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Rolle’s theorem
If f(a)=f(b) then there must be at least one number c in (a,b) such that f’(c)=0
Continuous interval
Closed []
Diff interval
Open interval ()
Steps for Rolle’s theorem
State if function is continuous over closed interval
State is function is differentiable over open interval
Show if f(a)=(fb)
State that the theorem applies
Take the derivative of ur function, set to zero, and solve for x
Make sure ur x is between (a,b)
The x value(s) you get are now guaranteed by the theorem
Mean value theorem steps
Determine if f(x) is continuous over closed interval
Determine if f(x) is differentiable over open interval
Differentiate f(x)
Find slope of intervals given (y2-y1/x2-x1)
Set f’(x) equal to the slope of the intervals you found and solve for x
Make sure your x(s) lie within the interval given
Mean value theorem
If f is continuous over the closed interval [a,b] and differentiable over the open interval (a,b), then there exists a number c in (a,b) such that f’(c) =( f(b)-f(a) ) / (b-a)
Basically it’s saying derivative = slope
Extreme value theorem
If f(x) is continuous over a closed interval, then f(x) has both a absolute maximum and a minimum on the interval
When is there Critical numbers
If f(x) is defined at c, and f’(c)=0 or f(x) is not differentiable at c (aka f’(c)=DNE)
Relative extrema
Occur at horizontal tangent lines and only occur at critical numbers
Relative minimum f(x)
f’(x) changes from - to +
Relative maximum of f(x)
f’x) changes from + to -
differentiable
continuous
continuous
not always differentiable
Continuity breaks when there is
Hole (removable discontinuity)
Jump discontinuity
Vertical asymptote
Any break in the graph
A function is not differentiable when
The function is not continuous
Corner or cusp
Vertical tangent line
Discontinuity (hole, jump, asymptote)
Fast Oscillation / wiggle / “infinite bouncing”
NOT continuous
NOT differentiable