Science Double Award Co-Ordinated (0654) iGCSE 2026 Chemistry 3 (Stoichiometry)

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Last updated 4:08 AM on 4/22/26
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67 Terms

1
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What is the molecular formula of water?

H₂O

2
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What is the molecular formula of carbon dioxide?

CO₂

3
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What is the molecular formula of methane?

CH₄

4
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Define molecular formula.

The number and type of different atoms in one molecule of a compound.

5
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Why do ionic compounds not have molecular formulas?

Because they form a giant lattice rather than individual molecules, so their formula represents the ratio of ions.

6
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A compound contains 2 hydrogen atoms and 1 oxygen atom. What is its molecular formula?

H₂O

7
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Deduce the formula of a compound with 1 magnesium ion (Mg²⁺) and 2 chloride ions (Cl⁻).

MgCl₂

8
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Deduce the formula of a compound with 1 calcium ion (Ca²⁺) and 1 sulfate ion (SO₄²⁻).

CaSO₄

9
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What is the relationship between ionic charge and the formula of an ionic compound?

The total positive and negative charges must balance to form a neutral compound.

10
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A model shows 3 oxygen atoms for every 2 aluminum atoms. What is the formula?

Al₂O₃

11
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A compound contains sodium (Na⁺) and phosphate (PO₄³⁻) ions. Deduce its formula.

Na₃PO₄

12
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What is a word equation?

A way of representing a chemical reaction using the names of the reactants and products.

13
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What is a symbol equation?

A way of representing a reaction using chemical formulas instead of names.

14
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What are state symbols, and what do they represent?

(s) = solid, (l) = liquid, (g) = gas, (aq) = aqueous (dissolved in water).

15
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Write the word equation for the reaction of hydrogen and oxygen to form water.

Hydrogen + Oxygen → Water

16
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Write the symbol equation for the reaction of hydrogen and oxygen to form water.

2H₂(g) + O₂(g) → 2H₂O(l)

17
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Why must chemical equations be balanced?

The law of conservation of mass states that atoms cannot be created or destroyed in a reaction.

18
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What does (aq) mean in a chemical equation?

The substance is dissolved in water (aqueous solution).

19
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Why do we include state symbols in equations?

To show the physical state of each substance and provide more information about the reaction.

20
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Write the balanced symbol equation for the reaction of sodium and chlorine to form sodium chloride. Include state symbols.

2Na(s) + Cl₂(g) → 2NaCl(s)

21
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Write the word equation for the reaction of calcium carbonate with hydrochloric acid.

Calcium carbonate + Hydrochloric acid → Calcium chloride + Carbon dioxide + Water

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Write the balanced symbol equation with state symbols for the reaction of calcium carbonate and hydrochloric acid.

CaCO₃(s) + 2HCl(aq) → CaCl₂(aq) + CO₂(g) + H₂O(l)

23
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Write the ionic equation for the neutralization of hydrochloric acid with sodium hydroxide.

H⁺(aq) + OH⁻(aq) → H₂O(l)

24
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Compare a word equation and a symbol equation using an example.

Word equation: Magnesium + Oxygen → Magnesium oxide. Symbol equation: 2Mg(s) + O₂(g) → 2MgO(s)

25
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Identify the reactants and products in the equation: Zn(s) + 2HCl(aq) → ZnCl₂(aq) + H₂(g).

Reactants: Zn, HCl. Products: ZnCl₂, H₂.

26
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How can you tell if a reaction produces a gas by looking at the equation?

A gas will have the state symbol (g) in the products, e.g., CO₂(g), H₂(g), O₂(g).

27
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Why is it necessary to balance equations before using them in calculations?

To ensure the correct mole ratio is used, which follows the law of conservation of mass.

28
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Given the reaction aluminum reacts with oxygen to form aluminum oxide, deduce the balanced symbol equation with state symbols.

4Al(s) + 3O₂(g) → 2Al₂O₃(s)

29
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A reaction produces barium sulfate as a precipitate. Write the ionic equation for this reaction.

Ba²⁺(aq) + SO₄²⁻(aq) → BaSO₄(s)

30
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What is relative atomic mass (Aᵣ)?

The average mass of the isotopes of an element compared to 1/12th of the mass of a carbon-12 atom.

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Why is relative atomic mass (Aᵣ) not always a whole number?

Because it is the weighted average of all naturally occurring isotopes of an element.

32
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What is relative molecular mass (Mᵣ)?

The sum of the relative atomic masses of all atoms in a molecule.

33
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What is relative formula mass (Mᵣ)?

The sum of the relative atomic masses of all atoms in an ionic compound.

34
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What is the difference between relative molecular mass and relative formula mass?

Relative molecular mass is used for covalent molecules, while relative formula mass is used for ionic compounds.

35
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How do you calculate the relative molecular mass (Mᵣ) of H₂O?

(2 × 1) + (1 × 16) = 18.

36
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How do you calculate the relative formula mass (Mᵣ) of NaCl?

(1 × 23) + (1 × 35.5) = 58.5.

37
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In what units can concentration be measured?

g/dm³ (grams per cubic decimetre) or mol/dm³ (moles per cubic decimetre).

38
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What is the unit for the amount of substance?

The mole (mol).

39
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How many particles are in one mole of a substance?

6.02 × 10²³ particles (Avogadro's constant).

40
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What does Avogadro's constant represent?

The number of atoms, ions, or molecules in one mole of a substance.

41
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What is the formula to calculate the amount of substance (mol)?

Amount of substance (mol) = Mass (g) / Molar mass (g/mol).

42
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How do you calculate the mass of a substance?

Mass (g) = Amount of substance (mol) × Molar mass (g/mol).

43
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How do you calculate the molar mass of a substance?

Molar mass (g/mol) = Mass (g) / Amount of substance (mol).

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How do you calculate the relative atomic mass (Aᵣ) or relative molecular/formula mass (Mᵣ)?

By summing the relative atomic masses of the elements in a molecule or formula unit.

45
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How do you calculate the number of particles in a sample?

Number of particles = Amount of substance (mol) × Avogadro's constant (6.02 × 10²³).

46
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Calculate the amount of substance in 20 g of NaCl (Mᵣ = 58.5 g/mol).

Amount (mol) = 20 g ÷ 58.5 g/mol = 0.342 mol.

47
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Calculate the mass of 2 moles of H₂O (Mᵣ = 18 g/mol).

Mass (g) = 2 mol × 18 g/mol = 36 g.

48
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Calculate the molar mass of a substance if 5 moles have a mass of 200 g.

Molar mass (g/mol) = 200 g ÷ 5 mol = 40 g/mol.

49
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Calculate the relative formula mass of CaCO₃. (Aᵣ: Ca = 40, C = 12, O = 16)

Mᵣ = (1 × 40) + (1 × 12) + (3 × 16) = 100 g/mol.

50
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Calculate the number of molecules in 0.5 mol of CO₂. (Avogadro's constant = 6.02 × 10²³)

Number of molecules = 0.5 mol × (6.02 × 10²³) = 3.01 × 10²³ molecules.

51
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Calculate the amount of substance in 100 cm³ (0.1 dm³) of a 2 mol/dm³ HCl solution.

Amount (mol) = Concentration (mol/dm³) × Volume (dm³) = 2 × 0.1 = 0.2 mol.

52
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Calculate the mass of solute in 250 cm³ (0.25 dm³) of a 4 g/dm³ NaOH solution.

Mass (g) = Concentration (g/dm³) × Volume (dm³) = 4 × 0.25 = 1 g.

53
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What is the molar gas volume at room temperature and pressure (r.t.p.)?

24 dm³ per mole of gas.

54
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How do you calculate the volume of gas at r.t.p.?

Volume (dm³) = Amount (mol) × 24.

55
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Calculate the volume of 2 moles of oxygen gas (O₂) at r.t.p.

Volume = 2 mol × 24 dm³/mol = 48 dm³.

56
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How do you convert cm³ to dm³?

Divide by 1000 (1 dm³ = 1000 cm³).

57
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Convert 250 cm³ to dm³.

250 cm³ ÷ 1000 = 0.25 dm³.

58
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How do you calculate the amount of gas (mol) from volume at r.t.p.?

Amount (mol) = Volume (dm³) ÷ 24.

59
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Calculate the number of moles in 72 dm³ of hydrogen gas (H₂) at r.t.p.

Amount = 72 ÷ 24 = 3 mol.

60
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How do you calculate stoichiometric reacting masses?

Use the balanced chemical equation to find the molar ratio and convert between mass and moles.

61
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In the reaction 2Mg + O₂ → 2MgO, how much MgO is produced from 12 g of Mg? (Mᵣ of Mg = 24, MgO = 40)

Moles of Mg = 12 ÷ 24 = 0.5 mol. MgO produced = 0.5 mol × 40 = 20 g.

62
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How much volume of hydrogen gas is produced when 4 g of magnesium reacts with excess hydrochloric acid? (Equation: Mg + 2HCl → MgCl₂ + H₂, Aᵣ: Mg = 24, Molar gas volume = 24 dm³ at r.t.p.)

Moles of Mg = 4 ÷ 24 = 0.167 mol. From the equation, 1 mol Mg produces 1 mol H₂, so 0.167 mol Mg produces 0.167 mol H₂. Volume of H₂ = 0.167 × 24 = 4 dm³.

63
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What volume of carbon dioxide gas is produced from the decomposition of 50 g of CaCO₃? (Equation: CaCO₃ → CaO + CO₂, Mᵣ: CaCO₃ = 100, Molar gas volume = 24 dm³ at r.t.p.)

Moles of CaCO₃ = 50 ÷ 100 = 0.5 mol. From the equation, 1 mol CaCO₃ produces 1 mol CO₂, so 0.5 mol produces 0.5 mol CO₂. Volume of CO₂ = 0.5 × 24 = 12 dm³.

64
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Calculate the concentration in mol/dm³ of a solution containing 20 g of NaOH in 500 cm³ of solution. (Mᵣ: NaOH = 40)

Amount of NaOH = 20 ÷ 40 = 0.5 mol. Convert cm³ to dm³: 500 ÷ 1000 = 0.5 dm³. Concentration = 0.5 mol ÷ 0.5 dm³ = 1 mol/dm³.

65
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What mass of H₂SO₄ is needed to prepare 250 cm³ of a 2 mol/dm³ solution? (Mᵣ: H₂SO₄ = 98)

Convert cm³ to dm³: 250 ÷ 1000 = 0.25 dm³. Moles of H₂SO₄ = 2 × 0.25 = 0.5 mol. Mass = 0.5 × 98 = 49 g.

66
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Determine the limiting reagent when 10 g of H₂ reacts with 80 g of O₂. (Equation: 2H₂ + O₂ → 2H₂O, Aᵣ: H = 1, O = 16)

Moles of H₂ = 10 ÷ (2 × 1) = 5 mol. Moles of O₂ = 80 ÷ (16 × 2) = 2.5 mol. From the equation, 2 mol H₂ reacts with 1 mol O₂, so 5 mol H₂ requires 2.5 mol O₂. Since both are in the correct ratio, neither is limiting. Both react completely.

67
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Determine the limiting reagent when 20 g of Mg reacts with 40 g of HCl. (Equation: Mg + 2HCl → MgCl₂ + H₂, Aᵣ: Mg = 24, HCl = 36.5)

Moles of Mg = 20 ÷ 24 = 0.833 mol. Moles of HCl = 40 ÷ 36.5 = 1.096 mol. From the equation, 1 mol Mg reacts with 2 mol HCl, so 0.833 mol Mg requires 1.67 mol HCl. Since there is only 1.096 mol HCl available, HCl is the limiting reagent.