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These flashcards cover complex identity proofs, evaluations, and series summations for Inverse Trigonometric Functions as found in JEE Advanced level lecture notes.
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What is the solution to the equation cos−1(2x)−2cos−1(1−x2)=π in the interval x∈[−1,1]?
The equation reduces to 2x=−(1−2x2), and the valid root is x=21−3.
If cos−1(α)=tan−1(α), what is the value of sin(cos−1α)?
By setting cos−1(α)=θ, we get cos(θ)=tan(θ), which leads to sin(θ)=25−1.
Evaluate d(tan(θ))df(θ) if f(θ)=sin(tan−1(cos(2θ)sin(θ))).
The expression simplifies to f(θ)=tan(θ), so its derivative with respect to tan(θ) is 1.
For the series Sn(x)=∑k=1ncot−1(1+k(k+1)x2), identify the value of cot(Sn(x)).
cot(Sn(x))=nx1+n(n+1)x2.
If a1=1,a2,a3,…,an are consecutive natural numbers, what is the value of the sum ∑k=12021tan−1(1+akak+11)?
The sum simplifies to tan−1(2022)−tan−1(1)=tan−1(2022)−4π.
In the context of the JEE problem on Page 12, what are the values of x and y given 3sin−1(log2x)+cos−1(log2y)=2π and sin−1(log2x)+2cos−1(log2y)=611π?
The specific values are x=2−1/2=21 and y=2−1=21.
What is the minimum value of x2+y2+2xysin(α) if cos−1(x)+sin−1(y)=α where 2π≤α≤π?
cos2(α)
Find the value of θ+ϕ if θ=tan−1(tan(43π)) and ϕ=tan−1(−tan(43π)).
0 (since θ=−4π and ϕ=4π within the principal values).
According to Page 19, what is the result of the sum ∑k=010sec(127π+2kπ)sec(127π+2(k+1)π)?
−8sin(67π)=4
What is the value of cot−1(cot(−11))+10sin(2cos−1(21))+10sin(2tan−1(2))?
45π−11
Given S={x∈R:sin−1(x2+2x+22(x+1))−cos−1(x2+2x+2x2+2x)=2π}, what are the elements of set S?
S={0,−1} (Based on calculations derived on Page 2).
If cos(x)+cos(y)+cos(z)=0 and sin(x)+sin(y)+sin(z)=0, what is the possible value of cos(x−y)?
−21