards

(-) - downwards

21
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Projectile Motion

v0x = v0 cosΘ

v0y = v0 sinΘ

x = v0x t

t = v0 sinΘ / g + √(2hmax / g)

hmax = ymax + h

ymax = v02sin2Θ / 2g

22
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Projectile Motion: General Formula for height of projectile

y = xtanΘ - gx2 / (2v02cos2Θ)

23
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Rotational Motion

ω = dΘ / dt

α = dω / dt

s = rΘ

v = rω

24
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Rotational Motion: Acceleration Components

aT = αr

aN = ω2r = v2 / r

a = √(aT2 + aN2)

25
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Work

W = F d

26
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Power

P = W / t

27
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Gravitational Potential Energy

PE = m g h

28
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Spring Potential Energy

PE = kx2 / 2

29
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Kinetic Energy

KE = mv2 / 2

30
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Conservation of Mechanical Energy

PE1 + KE1 = PE2 + KE2

For PE = KE: m g h = mv2 / 2

v = √2gh

31
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Linear Momentum and Impulse

p = m × v

Conservation: mv1 = mv2

J = F × t

32
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Coefficient of Resitution

e = - (vB2 - vA2) / (vB1 - vA1)

33
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Particle Kinetics: Centripetal Force

Fcf = mv2 / r

34
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Particle Kinetics: Banked Curves

Friction is Considered: tan (Θ + Φ) = v2 / gR

Car is Slipping: tan (Θ - Φ) = v2 / gR

Design Angle of Banking: tan (Θ) = v2 / gR

35
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Allowable vs. Ultimate

Allowable = Ultimate / Factor of Safety

36
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Axial Stress

σ = P / A

(P = axial load, A = cross-sectional area where axial load is applied)

37
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Axial Strain

ε = δ / L = σ / E

(δ = deflection/change in length, L = original length, E = modulus of elasticity)

38
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Modulus of Elasticity

E = σ / ε

39
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Axial Deformation/Deflection

δ = PL / AE = σL / E

40
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Thermal Deformation

δT = αLΔT

(α = Coefficient of Thermal Expansion)

41
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Shear Stress (General)

τ = V / As

(V = Shear Force, As = sheared area)

42
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Shear Strain

γ = δs / L

43
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Modulus of Rigidity

G = δs / γ

44
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Shear Deformation

δs = VL / AsG

45
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Bearing Stress

σb = Pb / Ab

46
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Cylindrical Thin-Walled Pressure Vessels

Tangential/Hoop: σT = pD / 2t

Longitudinal/Axial: σL = pD / 4t

(p = internal pressure, D = diameter of vessel, t = thickness)

47
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Spherical Thin-Walled Pressure Vessels

σ = pD / 4t

(p = internal pressure, D = diameter of vessel, t = thickness)

48
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Torsional Shear Stress

τ = Tr / J

(T = torque, r = radius of curvature, J = polar moment of inertia)

49
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Torsion: Angle of Twist

θ = TL / JG

(T = torque, L = length, J = polar moment of inertia, G = modulus of rigidity)

50
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Polar Moment of Inertia

J = Ix + Iy

For circular solid shafts: J = πD4 / 32

For circular hollow shafts: J = π(Do4 - Di4)

51
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Helical Springs: Approximate Maximum Shear Stress

Ss = 16PR/πd3 * (1 + d/4R)

(P = load applied, R = spring radius, d = diameter)

52
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Helical Spring: AM Wahl’s Formula

Ss = 16PR/πd3 * ((4m - 1) / (4m+4) + 0.615/m)

m = 2R/d

(4m - 1) / (4m+4) = Wahl factor

53
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Helical Springs: Deformation

δ = 64PR3n / Gd4

(n = number of turns, G = modulus of rigidity, R = spring radius, P = load applied, d = diameter of wire)

54
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Flexure: Bending Stress

fb = My / I

(M = maximum moment, y = distance of point from NA, I = moment of inertia)

55
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Flexural Shear Stress

fv = VQ / Ib

(V = maximum shear force, Q = A’y’, I = moment of inertia, b = width at section)

Note: A’ = area above/below NA, y’ = distance from centroid of A’ to NA

56
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Shear Flow

q = VQ / I = fv b

(V = maximum shear force, Q = A’y’, I = moment of inertia)

57
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Shear Connector

s = RI / VQ = R/q

(s = pitch of shear connector, R = total resistance of connectors within pitch length)

58
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Flexure for Curved Beams

fb = Ey / ρ

(E = modulus of elasticity, y = point from NA, ρ = radius of curvature)

59
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Flexure: Non-homogeneous beams

n = Es / Eb

b → nb

ftransformed = nMc / I

60
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Combined Stresses

σ = ± P/A ± Mc/I

τ = V/A

τ = VQ/Ib + Tr/J

61
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Mohr’s Circle: Sign Convention

Normal Stress: (+) Tension, (-) Compression

Shear Stress: (+) Clockwise, (-) Counterclockwise

62
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Static Determinacy of Beams (Planar)

DI = R - 3 - C

R - external reactions, C - releases

63
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Static Determinacy of Beams (3D)

DI = R - 6 - C

R - external reactions, C - releases

64
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Static Determinacy of Frames (Planar)

DI = R + 3M - 3J - C

R - external reactions, M - members, J - joints, C - releases

65
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Static Determinacy of Frames (3D)

DI = R + 6M - 6J - C

R - external reactions, M - members, J - joints, C - releases

66
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Static Determinacy of Trusses (Planar)

DI = R + M - 3J

R - external reactions, M - members, J - joints

67
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Static Determinacy of Trusses (3D)

DI = R + M - 2J

R - external reactions, M - members, J - joints

68
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Equations of Conditions (C) for Internal Hinge

M = 0; 2 internal reactions (Fx, Fy)

69
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Equations of Conditions (C) for Internal Roller

Fx = 0, M = 0; 1 internal reaction (Fy)

70
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Equations of Conditions (C) for Internal Fixed

3 internal reactions (Fx, Fy, M)

71
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Equations of Conditions (C) for Internal Slider

Fy = 0; 2 internal reactions (Fx, M)

72
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DIM: Moment Equation

EI y” = M

E = modulus of elasticity, I = moment of inertia

73
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DIM: Slope Equation

EI y’ = ∫ M dx + C1

E = modulus of elasticity, I = moment of inertia

74
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DIM: Beam Deflection Equation

EI y’ = ∫ ∫ (M dx) dx + C1x + C2

E = modulus of elasticity, I = moment of inertia

75
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Area-Moment for Cantilever → Moment at Free End

Area = bh (see figure for components)

<p>Area = bh (see figure for components)</p>
76
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Area-Moment for Cantilever → Point Load

Area = bh/2 (see figure for components)

<p>Area = bh/2 (see figure for components)</p>
77
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Area-Moment for Cantilever → Uniformly Distributed Load

Area = bh/3 (see figure for components)

<p>Area = bh/3 (see figure for components)</p>
78
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Area-Moment for Cantilever → Uniformly Varying Load (max at fixed end)

Area = bh/4 (see figure for components)

<p>Area = bh/4 (see figure for components)</p>
79
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Area-Moment Method: Theorem 1

θAB = (Area)AB / EI

80
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Area-Moment Method: Theorem 2

tB/A = (Area)AB / EI * x̄B

81
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<p>Area-Moment Method: Rotation at A</p>

Area-Moment Method: Rotation at A

y’A = θA = tB/A / L = (tC/A + δC) / xC

<p>y’<sub>A</sub> = θ<sub>A</sub> = t<sub>B/A</sub> / L = (t<sub>C/A</sub> + δ<sub>C</sub>) / x<sub>C</sub></p>
82
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<p>Area-Moment Method: Rotation at B</p>

Area-Moment Method: Rotation at B

y’B = θB = tA/B / L = (tC/B + δC) / (L - xC)

<p>y’<sub>B</sub> = θ<sub>B</sub> = t<sub>A/B</sub> / L = (t<sub>C/B</sub> + δ<sub>C</sub>) / (L - x<sub>C</sub>)</p>
83
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<p>Superposition Method - Simply Supported Beam: Concentrated Load at Midspan</p>

Superposition Method - Simply Supported Beam: Concentrated Load at Midspan

<p></p>
84
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<p>Superposition Method - Simply Supported Beam: Concentrated Load, General</p>

Superposition Method - Simply Supported Beam: Concentrated Load, General

<p></p>
85
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<p>Superposition Method - Simple Beam: Uniform Load over Entire Span</p>

Superposition Method - Simple Beam: Uniform Load over Entire Span

<p></p>
86
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<p>Superposition Method - Simple Beam: Uniformly Varying Load over Entire Span with Zero load at one end</p>

Superposition Method - Simple Beam: Uniformly Varying Load over Entire Span with Zero load at one end

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87
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<p>Superposition Method - Simple Beam: Symmetrical Triangular Load over Entire Span</p>

Superposition Method - Simple Beam: Symmetrical Triangular Load over Entire Span

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88
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<p>Superposition Method - Simple Beam: Moment Load at Right End </p>

Superposition Method - Simple Beam: Moment Load at Right End

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89
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<p>Superposition Method - Cantilever Beam: Point Load at Free End </p>

Superposition Method - Cantilever Beam: Point Load at Free End

<p></p>
90
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<p>Superposition Method - Cantilever Beam: Point Load, General</p>

Superposition Method - Cantilever Beam: Point Load, General

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91
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<p>Superposition Method - Cantilever Beam: Uniform Load over Entire Span</p>

Superposition Method - Cantilever Beam: Uniform Load over Entire Span

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92
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<p>Superposition Method - Cantilever Beam: Uniformly Varying Load over Entire Span with Zero Load at Free End</p>

Superposition Method - Cantilever Beam: Uniformly Varying Load over Entire Span with Zero Load at Free End

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93
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Three-Moment Equation: General

<p></p>
94
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Three-Moment Equation: Constant E and I

M1L1 + 2M2 (L1 + L2) + M3L2 + 6A1a1 / L1 + 6A2b2 / L2 = 6EI (h1 / L1 + h3 / L2)

95
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<p>Values of 6Aa/L and 6Ab/L for Point Load, General</p>

Values of 6Aa/L and 6Ab/L for Point Load, General

6Aa/L = Pa (L2 - a2) / L

6Ab/L = Pb (L2 - b2) / L

<p>6Aa/L = Pa (L<sup>2</sup> - a<sup>2</sup>) / L</p><p>6Ab/L = Pb (L<sup>2</sup> - b<sup>2</sup>) / L</p>
96
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<p>Values of 6Aa/L and 6Ab/L for Point Load at Midspan</p>

Values of 6Aa/L and 6Ab/L for Point Load at Midspan

6Aa/L = 3PL2 / 8

6Ab/L = 3PL2 / 8

<p>6Aa/L = 3PL<sup>2</sup> / 8</p><p>6Ab/L = 3PL<sup>2 </sup>/ 8</p>
97
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<p>Values of 6Aa/L and 6Ab/L for Uniform Load</p>

Values of 6Aa/L and 6Ab/L for Uniform Load

6Aa/L = w0L3 / 4

6Ab/L = w0L3 / 4

<p>6Aa/L = w<sub>0</sub>L<sup>3</sup> / 4</p><p>6Ab/L = w<sub>0</sub>L<sup>3</sup> / 4</p>
98
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<p>Values of 6Aa/L and 6Ab/L for Triangular Load, 0 at left end</p>

Values of 6Aa/L and 6Ab/L for Triangular Load, 0 at left end

6Aa/L = 8w0L3 / 60

6Ab/L = 7w0L3 / 60

<p>6Aa/L = 8w<sub>0</sub>L<sup>3</sup> / 60</p><p>6Ab/L = 7w<sub>0</sub>L<sup>3</sup> / 60</p>
99
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<p>Values of 6Aa/L and 6Ab/L for Symmetric Triangular Load</p>

Values of 6Aa/L and 6Ab/L for Symmetric Triangular Load

6Aa/L = 5w0L3 / 32

6Ab/L = 5w0L3 / 32

<p>6Aa/L = 5w<sub>0</sub>L<sup>3</sup> / 32</p><p>6Ab/L = 5w<sub>0</sub>L<sup>3</sup> / 32</p>
100
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<p>Values of 6Aa/L and 6Ab/L for Moment</p>

Values of 6Aa/L and 6Ab/L for Moment

6Aa/L = -M/L × (3a2 - L2)

6Ab/L = M/L × (3a2 - L2)

<p>6Aa/L = -M/L × (3a<sup>2</sup> - L<sup>2</sup>)</p><p>6Ab/L = M/L × (3a<sup>2</sup> - L<sup>2</sup>)</p>

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