Inverse Trig
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Last updated 6:08 PM on 5/9/26
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6 Terms
1
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d/dx (arcsinu)=
u’/sqrt(1-u’)
2
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d/dx (arccosu)=
-u’/sqrt(1-u²)
3
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d/dx arctanu=
u’/(1+u²)
4
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d/dx arccotu=
-u’/(1+u²)
5
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d/dx arcsecu=
u’/(|u|sqrt(u²-1)
6
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d/dx arccscu=
-u’/|u|sqrt(u²-1)