Mathematical Relations and Properties

0.0(0)
Studied by 0 people
call kaiCall Kai
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/5

flashcard set

Earn XP

Description and Tags

A set of vocabulary flashcards covering the definitions and properties of reflexive, symmetric, transitive, and equivalence relations as discussed in the lecture.

Last updated 5:36 AM on 6/6/26
Name
Mastery
Learn
Test
Matching
Spaced
Call with Kai

No analytics yet

Send a link to your students to track their progress

6 Terms

1
New cards

Reflexive Relation

A relation on a set AA where (a, a) \text{\textin} r for every a \text{\textin} A; for example, if A=1,2,3A = {1, 2, 3}, the relation contains (1,1)(1, 1), (2,2)(2, 2), and (3,3)(3, 3).

2
New cards

Symmetric Relation

A relation where if (a, b) \text{\textin} R, then it must also be true that (b, a) \text{\textin} R.

3
New cards

Transitive Relation

A relation where if (a, b) \text{\textin} R and (b, c) \text{\textin} R, then (a, c) \text{\textin} R must also be true.

4
New cards

Equivalence Relation

A relation that satisfies three specific conditions: it is Reflexive, Symmetric, and Transitive (often abbreviated as RST).

5
New cards

Non-Symmetric Example

In the set A=1,2,3A = {1, 2, 3}, the relation R={(1,1),(2,2),(3,3),(1,2),(2,3)}R = \text{\textbraceleft}(1, 1), (2, 2), (3, 3), (1, 2), (2, 3)\text{\textbraceright} is not symmetric because (1, 2) \text{\textin} R but (2, 1) \text{\textnotin} R.

6
New cards

Non-Transitive Example

In the set A=1,2,3A = {1, 2, 3}, the relation R={(1,1),(2,2),(3,3),(1,2),(2,3)}R = \text{\textbraceleft}(1, 1), (2, 2), (3, 3), (1, 2), (2, 3)\text{\textbraceright} is not transitive because while (1, 2) \text{\textin} R and (2, 3) \text{\textin} R, the pair (1, 3) \text{\textnotin} R.