Orgo 2 Exam 3 (Ch 20)

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Last updated 1:02 AM on 4/10/26
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35 Terms

1
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carboxylic acid derivatives

acid halide

anhydride

ester

amide

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how does LG affect reactivity

acid halide > anhydride > ester > amide

  • as list progresses:

    • LG becomes less e- neg

    • LG becomes a less likely LG

    • LG becomes less acidic

    • resonance increases, more stable, unlikely to react

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LGs and their notes

  • -X —> fast, even at room temp

  • -OCOR —> slow at RT but still reacts with nucleophile

  • -OR —> very slow, use catalyst or heat

  • -NR2 —> not observed, unles use catalyst, heat, time

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resonance with acid derivatives

  • resonance with acid halide: (+) on X, (-) on O

    • minor resonance product, because (+) charge on a highly e- neg atom

  • resonance with amide: (+) on NR2, (-) on O

    • important contributor because (+) is stable enough.

    • C=N double bond is shorter than C=X bond in above resonance.

    • NMR shows 2 isomer outcomes due to barrier rotation

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where on carboxylic acid is acidic and basic

alpha protons are acidic and will react with base

O is basic

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acidity trend in acid derivatives

acid halide > ketone > ester > amide

  • acid halide most acidic bc inducitive effect of very e- neg X. X is not a good resonane donator, so little resonance stabilizer bc no N to donate e- pair.

    • has the least stable CB —> more acidic molecule

  • amide is the most basic because it has the best resonance forms as N donates e- pair. the alpha H becomes less acidic and less likely to deprotonate.

    • the negative charge on the O shows resonance delocalization and electron density pulled from N to O

better electron donating abilities makes the molecule more stable and less acidic —> most basic (the amide)

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how do alcyl halides react

via addition elimination

  • are very reactive due to dipole facing O —> X

acid halide + carboxylic acid —> anhydride

acid halide + H2O —> carboxylic acid

acid halide + ROH —> ester

acid halide + H-NR2 —> amide

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mech for addition-elim of alycl halides

O from ROH adds to carbbonl carbon as nucleophile, arrow from bond to O

O makes double bond, Cl LG

Cl- base deprotonates H from ROH (use pyridine or amine if doing amine)

  • same mech for all reactions

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carboxylic acid + SOCl2 + ROH,pyridine (bulky base)

—> ester

  • need to use this method to make t-butyl esters

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alycl halide —> ketone

R-CuLi

  • cant use grignard, because will react twice after product is formed whereas cuprates dont react with ketones

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reduction of alcyl halides

  • alcyl halide —> ROH

    • 1) LiAlH4 2) H+ workup- because very strong

  • alcyl halide —> aldehyde

    • 1) LiAl(OtBu)3H 2) H+ workup

      • more bulky and less reactive- will react with reactive alycl halide, but not strong enough to react with less reactive aldehyde

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anhydride reactions

anhydride + H2O —> acid

anhydride + ROH —> ester

anhydride + RNH —> amide

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symmetrical anhydrides reactions

symmetrical anhydrides will give 2 products with reaction, because will react at both carbonyl carbons

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esters properties

slow reactions, catalyst helps, OR is a poor LG

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ester hydrolysis to carboxylic acid

ester + TsOH,H2O,acetone,heat —> carboxylic acid + EtOH

  • padped reverse reaction of ester formation

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ester under basic conditions- saponification: ester + -OH,H2O,heat —>

—> carboxylate ion + EtOH

mech

  • -OH adds to carbonyl C, arrow to O

  • O to double bond, OR is LG

  • -OR attacks H from O-H, O gets negative charge

    • CH3OH byproduct

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ester + 1)-OH,H2O,heat 2) H+ workup

—> carboxylic acid

  • needs acid workup to make this product, without it will get carboxylate ion

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ester —> carboxylic acid

carboxylic acid —> ester

ester —> carboxylic acid

  • add H2O

carboxylic acid —> ester

  • add ROH

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transesterification

one ester to another ester

  • OMe ester + EtOH,TsOH,heat —> OEt ester

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converting an ester to an amide

ester + amine,heat —> amide

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ester + 1) grignard 2) H+ workup

grignards add twice, so will get OH and 2 of the R groups in product

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ester + 1) LiAlH4, Et2O 2) H3O+, H2O

replaces OR with OH, removes carbonyl

  • very strong reducing agent

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ester + 1) DIBAL, -78°C 2) H3O+, H2O

makes aldehyde

  • replaces OR with H, keeps carbonyl

DIBAL is bulky version of LiAlH4 (Al with 2 isobutyls and an H)

  • is less reactive than LiAlH4 because of sterics

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ester + 1) LDA, 0° 2) R-Br

adds R-Br to alpha carbon

  • via intermediate enolate

    • problem: side reaction-claisen condensation

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amide reaction conditions

are the least reactive derivative so reactions will require heat

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amide hydrolysis: acid vs basic

acidic: amide + H2SO4,H2O,heat —> carboxylic acid + (+)amide group with 2 extra Hs added

basic: amide + NaOH,H2O,heat —> carboxylate ion(-) + amide group with 1 extra H

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amide + 1) -OH,H2O,heat 2) H3O+,H2O

carboxylic acid

  • even tho step 1 is base, to end with acid product, last step must be acidic

mech

  • PADPED like ester hydrolysis

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amide reduction to ROH

amide + 1) LiAlH4, THF 2) H3O+,H2O 3) -OH,H2O

  • same amide molecule but carbonyl O replaced with 2 Hs

    • N bonds don’t break as easily

    • use basic workup at end to end with basic amine product

mech

  • from ws

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amide + 1) DIBAL 2) H3O+,H2O

makes aldehyde- replaces amide group with H

  • because of DIBAL sterics, so less reactive

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hoffmann rearrangement

amide + Br2,NaOH,H2O

  • C=O gets removed and replaced with the amide group

    • loses a carbon

  • CO2 byproduct

mech

  • from ws

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amidate

amide group with one less H- so has negative charge

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nitrile hydrolysis

acidic: R-CN + H2SO4,H2O,heat —> R-COOH (carboxylic acid)

basic: R-CN + 1) -OH,H2O,heat 2) H3O+, H2O —> R-COOH (cabroxylic acid)

acidic mech: PADPED

  • first step protonate N

basic mech: start with addition and get carboxylate ion product unless adding H+ workup

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when to do PADPED vs addition-elimination

when you have a bad nucleophile like H2O, you are under acidic conditions and need to protonate- so do PADPED

when you have a good nucleophile (like -OH) you dont need to protonate so can do addition-elimination

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nitrile + organometallic

R-CN + CH3Li + 1) THF, 2) H+,H2O —> remove N, becomes ketone with R group on other side

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3 methods of nitrile reduction

  • R-CN + 1) DIBAL 2) H3O+,H2O —> aldehyde

  • R-CN + 1) LiAlH4,THF 2) H3O+,H2O —> replace N with NH2

  • R-CN + H2,cat Pt —> replace N with NH2