Toughness and Creep Resistance

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Last updated 5:41 PM on 5/19/26
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26 Terms

1
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What is toughness?

The energy required to fracture a material; it represents a material’s resistance to brittle fracture or sudden cracking under load.

2
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How is toughness represented on a stress–strain curve?

By the total area under the curve — the greater the area, the tougher the material.

3
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How is toughness different from strength?

Strength measures the maximum stress a material can withstand, while toughness measures the energy absorbed before fracture.

4
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What are two ways to measure toughness?

Energy absorbed to fracture a specimen (J), AND Energy per unit fracture area (J/m²)

5
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What are the main types of fracture?

Ductile (high-energy, cup-and-cone) and brittle (low-energy, flat fracture surface).

6
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How does temperature affect toughness?

Lower temperatures make materials more brittle, reducing toughness; higher temperatures make them more ductile.

7
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What is the Charpy impact test used for?

To measure the impact energy absorbed during fracture and determine the brittle-ductile transition temperature (BDTT)

8
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Describe the Charpy impact test procedure?

A notched bar is struck by a pendulum hammer; the energy lost by the pendulum equals the energy absorbed by the specimen.

9
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What does the Charpy test plot show?

Impact energy vs. temperature, showing low energy (brittle) at low T and high energy (ductile) at high T.

10
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What is the brittle-ductile transition temperature (BDTT)?

The temperature at which a material changes from brittle to ductile behaviour on the Charpy plot.

11
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Does the Charpy test give a material property?

No, it provides a comparative measure of toughness, not an intrinsic property

12
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Define creep?

The increase of strain with time at a constant stress and sufficiently high temperature

13
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How is the deformation of most metals and ceramics different (on dependence) at room temperature compared to high temperatures?

Low temp: ε = f(σ)

High temp: ε = f(σ,t,T)

14
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What can determine approximate sensitivity to creep?

T/Tm = operating temp/melting temp

15
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When does creep become important for polymers?

Above room temperature

16
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When does creep become important for metals?

above 0.3–0.4 Tₘ

17
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When does creep become important for Ceramics?

above 0.4–0.5 Tₘ

18
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Give examples of components affected by creep

Turbine blades, high-pressure pipes, boiler tubes, and light-bulb filaments

19
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Describe the main regions of a creep curve (ε against time)

Initial elastic strain, primary creep , secondary creep (steady-state), tertiary creep (accelerating until rupture).

<p>Initial elastic strain, primary creep , secondary creep (steady-state), tertiary creep (accelerating until rupture).</p>
20
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What is steady-state creep rate and why is it important? (ε˙s)

It’s the constant creep rate in the secondary stage; used to design long-life components such as power-plant parts

21
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Write the generalised creep law

ε˙s​=Ae−Q/RTσn

22
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What do the constants in the creep law represent?

A = material constant, Q = activation energy, R = gas constant (8.31 J mol⁻¹ K⁻¹), T = temperature (K), n = creep exponent (3–8).

23
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Why is creep characterisation carried out at constant stress or constant temperature?

It enables the effect of stress or temperature to be isolated, hence determined.

24
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What is the simplified form of the creep law at constant temperature?

ε˙s​=Bσn; plotting log ε̇ vs log σ gives a straight line with slope n

<p><span>ε˙s​=Bσ</span><sup><span>n</span></sup>; plotting log ε̇ vs log σ gives a straight line with slope n</p>
25
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What is the simplified form of the creep law at constant stress?

ε˙s​=Ce−Q/RT; plotting ln ε̇ vs 1/T gives a straight line with slope −Q/R.

<p><span>ε˙s​=Ce</span><sup><span>−Q/RT</span></sup>; plotting ln ε̇ vs 1/T gives a straight line with slope −Q/R.</p>
26
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What causes creep at the atomic level?

The diffusion and movement of atoms and dislocations that allow slow plastic deformation over time.