Hexose Monophosphate Shunt

0.0(0)
Studied by 0 people
call kaiCall Kai
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/21

encourage image

There's no tags or description

Looks like no tags are added yet.

Last updated 12:09 PM on 3/7/26
Name
Mastery
Learn
Test
Matching
Spaced
Call with Kai

No analytics yet

Send a link to your students to track their progress

22 Terms

1
New cards

introduction to hexose manophosphate

the hexose monophosphate shunt is a metabolic pathway parallel to glycolysis that serves two main functions:

  1. production of NADPH: essential for reductive photosynthesis and maintaining redox balance.

  2. synthesis of ribose-5-phosphate: precursor for nucleotide and nucleic acid synthesis

the hexose monophosphate pathway occurs in the cytoplasm of the cells and is especially active in tissues that require high levels of NADPH, such as:

-liver

-adipose tissue

-adrenal glands

-red blood cells

*the HMP pathway is active in tissues that require high levels of NADPH because the HMP pathway produces NADPH.

<p>the <strong>hexose monophosphate shunt</strong> is a <strong>metabolic pathway</strong> <strong>parallel</strong> to <strong>glycolysis</strong> that <strong>serves two main functions:</strong></p><ol><li><p><strong>production of NADPH</strong>: essential for reductive photosynthesis and maintaining redox balance.</p></li><li><p><strong>synthesis of ribose-5-phosphate</strong>: precursor for nucleotide and nucleic acid synthesis</p></li></ol><p>the <strong>hexose monophosphate pathway</strong> <strong>occurs</strong> in the <strong>cytoplasm</strong> of the <strong>cells</strong> and is <strong>especially active in tissues</strong> that <strong>require high levels of NADPH</strong>, such as:</p><p>-liver</p><p>-adipose tissue</p><p>-adrenal glands</p><p>-red blood cells</p><p>*the HMP pathway is active in tissues that require high levels of NADPH because the HMP pathway produces NADPH. </p>
2
New cards

phases of hexose monophosphate shunt pathway

-the hexose monophosphate can be divided into two major phases:

  1. -oxidative phases (irreversible): the NADPH is produced by oxidizing glucose-6-phosphate (the oxidative phase is irreversible due to the large negative ΔG (Highly Exergonic)

The oxidative step:

  • Transfers a hydride (H⁻) → Reduces NADP⁺ → NADPH, Oxidizes an alcohol group to a lactone

Oxidation + reduction of NADP⁺ releases significant free energy.

That makes: ΔG≪0

Large negative free energy change = reaction strongly favors products = irreversible under physiological conditions

  1. -non-oxidative phases (reversible): this phase involves the rearrangement of ribulose-5-phosphate into various sugar needed for biosynthesis.

<p>-the <strong>hexose monophosphate</strong> can be <strong>divided</strong> into <strong>two major phases</strong>:</p><ol><li><p>-<strong>oxidative phases (irreversible)</strong>: the <strong>NADPH is produced</strong> by <strong>oxidizing glucose-6-phosphate</strong> (<span style="color: rgb(9, 4, 4);"><span>the oxidative phase is irreversible due to the</span></span><span style="color: rgb(192, 41, 41);"><span> </span></span>large negative ΔG (Highly Exergonic)</p></li></ol><p>The oxidative step:</p><ul><li><p>Transfers a hydride (H⁻) → Reduces NADP⁺ → NADPH, Oxidizes an alcohol group to a lactone</p></li></ul><p>Oxidation + reduction of NADP⁺ releases significant free energy.</p><p>That makes: <span>ΔG≪0</span></p><p><strong>Large negative free energy change = reaction strongly favors products =</strong> <strong>irreversible under physiological conditions</strong></p><ol start="2"><li><p>-<strong>non-oxidative phases (reversible)</strong>: this phase involves the <strong>rearrangement</strong> of <strong>ribulose-5-phosphate</strong> into <strong>various sugar</strong> needed for <strong>biosynthesis</strong>.</p></li></ol><p></p>
3
New cards

Phases of hexose monophosphate shunt (in biochemistry notebook with “HMS” on the page)

as mentioned previously, the hexose monophosphate shunt is a pathway that will occur parallel to glycolysis.

here is an overview of both pathways for your reference.

<p>as mentioned previously, the <strong>hexose monophosphate shunt</strong> is a <strong>pathway</strong> that will occur <strong>parallel </strong>to <strong>glycolysis</strong>.</p><p>here is an overview of both pathways for your reference.</p>
4
New cards

step by step of the oxidative phase (in biochemistry notebook with “HMS” on the page)

oxidative phase of HMP: breaks down glucose-6-phosphate (oxidizes glucose-6-phosphate) → NADPH + H.

the first step of the hexose monophosphate shunt is catalyzed by the enzyme Glucose-6-phosphate dehydrogenase (G6PD)

At C1: There is an aldehyde in the open-chain form,

1. G6PD removes a hydride (H⁻),

2. NADP⁺ accepts that hydride → becomes NADPH, there is another proton (hydride is H-, proton is H+), the other proton is released into the aqueous environment.

So chemically: Alcohol/aldehyde → more oxidized carbonyl derivative

This forms: 6-phosphoglucono-δ-lactone (a cyclic ester)

That immediately cyclizes into a lactone glucose-6-phosphate at carbon 1 forming a lactone

-the reaction reduces NADP→ NADPH, generating the first molecule of NADPH in the pathway.

-Mg2+ is a cofactor that is used to stabilize the negatively charged phosphate group on glucose-6-phosphate. the phosphate has a negative charge that repels nearby negative residues, makes precise positioning harder, need stabilization inside the enzyme active site. Mg2+ is there to neutralize the charge and reduce electrostatic repulsion.

-this is the RATE LIMITING STEP of the pathway and is highly regulated:

Why Is This the Rate-Limiting Step (The slowest step in a metabolic pathway that determines the overall speed (flux) of the pathway.)?

  1. It is the first committed step (The first irreversible reaction that sends a metabolite down one pathway and prevents it from easily returning to competing pathways.)

  2. It controls NADPH production

  3. It has the largest negative ΔG in the pathway

  4. It is tightly regulated by NADP⁺/NADPH ratio

Regulation of G6PD (Very High Yield) Primary Regulator: NADP⁺ Availability

High NADP⁺

→ Activates G6PD

High NADPH

→ Inhibits G6PD

This makes perfect physiological sense:

  • If the cell needs reducing power → NADPH gets used

  • NADP⁺ rises

  • Pathway turns ON

This is elegant redox control.

what is NADPH used for?

NADH → ATP production (energy extraction)

NADPH → biosynthesis + protection (reduction reactions)

1⃣ Fatty Acid Synthesis (Very High Yield): In liver, adipose, lactating mammary gland: NADPH provides electrons to reduce carbon chains during fatty acid elongation, convert acetyl-CoA into palmitate.

Without NADPH: You cannot convert acetyl-CoA into palmitate.

This is one of the biggest consumers of NADPH.


Why This Step Is Irreversible

1. Strongly Exergonic (Large Negative ΔG)

Redox reactions involving NADP⁺ release substantial free energy.

2. NADPH Is Rapidly Consumed in:

  • Fatty acid synthesis

  • Cholesterol synthesis

  • Glutathione reduction (RBC survival)

  • Cytochrome P450 detox

Product removal pulls reaction forward.

3. It Commits G6P Away From Glycolysis

Once oxidized at C1, glucose cannot easily return to glycolysis as G6P.

<p><strong>oxidative phase of HMP</strong>: breaks down glucose-6-phosphate (oxidizes glucose-6-phosphate) → NADPH + H.</p><p>the <strong>first step</strong> of the <strong>hexose monophosphate shunt</strong> is <strong>catalyzed</strong> by the<strong> enzyme Glucose-6-phosphate <u>de</u>hydrogenase (G6P<u>D</u>)</strong></p><p><strong>At C1</strong>: There is an <strong>aldehyde</strong> in the <strong>open-chain form</strong>, </p><p>1. <strong>G6PD removes a hydride (H⁻)</strong>, </p><p>2. <strong>NADP⁺ accepts that hydride</strong> → becomes <strong>NADPH, </strong>there is another proton (hydride is H-, proton is H+), the other proton is released into the aqueous environment.</p><p>So chemically: <strong>Alcohol/aldehyde → more oxidized carbonyl derivative</strong></p><p>This forms: <span style="color: blue;"><span>6-phosphoglucono-δ-lactone</span></span> (a cyclic ester)</p><p>That immediately cyclizes into a <strong>lactone glucose-6-phosphate</strong> at <strong>carbon 1</strong> forming a <span style="color: rgb(0, 0, 0);"><strong><span>lactone</span></strong></span></p><p>-the reaction reduces NADP→ NADPH, generating the first molecule of NADPH in the pathway.</p><p>-<strong>Mg2+</strong> is a <strong>cofactor</strong> that is used to <strong>stabilize the negatively charged phosphate group</strong> on <strong>glucose-6-phosphat</strong>e. the <strong>phosphate</strong> has a <strong>negative</strong> <strong>charge</strong> that <strong>repels nearby negative residues</strong>, makes precise positioning harder, need stabilization inside the enzyme active site. <strong>Mg2+</strong> is there to <strong>neutralize the charge and reduce electrostatic repulsion.</strong></p><p><span style="color: rgb(3, 1, 1);"><span>-this is the </span><strong><span>RATE LIMITING STEP</span></strong><span> </span><strong><span>of the pathway</span></strong><span> and is </span><strong><span>highly regulated:</span></strong></span></p><p>Why Is This the Rate-Limiting Step (The slowest step in a metabolic pathway that determines the overall speed (flux) of the pathway.)?</p><ol><li><p>It is the <strong>first committed step </strong>(The first irreversible reaction that sends a metabolite down one pathway and prevents it from easily returning to competing pathways.)</p></li><li><p>It controls NADPH production</p></li><li><p>It has the largest negative ΔG in the pathway</p></li><li><p>It is tightly regulated by NADP⁺/NADPH ratio</p></li></ol><p></p><p>Regulation of G6PD (Very High Yield) Primary Regulator: NADP⁺ Availability</p><table style="min-width: 50px;"><colgroup><col style="min-width: 25px;"><col style="min-width: 25px;"></colgroup><tbody><tr><th colspan="1" rowspan="1"><p>High NADP⁺</p></th><th colspan="1" rowspan="1"><p>→ Activates G6PD</p></th></tr><tr><td colspan="1" rowspan="1"><p>High NADPH</p></td><td colspan="1" rowspan="1"><p>→ Inhibits G6PD</p></td></tr></tbody></table><p>This makes perfect physiological sense:</p><ul><li><p>If the cell needs reducing power → NADPH gets used</p></li><li><p>NADP⁺ rises</p></li><li><p>Pathway turns ON</p></li></ul><p>This is elegant redox control.</p><p>what is NAD<strong>PH</strong> used for?</p><p>NADH → ATP production (energy extraction)</p><p>NADPH → <strong>biosynthesis</strong> + protection (reduction reactions)</p><p><span>1⃣</span> <strong>Fatty Acid Synthesis </strong>(Very High Yield): In liver, adipose, lactating mammary gland: NAD<strong>PH</strong> <strong>provides electrons</strong> to <strong>reduce carbon chains during fatty acid elongation, c</strong>onvert acetyl-CoA into palmitate.</p><p>Without NADPH: You cannot convert acetyl-CoA into palmitate.</p><p>This is one of the <strong>biggest consumers</strong> of NADPH.</p><div data-type="horizontalRule"><hr></div><p>Why This Step Is Irreversible</p><p>1. Strongly Exergonic (Large Negative ΔG)</p><p>Redox reactions involving NADP⁺ release substantial free energy.</p><p>2. NADPH Is Rapidly Consumed in:</p><ul><li><p>Fatty acid synthesis</p></li><li><p>Cholesterol synthesis</p></li><li><p>Glutathione reduction (RBC survival)</p></li><li><p>Cytochrome P450 detox</p></li></ul><p>Product removal pulls reaction forward.</p><p>3. It Commits G6P Away From Glycolysis</p><p>Once oxidized at C1, glucose cannot easily return to glycolysis as G6P.</p>
5
New cards
<p><strong>Lactone</strong> comes from:</p><ul><li><p><strong>Latin:</strong> <em>lac, lactis</em> = “milk”</p></li><li><p><strong>-one</strong> = suffix in organic chemistry indicating a ketone or carbonyl-containing compound</p></li></ul><p>“milk ketone”</p><p>Why “Milk”? In the 1800s, chemists first discovered these compounds while studying <strong>lactic acid</strong> (from sour milk).</p><p>They noticed that certain hydroxy acids could: Internally react, Form a cyclic ester, Lose water in the process</p><p>Because this was discovered in lactic acid chemistry, the cyclic product was named a <strong>lactone</strong>.</p>

Lactone comes from:

  • Latin: lac, lactis = “milk”

  • -one = suffix in organic chemistry indicating a ketone or carbonyl-containing compound

“milk ketone”

Why “Milk”? In the 1800s, chemists first discovered these compounds while studying lactic acid (from sour milk).

They noticed that certain hydroxy acids could: Internally react, Form a cyclic ester, Lose water in the process

Because this was discovered in lactic acid chemistry, the cyclic product was named a lactone.

6
New cards

step by step of the oxidative phase (step 2) (in biochemistry notebook with “HMS” on the page)

in step 2,

  1. 6-phosphoglucono-delta-lactone binds to the active site of lactonase. (there is a double bond to the non-lactone oxygen, but it’s not shown in the picture)

  2. a water molecule is positioned near the lactone ring, making the oxygen in water perform a nucleophilic attack to the lactone ring carbonyl groups.

-The carbonyl carbon is electrophilic because the C=O bond is polarized.

  1. lactonase then releases 6-phosphogluconate (, which is now an open chain form and ready for the next step.

-the Mg2+ is also used here to stabilize the phosphate group.

-lactonase: uses the nucleophilic oxygen in water to destroy the bond between the oxygen in the lactone ring and C5.

Gluconic acid (deprotonated) = Gluconate (“ate”: deprotonated due to physiological pH 7.4, so there is a negative charge on the oxygen, -COO-)

<p>in step 2,</p><ol><li><p><strong>6-phosphoglucono-delta-lactone binds</strong> to the <strong>active site </strong>of <strong>lactonase. </strong>(there is a double bond to the non-lactone oxygen, but it’s not shown in the picture)</p></li><li><p>a <strong>water molecule</strong> is <strong>positioned near the lactone ring</strong>, making the <strong>oxygen</strong> in <strong>water</strong> perform a <strong>nucleophilic attack</strong> to the <strong>lactone ring carbonyl groups.</strong></p></li></ol><p>-The carbonyl carbon is <strong>electrophilic</strong> because the C=O bond is polarized.</p><ol start="3"><li><p>lactonase then releases <strong>6-phosphogluconate (</strong>, which is now an <strong>open chain form</strong> and ready for the next step.</p></li></ol><p>-the Mg2+ is also used here to stabilize the phosphate group. </p><p>-lactonase: uses the nucleophilic oxygen in water to destroy the bond between the oxygen in the lactone ring and C5.</p><p>Gluconic acid (deprotonated) = Gluconate (“ate”: deprotonated due to physiological pH 7.4, so there is a negative charge on the oxygen, -COO-)</p>
7
New cards

step by step of the oxidative phase (Final step of oxidative phase) (in biochemistry notebook with “HMS” on the page)

in the third step and final step,

  1. 6-phosphogluconate, binds to enzyme six-phosphogluconate dehydrogonase

  2. once this binding happens, NADP extracts a hydride from C3, oxidizing 6-phosphogluconate at carbon 3 forming NADPH.

• A hydride (H⁻) is transferred from C3 to NADP⁺, That hydride contains 2 electrons + 1 proton = NADP⁺ → NADPH

So only one hydride is transferred.

what happens at C3?

• The hydrogen on C3 leaves as a hydride (H⁻)
• That hydride goes to NADP⁺ → NADPH
• The OH is converted into a carbonyl.

C2?

No hydrogen from C3 OH migrates to C2, instead, Because after decarboxylation, there is:

• An enol intermediate
• Protonation from solvent
• Tautomerization

That proton comes from water, not from C3.

So yes — C3 loses one hydride (2e⁻ + H⁺ equivalent).

It does not lose two separate hydrogens.

Only one hydride is transferred.

An extra proton appears in solution with NADPH to get NADPH + H.

Oxidation of 6-phosphogluconate at C3

Formation of ribulose-5-phosphate after CO₂ leaves

An additional H⁺ appears in solution.

  1. this will form an unstable intermediate that will release CO2 (the CO2 that had the negative charge on top of 6-phosphogluconate) and form ribulose-5-phosphate. (because the carbon was lost)

-this D-ribulose-5-phosphate will now be used for the non-oxidative phase of this pathway.

<p>in the third step and final step,</p><ol><li><p><strong>6-phosphogluconate</strong>, binds to enzyme <strong>six-phosphogluconate dehydrogonase</strong></p></li><li><p>once this binding happens, <strong>NADP</strong> <strong>extracts a hydride </strong>from<strong> C3,</strong> oxidizing 6-phosphogluconate at <strong>carbon 3</strong> forming <strong>NADPH</strong>.</p></li></ol><p>• A <strong>hydride (H⁻)</strong> is <strong>transferred</strong> from <strong>C3</strong> to <strong>NADP⁺, </strong>That hydride contains 2 electrons + 1 proton = NADP⁺ → NADPH</p><p>So only one hydride is transferred.</p><p><u>what happens at C3?</u></p><p>• The hydrogen on C3 leaves as a <strong>hydride (H⁻)</strong><br>• That hydride goes to <strong>NADP⁺ → NADPH</strong><br>• The OH is converted into a carbonyl. </p><p><u>C2?</u></p><p>No hydrogen from C3 OH migrates to C2, instead, Because after decarboxylation, there is:</p><p>• An enol intermediate<br>• Protonation from solvent<br>• Tautomerization</p><p>That proton comes from <strong>water</strong>, not from C3.</p><p></p><p>So yes — C3 loses <strong>one hydride (2e⁻ + H⁺ equivalent)</strong>.</p><p>It does <strong>not</strong> lose two separate hydrogens.</p><p>Only one hydride is transferred.</p><p>An extra proton appears in solution with NADPH to get NADPH + H. </p><p>Oxidation of <strong>6-phosphogluconate at C3</strong></p><p>Formation of <strong>ribulose-5-phosphate after CO₂ leaves</strong></p><p>An additional H⁺ appears in solution.</p><ol><li><p>this will form an unstable intermediate that will <strong>release CO2</strong> (the CO2 that had the negative charge on top of <strong>6-phosphogluconate)</strong> and form ribulose-5-phosphate. (because the carbon was lost)</p></li></ol><p>-this <em>D-ribulose-5-phosphate</em> will now be used for the non-oxidative phase of this pathway.</p>
8
New cards

(in biochemistry notebook with “HMS” on the page)

the produced ribulose-5-phosphate will undergo either an isomerization OR epimerization process, which will produce different products.

-the most important difference between these products is that both reactions rely on acid-base catalysis to form each product, but isomerization changes a ketone → aldehyde, while epimerization alters stoichiometry at C3.

-iso “equal” mer “part”: isomer: “equal parts”, Isomers are: molecules that have the same molecular formula but different arrangements of atoms.

epi: “upon”, mer: “part”, epimer: “different at one part”, Epimers are: stereoisomers that differ in configuration at only ONE chiral carbon.

epimers are stereoisomers.

<p>the produced <strong>ribulose-5-phosphate</strong> will undergo either an <strong>isomerization</strong> OR <strong>epimerization</strong> process, which will <strong>produce different products</strong>.</p><p>-the most important difference between these products is that both reactions rely on acid-base catalysis to form each product, but isomerization changes a ketone → aldehyde, while epimerization alters stoichiometry at C3.</p><p>-iso “equal” mer “part”: isomer: “equal parts”, Isomers are: molecules that have the same molecular formula but different arrangements of atoms.</p><p>epi: “upon”, mer: “part”, epimer: “different at one part”, Epimers are: stereoisomers that differ in configuration at only ONE chiral carbon. </p><p>epimers are stereoisomers. </p>
9
New cards

Functions of the hexose monophosphate pathway

the hexose monophosphate pathway has several key functions in cellular metabolism. Due its metabolic flexibility, it helps the cell produce energy, nucleotides, antioxidants, and lipids depending on its needs.

In this table, we can see a detailed summary of all the key functions of this pathway and where it is going to be important in the body.

<p>the <strong>hexose monophosphate pathway</strong> has <strong>several key functions</strong> in <strong>cellular metabolism</strong>. Due its <strong>metabolic flexibility</strong>, it <strong>helps the cell produce energy</strong>, <strong>nucleotides</strong>, <strong>antioxidants</strong>, and <strong>lipids</strong> depending on its needs.</p><p>In this table, we can see a <em>detailed summary</em> of all the key functions of this pathway and where it is going to be important in the body.</p>
10
New cards
<p>Functions of the hexose monophosphate pathway: NADH Production</p>

Functions of the hexose monophosphate pathway: NADH Production

1. NADPH Production What the pathway produces

The oxidative phase of the PPP generates NADPH.

Reaction example:

Glucose-6-phosphate+NADP+→NADPH

NADPH is used for:

Redox balance – maintaining proper electron balance
Biosynthesis – building molecules like fatty acids
Detoxification – cytochrome P450 reactions in the liver

NADPH is essentially a source of reducing power (electrons).

Where this matters most

Liver

  • detoxification

  • lipid synthesis

Red blood cells

  • antioxidant defense

Adipose tissue

  • fatty acid synthesis

<p>1. NADPH Production What the pathway produces </p><p>The <strong>oxidative phase of the PPP</strong> generates <strong>NADPH</strong>.</p><p>Reaction example:</p><p> <span>Glucose-6-phosphate+NADP+→NADPH</span></p><p>NADPH is used for:</p><p>• <strong>Redox balance</strong> – maintaining proper electron balance<br>• <strong>Biosynthesis</strong> – building molecules like fatty acids<br>• <strong>Detoxification</strong> – cytochrome P450 reactions in the liver</p><p>NADPH is essentially a <strong>source of reducing power (electrons)</strong>.</p><p> Where this matters most </p><p><strong>Liver</strong></p><ul><li><p>detoxification</p></li><li><p>lipid synthesis</p></li></ul><p><strong>Red blood cells</strong></p><ul><li><p>antioxidant defense</p></li></ul><p><strong>Adipose tissue</strong></p><ul><li><p>fatty acid synthesis</p></li></ul><p></p>
11
New cards
<p>Functions of the hexose monophosphate pathway: Ribose-5-phosphate Synthesis </p>

Functions of the hexose monophosphate pathway: Ribose-5-phosphate Synthesis

2. Ribose-5-Phosphate Synthesis What the pathway produces

The PPP generates:

Ribose-5-phosphate\textbf{Ribose-5-phosphate}Ribose-5-phosphate

This is a 5-carbon sugar used to build nucleotides.

Key role

Ribose-5-phosphate is needed for:

DNA synthesis
RNA synthesis
ATP production
NAD⁺ / FAD synthesis

It becomes PRPP (phosphoribosyl pyrophosphate), which starts nucleotide synthesis.

Where this is important

Cells that divide rapidly:

  • Bone marrow

  • Skin

  • Tumor cells

These tissues need large amounts of DNA and RNA.

<p>2. Ribose-5-Phosphate Synthesis What the pathway produces </p><p>The PPP generates:</p><p> <span>Ribose-5-phosphate\textbf{Ribose-5-phosphate}Ribose-5-phosphate</span> </p><p>This is a <strong>5-carbon sugar</strong> used to build nucleotides.</p><p> Key role </p><p>Ribose-5-phosphate is needed for:</p><p>• <strong>DNA synthesis</strong><br>• <strong>RNA synthesis</strong><br>• <strong>ATP production</strong><br>• <strong>NAD⁺ / FAD synthesis</strong></p><p>It becomes <strong>PRPP (phosphoribosyl pyrophosphate)</strong>, which starts nucleotide synthesis.</p><p>Where this is important </p><p>Cells that divide rapidly:</p><ul><li><p><strong>Bone marrow</strong></p></li><li><p><strong>Skin</strong></p></li><li><p><strong>Tumor cells</strong></p></li></ul><p>These tissues need large amounts of <strong>DNA and RNA</strong>.</p>
12
New cards
<p>Functions of the hexose monophosphate pathway: Sugar-rearrangement </p>

Functions of the hexose monophosphate pathway: Sugar-rearrangement

3. Sugar Rearrangement What happens

The non-oxidative phase rearranges sugars.

Pentose sugars (5 carbons) are converted into glycolysis intermediates.

Example:

3 pentoses (5C)→2 fructose-6-P+1 glyceraldehyde-3-P3

Enzymes responsible:

Transketolase (2-carbon transfer)
Transaldolase (3-carbon transfer)

Key role

This allows the cell to:

• recycle pentose sugars
• reconnect the PPP with glycolysis

Where this is important

All cells

Because every cell uses glycolysis.

<p>3. Sugar Rearrangement What happens</p><p>The <strong>non-oxidative phase</strong> rearranges sugars.</p><p>Pentose sugars (5 carbons) are converted into <strong>glycolysis intermediates</strong>.</p><p>Example:</p><p><span>3&nbsp;pentoses&nbsp;(5C)→2&nbsp;fructose-6-P+1&nbsp;glyceraldehyde-3-P3 </span></p><p>Enzymes responsible:</p><p>• <strong>Transketolase</strong> (2-carbon transfer)<br>• <strong>Transaldolase</strong> (3-carbon transfer)</p><p>Key role</p><p>This allows the cell to:</p><p>• recycle pentose sugars<br>• reconnect the PPP with <strong>glycolysis</strong></p><p>Where this is important</p><p><strong>All cells</strong></p><p>Because every cell uses glycolysis.</p>
13
New cards
<p>Functions of the hexose monophosphate pathway: Xylolose-5-phosphate </p>

Functions of the hexose monophosphate pathway: Xylolose-5-phosphate

4. Xylulose-5-Phosphate What it is

Xylulose-5-phosphate is an intermediate produced in the non-oxidative PPP.

Key role

It acts as a metabolic signal molecule.

In the liver it activates:

ChREBP (carbohydrate response element binding protein)

This transcription factor increases expression of genes involved in:

• glycolysis
• fatty acid synthesis

So it helps the body convert excess glucose into fat.

Where this matters

Liver
Adipose tissue

<p>4. Xylulose-5-Phosphate What it is</p><p>Xylulose-5-phosphate is an intermediate produced in the <strong>non-oxidative PPP</strong>.</p><p>Key role</p><p>It acts as a <strong>metabolic signal molecule</strong>.</p><p>In the liver it activates:</p><p><strong>ChREBP (carbohydrate response element binding protein)</strong></p><p>This transcription factor increases expression of genes involved in:</p><p>• glycolysis<br>• fatty acid synthesis</p><p>So it helps the body <strong>convert excess glucose into fat</strong>.</p><p>Where this matters</p><p>• <strong>Liver</strong><br>• <strong>Adipose tissue</strong></p>
14
New cards
<p>Functions of the hexose monophosphate pathway: Oxidative Stress Defense</p>

Functions of the hexose monophosphate pathway: Oxidative Stress Defense

5. Oxidative Stress Defense Key role

The PPP protects cells from reactive oxygen species (ROS).

NADPH produced by the pathway keeps glutathione reduced.

Reaction:

GSSG+NADPH→2GSH

Reduced glutathione (GSH) neutralizes:

  • hydrogen peroxide

  • free radicals

  • oxidants

Where this is critical

Red blood cells (RBCs)

RBCs cannot make NADPH any other way because they lack mitochondria.

If PPP fails → oxidative damage → hemolysis.

Example:

G6PD deficiency

<p>5. Oxidative Stress Defense Key role</p><p>The PPP protects cells from <strong>reactive oxygen species (ROS)</strong>.</p><p><strong>NADPH produced</strong> by the pathway keeps <strong>glutathione reduced</strong>.</p><p>Reaction:</p><p><span>GSSG+NADPH→2GSH</span></p><p>Reduced glutathione (<strong>GSH</strong>) neutralizes:</p><ul><li><p>hydrogen peroxide</p></li><li><p>free radicals</p></li><li><p>oxidants</p></li></ul><p>Where this is critical</p><p><strong>Red blood cells (RBCs)</strong></p><p>RBCs cannot make NADPH any other way because they lack mitochondria.</p><p>If PPP fails → <strong>oxidative damage → hemolysis</strong>.</p><p>Example:</p><p><strong>G6PD deficiency</strong></p>
15
New cards
<p>Functions of the hexose monophosphate pathway: Fatty Acid &amp; Steroid Synthesis Key Role </p>

Functions of the hexose monophosphate pathway: Fatty Acid & Steroid Synthesis Key Role

6. Fatty Acid & Steroid Synthesis Key role

NADPH is required for reductive biosynthesis.

Examples:

Fatty acid synthesis
Cholesterol synthesis
Steroid hormone synthesis

Each step requires reducing equivalents from NADPH.

Where this is important

Liver
Adipose tissue
Adrenal glands

Adrenal glands use NADPH to synthesize:

  • cortisol

  • aldosterone

  • sex steroids

<p>6. Fatty Acid &amp; Steroid Synthesis Key role </p><p>NADPH is required for <strong>reductive biosynthesis</strong>.</p><p>Examples:</p><p>• <strong>Fatty acid synthesis</strong><br>• <strong>Cholesterol synthesis</strong><br>• <strong>Steroid hormone synthesis</strong></p><p>Each step requires <strong>reducing equivalents from NADPH</strong>.</p><p> Where this is important </p><p>• <strong>Liver</strong><br>• <strong>Adipose tissue</strong><br>• <strong>Adrenal glands</strong></p><p>Adrenal glands use NADPH to synthesize:</p><ul><li><p>cortisol</p></li><li><p>aldosterone</p></li><li><p>sex steroids</p></li></ul><p></p>
16
New cards

the hexose monophosphate pathway is tightly regulated to balance NADPH production, nucleotide synthesis, and sugar metabolism on the cellular needs.

The key regulatory mechanisms include

  1. allosteric control: (This means molecules bind to an enzyme and change its activity, the main allosteric regulator is: NADPH, If NADPH binds to G6PD → enzyme slows.)

  2. substrate availability (This means the reaction rate depends on how much substrate or cofactor is present, Here the important molecule is: NADP⁺, G6PD requires NADP⁺ to accept electrons. If NADP⁺ levels rise → the enzyme becomes more active.

  1. hormonal regulation: Hormones change enzyme expression, Insulin

    Insulin increases production of G6PD enzyme in certain tissues.

during the oxidative phase, we will see different ways that glucose-6-phosphate will be regulated, mainly, due to HIGH or LOW LEVELS of NADPH, but we will also see insulin and gluthathione, which can regulate the action of this enzyme.

3. High NADPH → Inhibits G6PD

Effect: High NADPH inhibits the enzyme.

Why: This is negative feedback inhibition.

If NADPH is already abundant, the cell does not need more.

4. Low NADPH / High NADP⁺ → Activates G6PD

Effect

Low NADPH or high NADP⁺ activates the enzyme.

5. Insulin → Activates G6PD

Effect

Insulin increases the expression of the G6PD enzyme.

Why

Insulin signals the fed state.

In the fed state:

glucose levels are high

excess glucose is converted to fat

Fatty acid synthesis requires large amounts of NADPH.

So insulin stimulates the PPP to provide that NADPH.

6. Glutathione Demand (Oxidative Stress) → Activates G6PD

Effect

When cells experience oxidative stress, G6PD activity increases.

Why: Cells use glutathione (GSH) to neutralize reactive oxygen species.

Reaction: 2GSH+H2O2→GSSG+2H2O

But once glutathione becomes oxidized (GSSG), it must be regenerated:

GSSG+NADPH→2GSH

So oxidative stress increases NADPH consumption.

That raises NADP⁺ levels, which activates G6PD.

<p>the <strong>hexose monophosphate pathway</strong> is <strong>tightly regulated</strong> to <strong>balance NADPH production, nucleotide synthesis</strong>, and <strong>sugar metabolism</strong> on the <strong>cellular needs</strong>.</p><p>The <strong>key regulatory mechanisms</strong> include</p><ol><li><p>allosteric control: (This means <strong>molecules bind to an enzyme and change its activity</strong>, the main allosteric regulator is: NADPH, If NADPH binds to G6PD → enzyme slows.)</p></li><li><p>substrate availability (This means the reaction rate depends on how much substrate or cofactor is present, Here the important molecule is: NADP⁺, G6PD requires NADP⁺ to accept electrons. If NADP⁺ levels rise → the enzyme becomes more active.</p></li></ol><ol><li><p>hormonal regulation: Hormones change enzyme expression, <strong>Insulin</strong></p><p><strong>Insulin increases production of G6PD</strong> <strong>enzyme</strong> in certain tissues.</p></li></ol><p>during the oxidative phase, we will see different ways that glucose-6-phosphate will be regulated, mainly, due to HIGH or LOW LEVELS of NADPH, but we will also see insulin and gluthathione, which can regulate the action of this enzyme.</p><p>3. High NADPH → Inhibits G6PD</p><p>Effect: High NADPH inhibits the enzyme.</p><p>Why: This is negative feedback inhibition.</p><p>If NADPH is already abundant, the cell does not need more.</p><p></p><p>4. Low NADPH / High NADP⁺ → Activates G6PD</p><p>Effect</p><p>Low NADPH or high NADP⁺ activates the enzyme.</p><p></p><p>5. Insulin → Activates G6PD</p><p>Effect</p><p>Insulin increases the expression of the G6PD enzyme.</p><p>Why</p><p>Insulin signals the fed state.</p><p>In the fed state:</p><p>glucose levels are high</p><p>excess glucose is converted to fat</p><p>Fatty acid synthesis requires large amounts of NADPH.</p><p>So insulin stimulates the PPP to provide that NADPH.</p><p></p><p>6. Glutathione Demand (Oxidative Stress) → Activates G6PD</p><p>Effect</p><p>When cells experience oxidative stress, G6PD activity increases.</p><p>Why: Cells use glutathione (GSH) to neutralize reactive oxygen species.</p><p>Reaction: <span>2GSH+H2O2→GSSG+2H2O</span></p><p>But once glutathione becomes oxidized (<strong>GSSG</strong>), it must be regenerated:</p><p><span>GSSG+NADPH→2GSH</span></p><p>So oxidative stress increases <strong>NADPH consumption</strong>.</p><p>That raises <strong>NADP⁺ levels</strong>, which activates G6PD.</p>
17
New cards

Regulation of the hexose-monophosphate pathways: non-oxidative phase regulation

during the non-oxidative phase, we will also see different forms of regulation. mainly, this phase will be regulated by substrate availability and cellular demands for ribose-5-phosphate or glycolytic intermediates.

<p>during the non-oxidative phase, we will also see different forms of regulation. mainly, this phase will be regulated by substrate availability and cellular demands for ribose-5-phosphate or glycolytic intermediates.  </p>
18
New cards

Clinical Relevance of HMS

Finally, the clinical relevance of the hexose monophosphate shunt is mostly observed in conditions related to

1. oxidative stress (a harmful imbalance where reactive oxygen molecules accumulate faster than the cell can neutralize them.)

2. metabolic disorders

3. cancers.

in glucose-6-phosphate dehydrogenase deficiency cases, we will see that this could lead to hemolytic anemia

in the case of some cancers, we will see that increases levels of NADPH and ribose-5-phosphate will support tumor growth and reactive oxygen species

in diabetes, deregulation of the hexose monophosphate shunt will lead to increased oxidative stress and vascular damage.

For neurodegenerative conditions, like Alzheimer’s, we will see that decrease of hexose monophosphate pathway activity will lead to decreased levels of NADPH, which ultimately leads to increase levels of reactive oxygen species and neural damage.

Finally, there are also conditions that can affect the immune system, mostly, when there is glucose-6-phosphate dehydrogenase deficiency, which leads to impair or decrease immune response.

<p>Finally, the <strong>clinical relevance</strong> of the <strong>hexose monophosphate shunt </strong>is <strong>mostly observed</strong> in<strong> conditions</strong> <strong>related to</strong></p><p><strong>1. oxidative stress (</strong>a <strong>harmful imbalance </strong>where <strong>reactive oxygen</strong> molecules <strong>accumulate faster </strong>than the cell can neutralize them<strong>.)</strong></p><p>2. <strong>metabolic disorders</strong></p><p>3. <strong>cancers</strong>.</p><p>in <strong>glucose-6-phosphate dehydrogenase deficiency cases</strong>, we will see that this could lead to <strong>hemolytic anemia</strong></p><p>in the case of some <strong>cancers</strong>, we will see that increases levels of NADPH and ribose-5-phosphate will support tumor growth and reactive oxygen species</p><p>in <strong>diabetes</strong>, deregulation of the hexose monophosphate shunt will lead to increased oxidative stress and vascular damage.</p><p>For <strong>neurodegenerative conditions, like Alzheimer’s</strong>, we will see that <strong>decrease of hexose monophosphate pathway</strong> activity will lead to <strong>decreased levels of NADPH</strong>, which <strong>ultimately leads to increase levels </strong>of <strong>reactive oxygen species</strong> and <strong>neural damage.</strong></p><p>Finally, there are also conditions that can affect the immune system, mostly, when there is glucose-6-phosphate dehydrogenase deficiency, which leads to impair or decrease immune response.</p>
19
New cards

1. G6PD Deficiency (hemolytic anemia)

What happens in the pathway

Glucose-6-phosphate dehydrogenase (G6PD) is the rate-limiting enzyme of the PPP.

If it is deficient: 1. decreased G6PD → 2. decreased NADPH → 3. decreased glutathione (GSH)

Why this matters: Glutathione protects cells from oxidative damage.

Reaction:

2GSH+H2O2→GSSG+2H2O

But glutathione must be regenerated:

GSSG+NADPH→2GSH

The –SH (sulfhydryl) group is what neutralizes oxidants by donating electrons to the Reactive Oxygen Species (ROS).

the ROS wants to steal electrons from cellular molecules, damaging: lipids, proteins, DNA. This damage is called oxidative stress. Instead, the sulfhydryl group on GSH gives the electrons so there is no damage.

Without NADPH:

  • glutathione cannot be regenerated

  • oxidative damage accumulates

Clinical consequence

Red blood cells are most affected because they:

  • 1. lack mitochondria

  • 2. rely almost entirely on PPP for NADPH

Result: Hemolytic anemia during oxidative stress (Hemolytic anemia = anemia caused by destruction of red blood cells.)

2. What Hemolytic Anemia Actually Is

Normally, red blood cells (RBCs) live about:

120 days

Then they are removed by the spleen.

In hemolytic anemia (hemo: blood, lytic: “destroying” Anemia = “lack of blood.”, RBCs are destroyed faster than the bone marrow can replace them.

So the body develops:

Too few functional RBCs (Red blood cells break inside blood vessels.) → This reduces oxygen delivery to tissues.

Intravascular hemolysis

Red blood cells break inside blood vessels.

This releases hemoglobin directly into the blood.

Common causes:

  • G6PD deficiency

  • mechanical damage (prosthetic heart valves)

  • severe infections

4. What Happens When RBCs Break Down

When RBCs rupture:

  1. Hemoglobin is released

  2. Hemoglobin breaks into heme + globin

  3. Heme becomes bilirubin

So hemolysis leads to:

↑ bilirubin

This causes jaundice.

Triggers include:

  • infections

  • fava beans

  • sulfa drugs

  • antimalarials

20
New cards

2. Cancer

2. Cancer What happens in the pathway: Many cancers increase PPP activity.

This leads to: 1. increased NADPH 2. Ribose-5-phoshphate



Why cancer cells need this

Ribose-5-phosphate
→ used for DNA and RNA synthesis

Cancer cells divide rapidly and need lots of nucleotides.

NADPH
→ protects tumor cells from oxidative stress
→ supports fatty acid synthesis

Cancer cells produce many membranes for new cells.


Clinical consequence

PPP activation helps tumors:

  • 1. grow rapidly

  • 2. resist oxidative stress (ROS)

21
New cards

3. Diabetes

3. Diabetes

What happens: In diabetes, metabolism becomes dysregulated (insulin).

The PPP may not produce sufficient NADPH in some tissues.


Why this matters

Less NADPH means:

  1. less glutathione

  2. more reactive oxygen species

ROS damage:

  • endothelial cells

  • blood vessels

  • tissues



Clinical consequence

This contributes to diabetic complications:

  • retinopathy

  • nephropathy

  • neuropathy

  • vascular disease

22
New cards

4. Neurodegeneration

Examples:

  • Alzheimer’s disease (The protein amyloid-β accumulates in neurons and can enter mitochondria, inhibit mitochondrial enzymes, decrease ATP production and increase ROS)

  • Parkinson’s disease (In Parkinson’s disease, mitochondrial damage is central to the disease.

    The neurons most affected are dopamine neurons in the substantia nigra.

  • Many Parkinson’s patients show problems in Complex I of the electron transport chain.

    Result:

    ↓ ATP

    ↑ ROS

    Dopaminergic neurons are especially sensitive to oxidative stress.


What happens: PPP activity may decrease in neurons.

Result:

  1. decreased NADPH

  2. decreased antioxidant capacity

  3. decreased ROS



Why neurons are vulnerable

Neurons:

  • consume large amounts of oxygen

  • generate many reactive oxygen species

Without enough NADPH to maintain glutathione:

  1. oxidative stress → mitochondrial damage → neuronal death.

3. Connection to Alzheimer’s Disease

In Alzheimer’s disease, mitochondrial dysfunction occurs early.