cell biology-potato practical

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Last updated 9:38 AM on 4/11/26
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17 Terms

1
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What is diffusion?

Spreading out of particles of a gas or substances in solution causing a...

Net movement from an area of higher concentration to an area of lower conc. (down a conc. gradient)

2
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Give examples of substances transported in / out of cells by diffusion

Oxygen and carbon dioxide in gas exchange

● Urea (a waste product) out of cells into blood plasma for excretion (removal) in the kidney

3
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Describe 3 factors that increase rate of diffusion

1. Increasing concentration gradient (difference in concentrations)

2. Increasing temperature (so increasing kinetic energy)

3. Increasing surface area of membrane

4
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How is surface area to volume ratio (SA:V) calculated?

Divide surface area (size length x side width x number of sides) by volume (length x width x depth)

5
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How are single-celled organisms able to transport enough molecules in and out to meet their needs?

  • Have a (relatively) large surface area to volume ratio (and short diffusion distance)

6
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Explain why multicellular organisms require exchange surfaces and

transport systems?

Surface area to volume ratio is too small

● Diffusion distance too long (some cells too far from surface)

● So diffusion rate per unit volume too slow

7
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Describe how the effectiveness of an exchange surface is increased

1. Increased surface area of cell membrane

2. Thin wall / membrane to provide a short diffusion path

3. (In animals) efficient blood supply

4. (In animals, for gaseous exchange) being ventilated

8
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Explain how the small intestine is adapted for exchanging materials

1. Internal surface covered in many (villi) → ↑

surface area to maximise diffusion

2. Wall of villi are thin / one cell thick → short diffusion distance

3. Good blood supply to villi → moves food molecules away to

maintain a steep conc. gradient

4. Very long → increasing time for absorption

5. Many mitochondria in cells → ↑ respiration to transfer energy

for active transport

9
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Explain how the lungs are adapted for gas exchange

1. Large number of alveoli (tiny air sacs)→ increase surface area to maximise diffusion

2. Walls of alveoli / capillary one cell thick → short diffusion distance

3. Alveoli have a good blood supply → remove O2 quickly to maintain a steep conc. gradient

4. Ventilation → brings in O2 to maintain a steep concentration gradient

10
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Explain how gills in fish are adapted for gas exchange

Many villi → ↑ surface area to maximise diffusion

2. Very thin → short diffusion distance

3. Good blood supply → remove O2 quickly to maintain a steep conc. gradient

11
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Explain how plant roots are adapted for exchanging materials

1. Many root hairs, root hair cells have long projections → ↑ surface area to maximise diffusion

2. Hairs are one cell thick / thin → short diffusion distance

3. Many mitochondria in cells → ↑ respiration to transfer energy for active transport

12
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Explain how plant leaves are adapted for exchanging materials

1. Flattened shape, many stomata (pores) and internal air spaces → ↑ surface area

2. Thin → short diffusion distance

13
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What is osmosis?

Diffusion of water

● From a dilute solution (high water conc.) to a more concentrated solution (low water conc.)

● Through a partially permeable membrane

14
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Required practical 2-Investigate the effect of a range of concentrations of salt or sugar solutions on the mass of plant tissue.

1. Use a scalpel / cork borer to cut up a potato (remove peel) into 6 identical size cylinders

2. Blot dry then measure initial mass of each

3. Place each in a different concentration of sugar solution for 24 hours

4. Blot potato dry with paper towel then measure final mass of each

5. Percentage change in mass = (change in mass / starting mass) x 100

6. Repeat and calculate a mean for each concentration

7. On a graph, plot % change in mass (y axis) against concentration of sugar solution (x axis

15
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What are the independent, dependent and control variables?

  • Independent - concentration of sugar solution

● Dependent - change in mass of plant tissue

● Control - volume of solution, temperature of solution, time in

solution, starting size / length / shape of potato, variety of potato

16
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What is active transport?

Movement of substances from a dilute to a more concentrated solution (against a conc. gradient)

● Requires energy from respiration

17
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Give examples of active transport

  • Absorption of mineral ions from soil into plant root hair cells → for healthy growth

● Absorption of sugar molecules from gut to blood → for cellular respiration to release energy