Complex Analysis Part 2

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Complex Integration to the end (wk 7-12)

Last updated 3:00 AM on 4/12/26
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44 Terms

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C’ Path

gamma is a C’ Path if it is differentiable and its derivative is continuous

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Smooth path

A path is smooth if it is infinitely differentiable

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Integral over a C’ Path

∫fdz := ∫f(δ(t))*δ’(t)dt


(δ is the path, take the integral from the endpoints)

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∫f(z) dz over p1+p2

∫f(z)dz over p1 + ∫g(z)dz over p2

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Arc length of a path

l(p) = ∫|p’(t)|dt

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Bounding integral lemma

| ∫f(z)dz | ≤ M * l(p), where M is a real number M>0 s.t. |f(z)| ≤ M
(M is a maximum of f(z))

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Fundamental theorem of contour integrals

∫f(z) dz over p = F(p(b)) - F(p(a))

given: p is c’ path, f is continuous and defined on the same set as p, f has an integral.

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T/F the integral of F over p is path dependent

F - depends only on endpoints

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Morera Thoerem

∫f dz over p = 0,

given: p is a simple closed path, f is analytic.

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∮ vs ∫

∮ is for closed paths.

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Cauchy-Goursat Theorem

∮f(z)dz over C = 0.
where f is analytic in and on its boundary C.

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Consequences of Cauchy’s Theorem

  1. ∫ f(z)dz over p1 = ∫ f(z)dz over p2 (path independence)

  2. G(z) = ∫f(z)dz, then G is analytic

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Cauchy Integral Fomulas

1/2ipi ∫ f(z)/z-a dz = f(a)
and
the nth derivative of f at a = n!/2ipi
∫f(z)/(z-a)^(n+1) dz (provided the nth deriative exists)

gamma must be a closed curve, f must be holomorphic on and inside gamma

<p>1/2ipi <em>∫ f(z)/z-a dz = f(a)<br>and<br>the nth derivative of f at a = n!/2ipi </em>∫f(z)/(z-a)^(n+1) dz <em>(</em>provided the nth deriative exists)<br><br>gamma must be a closed curve, f must be holomorphic on and inside gamma</p>
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Cauchy’s Inequalities

| f^n (a) | = M * n!/p^n for n∈W
where M = max{ |f(z)| : |z-a| = r } (the maximum value of f at the border of the circle

<p>| f^n (a) | = M * n!/p^n for n∈W<br>where M = max{ |f(z)| : |z-a| = r } (the maximum value of f at the border of the circle</p>
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Louiville’s Thoerem

Every bounded, entire function is constant.

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Fundamental theorem of Algebra

every non-constant polynomial in C has at least one root in C

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Gauss’ mean value theorem

f(a) = 1/2pi * ∫p f(a+re^iθ) dθ
f os analytic in and on the circle |z-a| = r

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Maximum Modulus Theorem

if f is analytic in and in a simple closed curve, fmax is on the boundary

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Types of singularities

  1. Isolated

  2. Removable

  3. Poles

  4. Essential

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Isolated Singularity

there are no other singularities right next to it

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Removable Singularity

an isolated singularity where the lim f(z) at the singularity exists. check either by l’Hopital or factoring and cancelling.

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Pole

isolated singularity where lim z→a of (z-a)n *f(z) exists and is non-zero

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Essential Singularity

isolated singularity which is not removable or a pole

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Argument Theorem

1/2ipi * ∮p f’/f dz = N - P
f is holomorphic and non-vanishing in and on p. N,P are counted with multiplicity

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Rouche’s Theorem

if |g(z)| < |f(z)| ∀ z∈δ, then f and f+g have the same number of zeros inside δ

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Entire/Analytic

differentiable at all points on the complex plane

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Meromorphic

analytic everywhere except at a finite number of poles

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Convergence Tests

  1. Ratio

  2. Root

  3. Weierstass M Test

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Ratio Test

let L:= lim | un+1 | / | un |, n→inf

if L<1, convergence

if L > 1 divergence

if L = 1, inconclusive

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Root test

let L:= lim |un|1/n

the sum of un :

converges if L < 1

diverges if L > 1

inconclusive if L = 1

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Wierstrass M-Test

if |un| ≤ Mn and ∑1infMn converges, then ∑1n uniformly converges

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Properties of uniformly convergent series

  1. if un is holomorphic and ∑1infun is uniformly convergent, then ∑1infun is holomorphic

  2. If un is holomorphic, then u’(z) = ∑1infu’n (differentiate termwise)

  3. Integrate termwise if un is continuous

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Taylors Theorem

let f be holomorphic on and inside δ with center at w=a, then

f(w) = f(a) + f’(a) + f”(a)/2! (w-a)² + … + f(n)(a)/n!*(w-a)n

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Laurent’s Theorem

f(z) = ∑1infa-n/(z-a)n + ∑0infan(z-a)n = ∑-infinfan(z-a)n

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Residue

f is holomorphic on and inside a circle except at the center a, then
f(z) = ∑-infinfan(z-a)n

and an = 1/2ipi * ∮ f(z) / (z-a)n+1 dz,

an is called the residue.

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Cauchy’s Residue Theorem

1/2ipi * ∮f(z)dz = sum of the residues

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Residue Limit Formula

a-1 = limz→a 1/(k-1)! dk-1/dzk-1 (z-a)k * f(z)

<p>a<sub>-1 </sub> = lim<sub>z→a</sub> 1/(k-1)! <em> d<sup>k-1</sup>/dz<sup>k-1</sup> (z-a)<sup>k</sup> * f(z)</em></p>
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