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How to show points ae coplanar?
Find plane equation using 3 of the points
Sub fourth point into equation and check if works
r.n = a.n r.n̂ = p r · General point n · normal a · any point in plane
To find an equation of a plane with three points (a,b,c).
Find ab, ac .
dot each with (n̂), equals to 0
let z=1, sim equations to get normal
then use one point dotted with normal to get p
Intersection of line and plane
Sub line into r.n = p
find λ value
sub λ into point
Parametric → Cartesian
take n.b=0 n.c=0 from parametric (r=a+λb+μc)
solve sim equations (z=1 method)
Dot any point with n for p . r.n=p
Intersection of two planes (2 methods)
Method 1
Find two common points on both planes (solve planes silmatenously - let z=0)
find the vector through them, form line equation
Shortest distance between two skew lines
Find gp's on both lines
find vector between them (let t=λ-h) ensure the vector is perpendicular to l₁ ie. dot with one lines direction vector
use value of t from that and put back into AB (vector between two)
pythagoras for distance
Shortest distance between point and line
Find gp on l₁
vector between point and l₁
ensure perp to l₁ (dot product=0)
find λ sub into distance, pythagoras
Reflecting a point in a plane
Intersection of line and plane (i.e Sub line into r.n=p , find λ value)
Double λ value , sub into line
Reflecting a line in a plane
Find intersection point (of plane and og line) -ie sub line in plane
Reflect a point in the plane (direction of line is the normal btw) on l₁ to l₂
Find equation of line with the 2 points