a level organic

0.0(0)
Studied by 0 people
call kaiCall Kai
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/250

encourage image

There's no tags or description

Looks like no tags are added yet.

Last updated 5:14 PM on 6/13/26
Name
Mastery
Learn
Test
Matching
Spaced
Call with Kai

No analytics yet

Send a link to your students to track their progress

251 Terms

1
New cards

state why Si(CH3) is used in 1NMR and explain how its properties make it suitable for use in 1NMR:

Si(CH3) aka. TMS:

  • TMS as reference/calibration/standard/peak at 0

  • inert (so unlikely to react w/ the sample)

  • gives one signal (as has lots of equivalent Hs)

  • signal in an area away from other typical H signals

  • easy to remove/volatile/low bpt

<p>Si(CH<sub>3</sub>) aka. TMS:</p><ul><li><p>TMS as reference/calibration/standard/peak at 0</p></li><li><p>inert (so unlikely to react w/ the sample)</p></li><li><p>gives one signal (as has lots of equivalent Hs)</p></li><li><p>signal in an area away from other typical H signals</p></li><li><p>easy to remove/volatile/low bpt</p></li></ul><p></p>
2
New cards

state why CDCl3 or CCl4 is used in 1NMR and explain how its properties make it useful for use in 1NMR:

  • CDCl3 or CCl4 solvent

  • both have no Hs (so give no signals in spectrum)

  • CCl4 non polar (so good solvent for non polar organic molecules)

  • CDCl3 polar covalent molecules (so good solvent for polar organic compounds)

<ul><li><p>CDCl<sub>3</sub> or CCl<sub>4</sub> solvent</p></li><li><p>both have no Hs (so give no signals in spectrum)</p></li><li><p>CCl<sub>4</sub> non polar (so good solvent for non polar organic molecules)</p></li><li><p>CDCl<sub>3</sub> polar covalent molecules (so good solvent for polar organic compounds)</p></li></ul><p></p>
3
New cards
<p>suggest why it is difficult to use Table B in the Data Booklet to predict the chemical shift for the peak given by the H atom labelled y (1)</p>

suggest why it is difficult to use Table B in the Data Booklet to predict the chemical shift for the peak given by the H atom labelled y (1)

H attached to both C-Cl and adjacent to C=O so doesn’t fit w/ data in table B

4
New cards

give the structure of TMS:

knowt flashcard image
5
New cards

what does NMR stand for? what does it give info about?

  • NMR = nuclear magnetic resonance

  • gives info about the position of 13C or 1H atoms in a molecule

6
New cards

what does it mean for 1H atoms/13C atoms to be equivalent?

in the same chemical environment

<p>in the same chemical environment</p>
7
New cards

what is chemical shift (δ)?

difference between TMS peak and peaks produced by substance under test

8
New cards

what does the vertical axis on an NMR spectrum represent?

intensity of absorption

9
New cards

what does the chemical shift depend on?

  • depends on what other atoms/groups are near the 1H/13C atom

  • more electronegative groups give a greater chemical shift

10
New cards

give the components of a proton NMR spectrum and what information they provide:

  • no. of peaks = no. of different 1H environments

  • chemical shifts = type of environment the 1H atoms are in

  • integration ratio = no. of no.s of H atoms on each environment

  • splitting = no. of H atoms on adjacent C atom

11
New cards

give the components of a carbon-13 NMR spectrum and what information they provide:

  • no. of peaks = no. of diff carbon-13 environments

  • chemical shifts = type of environment 13C atoms are in

12
New cards

what is the integration ratio?

ratio of no. of hydrogen atoms in each environment

13
New cards

when does splitting not ocur?

  • H atoms are equivalent

  • H atoms on O atoms

14
New cards
<p>can you fill in this table?</p>

can you fill in this table?

yes :)

<p>yes :)</p>
15
New cards

what is the eqn used to determine splitting?

n + 1 (where n = no. of H atoms on adjacent C)

16
New cards
<p>deduce the structure of <strong>Q</strong> (C<sub>3</sub>H<sub>7</sub>ClO) - <strong>explain</strong> your answer (5)</p>

deduce the structure of Q (C3H7ClO) - explain your answer (5)

  • integration ratio 2:2:3

  • peak at 3.95:

    • has 2 Hs in environment, is a triplet so has 2Hs on adjacent C so must be CH2-Cl next to CH2

  • peak at 3.65:

    • has 2 Hs in environment, is a triplet so has 2 Hs on adjacent C atom so must be O-CH2 next to CH2

  • peak 3.35:

    • has 3 H atoms in its environment, is a singlet so has no H atoms on adjacent C atom so must be O-CH3

<ul><li><p>integration ratio 2:2:3</p></li><li><p><strong>peak at 3.95:</strong></p><ul><li><p>has 2 Hs in environment, is a triplet so has 2Hs on adjacent C so must be <strong>CH<sub>2</sub>-Cl next to CH<sub>2</sub></strong></p></li></ul></li><li><p><strong>peak at 3.65: </strong></p><ul><li><p>has 2 Hs in environment, is a triplet so has 2 Hs on adjacent C atom so must be <strong>O-CH<sub>2 </sub>next to CH<sub>2</sub></strong></p></li></ul></li><li><p><strong>peak 3.35:</strong></p><ul><li><p>has 3 H atoms in its environment, is a singlet so has no H atoms on adjacent C atom so must be <strong>O-CH<sub>3 </sub></strong></p></li></ul></li></ul><p></p>
17
New cards

give the eqn for the partial dissociation of carboxylic acids in water:

knowt flashcard image
18
New cards

state where the PoE lies for the partial dissociation of carboxylic acids in water and explain why:

  • PoE lies to the left as most molecules do not dissociate

  • ∴ making carboxylic acids weak acids

<ul><li><p>PoE lies to the left as most molecules do not dissociate</p></li><li><p><span><span>∴ making carboxylic acids weak acids</span></span></p></li></ul><p></p>
19
New cards

give the general word eqn for the reaction between an acid and alkali:

acid + alkali → salt + water

20
New cards

give the general word eqn for the reaction between an acid and a carbonate:

acid + carbonate → carbon dioxide + salt + water

21
New cards

give the general word eqn for the reaction between an acid and a metal:

acid + metal → salt + hydrogen

22
New cards

give the eqn for the reaction between ethanoic acid and sodium hydroxide - name the product:

  • CH3COOH + NaOH → CH3COO-Na+ + H2O

  • CH3COO-Na+ = sodium ethanoate (this is a salt, not an ester!)

23
New cards

give the eqn for the reaction between ethanoic acid and ammonia - name the product:

  • CH3COOH + NH3 → CH3COO-NH4+

  • ammonium ethanoate (this is a salt, not an ester!)

24
New cards

give the eqn for the reaction between ethanoic acid and sodium carbonate and name the product:

  • 2CH3COOH + Na2CO3 → CO2 + H2O + 2CH3COO-Na+

  • 2CH3COO-Na+ = sodium ethanoate

25
New cards

give the eqn for the reaction between ethanoic acid and sodium and name the product:

  • 2CH3COOH + 2Na → H2 + 2CH3COO-Na+

  • 2CH3COO-Na+ = sodium ethanoate

26
New cards

give the eqn for the reaction between ethanoic acid and magnesium and name the product:

  • 2CH3COOH + Mg → H2 + (CH3COO-)2Mg2+

  • (CH3COO-)2Mg2+ = magnesium ethanoate

27
New cards

give the general eqn for the formation of esters and state the conditions - what is this process called?

  • conc H2SO4 catalyst

  • esterification (condensation reaction)

<ul><li><p>conc H<sub>2</sub>SO<sub>4 </sub>catalyst</p></li><li><p>esterification (condensation reaction)</p></li></ul><p></p>
28
New cards

what is the ester functional group?

<p></p>
29
New cards

how do we name esters?

  • first part - from alcohol used (on RHS)

  • second part - from carboxylic acid used (on LHS)

<ul><li><p>first part - from alcohol used (on RHS)</p></li><li><p>second part - from carboxylic acid used (on LHS)</p></li></ul><p></p>
30
New cards

give 4 uses of esters:

  • solvents

  • plasticisers

  • perfumes

  • food flavourings

31
New cards

give the general eqn for the acid hydrolysis of an ester - state the conditions and products:

  • dilute acid (typically H2SO4) catalyst

  • heated under reflux

  • products = carboxylic acid and alcohol

<ul><li><p>dilute acid (typically H<sub>2</sub>SO<sub>4</sub>) catalyst</p></li><li><p>heated under reflux</p></li><li><p>products = carboxylic acid and alcohol</p></li></ul><p></p>
32
New cards

give the general eqn for the base hydrolysis of an ester - state the conditions and products:

  • heated under reflux

  • products = salt (of the carboxylic acid) and alcohol

<ul><li><p>heated under reflux</p></li><li><p>products = salt (of the carboxylic acid) and alcohol</p></li></ul><p></p>
33
New cards

give and justify 4 safety measures necessary when heating under reflux in the formation of esters:

  • use a fume cupboard - to avoid breathing in harmful/toxic/corrosive compounds

  • add anti-bumping granules - to ensure smooth boiling/reduce size of bubbles

  • use an electric heater/water bath - as compounds are flammable

  • wear gloves - compounds may be corrosive

34
New cards

why might we shake the reaction mixture with aqueous sodium carbonate after making esters? what precaution should be taken when doing this and why?

  • to neutralise/react with XS acid

  • you should remove the stopper to prevent a buildup of pressure as CO2 is produced

35
New cards

why may we add anhydrous magnesium sulfate when making esters?

drying agent

36
New cards

which alcohol are animal fats and vegetable oils made from in esterification?

propane-1,2,3-triol (glycerol)

37
New cards

give the general structure of a triglyceride (lipid):

knowt flashcard image
38
New cards

give and explain one example where base hydrolysis may be used and give the word and symbol eqn:

making soap (saponification) - reacting a lipid w/ a strong base forms salts of the fatty acids and glycerol

<p>making soap (saponification) - reacting a lipid w/ a strong base forms salts of the fatty acids and glycerol</p>
39
New cards

what are biodiesels? how are they made?

  • biodiesel (renewable fuel) = mixture of methyl esters of long-chain carboxylic acids

  • produced by reacting vegetable oils w/ methanol in the presence of a catalyst

40
New cards

give the word and symbol eqn for making biodiesels:

<p></p>
41
New cards

during ester hydrolysis, 2 layers form in the separating funnel - suggest why ethyl ethanoate forms the upper layer (2)

  • ethyl ethanoate is immiscible with/insoluble in water - if 1 mark - this point usually!

  • ethyl ethanoate is less dense/has a lower density (than water)

42
New cards

why may anhydrous calcium chloride be added when heating under reflux to make an ester?

as a drying agent

43
New cards

what can chromatography be used for?

to separate and identify the components in a mixture

44
New cards

name the 3 types of chromatography:

  • thin-layer chromatography (TLC)

  • column chromatography (CC)

  • gas chromatography (GC)

45
New cards

in chromatography, what does separation depend on?

the balance between solubility in the moving phase and retention by the stationary phase

46
New cards

what is thin-layer chromatography (TLC)?

chromatography in which a plate is coated w/ a solid and a solvent moves up the plate

<p>chromatography in which a plate is coated w/ a solid and a solvent moves up the plate </p>
47
New cards

what is column chromatography (CC)?

chromatography in which a column is packed w/ a solid and a solvent moves down the column

<p>chromatography in which a column is packed w/ a solid and a solvent moves down the column</p>
48
New cards

what is gas chromatography?

chromatography in which a column is packed w/ a solid/solid coated by a liquid and a gas is passed through the column under pressure at high temps

<p>chromatography in which a column is packed w/ a solid/solid coated by a liquid and a gas is passed through the column under pressure at high temps </p>
49
New cards

what is the moving/mobile phase?

  • carries the soluble components of the mixture

  • always a liquid or gas

50
New cards

what is the stationary phase?

  • the solid the mobile phase moves over

  • holds back components which are attracted to it

51
New cards

what affects the distance that each substance moves up the plate?

  • components that are more soluble in the mobile phase will travel further up the plate i.e. move more quickly

  • components that have a higher affinity for the stationary phase will travel less far up the plate i.e. move more slowly

52
New cards

describe the process of thin layer chromatography (TLC):

  1. draw a line in pencil near the bottom of the TLC plate

  2. add small drops of each mixture to be separated along the initial pencil line using a capillary tube

  3. leave the spots to dry

  4. place TLC plate in a beaker w/ a small amount of solvent - the level of the solvent must be below the baseline - and cover the top with a watch glass

  5. the solvent (mobile phase) will move up the plate, separating the different substances in the mixture

  6. leave until the solvent almost reaches the top of the plate and use a pencil to mark this as the solvent front

  7. leave to dry

  8. reveal using a UV lamp or using iodine/potassium permanganate

<ol><li><p>draw a line in pencil near the bottom of the TLC plate</p></li><li><p>add small drops of each mixture to be separated along the initial pencil line using a capillary tube</p></li><li><p>leave the spots to dry</p></li><li><p>place TLC plate in a beaker w/ a small amount of solvent - the level of the solvent must be below the baseline - and cover the top with a watch glass</p></li><li><p>the solvent (mobile phase) will move up the plate, separating the different substances in the mixture</p></li><li><p>leave until the solvent almost reaches the top of the plate and use a pencil to mark this as the solvent front</p></li><li><p>leave to dry</p></li><li><p>reveal using a UV lamp or using iodine/potassium permanganate</p></li></ol><p></p>
53
New cards

what is the purpose of the lid/watch glass in TLC?

  • to prevent the solvent from evaporating

  • so atmosphere in beaker is saturated w/ solvent vapour

<ul><li><p>to prevent the solvent from evaporating </p></li><li><p>so atmosphere in beaker is saturated w/ solvent vapour</p></li></ul><p></p>
54
New cards

give 2 methods of revealing TLC plates:

  • put plate under UV lamp

  • dip chromatogram into iodine to reveal the spots

55
New cards

state why components separate in chromatography:

difference in balance between solubility in the mobile phase and retention by the stationary phase

<p>difference in balance between solubility in the mobile phase and retention by the stationary phase</p>
56
New cards

give the formula used to calculate Rf values - how can we use these values to identify the substance?

  • Rf = distance moved by spot/distance moved by solvent

  • compare Rf value to known value (same mobile/stationary phases must be used)

57
New cards

what is column chromatography typically used for?

purification of large quantities of organic compounds

58
New cards

describe the process of column chromatography (CC):

  1. the sample to be purified is placed at the top of the column filled w/ the solid stationary phase

  2. solvent is flushed through the column, carrying the mixture components at diff rates

  3. components separate based on their solubility in the solvent and their adsorption to the stationary phase (retention)

  4. the separated components exit the column and are collected for analysis

<ol><li><p>the sample to be purified is placed at the top of the column filled w/ the solid stationary phase</p></li><li><p>solvent is flushed through the column, carrying the mixture components at diff rates</p></li><li><p>components separate based on their solubility in the solvent and their adsorption to the stationary phase (retention)</p></li><li><p>the separated components exit the column and are collected for analysis</p></li></ol><p></p>
59
New cards

give 2 examples of stationary phases used in column chromatography:

  • silica

  • aluminium oxide

<ul><li><p>silica</p></li><li><p>aluminium oxide </p></li></ul><p></p>
60
New cards

how may polarity affect retention in column chromatography?

more polar groups will be retained longer through the column i.e. they will come out later

<p>more polar groups will be retained longer through the column i.e. they will come out later</p>
61
New cards

describe the process of gas chromatography (GC):

  1. liquid sample vaporised in heated chamber

  2. inert gas - mobile phase - transports vaporised sample through chromatographic column containing the stationary phase - powder packed inside long capillary tube by an oil - which interacts differently with each component of the sample

  3. components separated based on how they partition between the mobile gas phase and stationary phase

  4. as they exit the column a detector records the separation producing a chromatogram with distinct peaks for each component

  5. components leave the column at different times - this is the retention time

<ol><li><p>liquid sample vaporised in heated chamber</p></li><li><p>inert gas - mobile phase - transports vaporised sample through chromatographic column containing the stationary phase - powder packed inside long capillary tube by an oil - which interacts differently with each component of the sample</p></li><li><p>components separated based on how they partition between the mobile gas phase and stationary phase</p></li><li><p>as they exit the column a detector records the separation producing a chromatogram with distinct peaks for each component</p></li><li><p>components leave the column at different times - this is the retention time</p></li></ol><p></p>
62
New cards

how can we use retention times to identify substances in GC?

  • position of each peak determined by retention time of each substance

  • area under the peaks = amount of each substance

  • compare retention times to known values (same mobile/stationary phases must be used)

  • (GC may be coupled w/ other spectrometers e.g. mass spec - substances separated out then mass spectrum for each is produced)

<ul><li><p>position of each peak determined by retention time of each substance</p></li><li><p>area under the peaks = amount of each substance</p></li><li><p>compare retention times to known values (same mobile/stationary phases must be used)</p></li><li><p>(GC may be coupled w/ other spectrometers e.g. mass spec - substances separated out then mass spectrum for each is produced)</p></li></ul><p></p>
63
New cards

name a suitable developing agent for the separation of a polypeptide into its constituent AAs - state why the developing agent is needed:

  • ninhydrin

  • AAs are colourless/to make the AAs visible

64
New cards

how are condensation polymers hydrolysed?

conc HCl (any strong acid/alkali) - heat

(MS for polypeptide)

<p><u>conc</u> HCl (any strong acid/alkali) - heat</p><p>(MS for polypeptide)</p>
65
New cards
<p>can you complete this table? </p>

can you complete this table?

yes!

<p>yes!</p>
66
New cards

give the methods of polymer disposal:

  • landfill

  • incineration

  • recycling

67
New cards

give the benefits and drawbacks of disposing of (addition) polymers in landfill:

benefits:

  • useful for disposing of plastics which:

    • are too diff to recycle

    • are too diff to separate from other materials

    • there is not enough plastic to extract to make it economically viable

drawbacks:

  • decomposition of waste in landfill produces methane - greenhouse gas

  • risk of water contamination from waste leaching

  • large amounts of land needed - unsustainable and expensive

68
New cards

give the benefits and drawbacks of incineration as a method of polymer disposal:

benefits:

  • method of disposal if the plastics can’t be recycled

  • E from burning can be used to generate electricity

drawbacks:

  • can release toxic fumes so must be monitored e.g. PVC produces toxic HCl fumes

    • flue gas scrubbers used to neutralise toxic gases produced by firing a base at the flue gases

69
New cards

give the benefits and drawbacks of recycling as a form of polymer disposal:

benefits:

  • cheaper

  • less CO2 produced than incineration

  • reduces reliance on landfill

  • preserves non-renewable raw materials e.g. crude oil

drawbacks:

  • can be contaminated w/ other materials when being recycled

  • diff to recycle due to wide variety of diff plastics

  • diff to remake original plastic from recycled material

  • sorting and process recycling of plastics more expensive than incineration

70
New cards

golf balls recovered from lakes and ponds can be used again even after being in water for several years - explain why these golf balls do not biodegrade (2)

(ignore the MS, say both!)

  • C-C bonds are non polar/strong/not attacked by nucleophiles

  • C-C bonds cannot be hydrolysed

<p>(ignore the MS, say both!)</p><ul><li><p><u>C-C bonds</u> are non polar/strong/not attacked by <strong>nucleophiles</strong></p></li><li><p><u>C-C bonds</u> cannot be hydrolysed</p></li></ul><p></p>
71
New cards

what must each monomer have to make a condensation polymer?

at least 2 functional groups e.g. diols, dicarboxylic acids

72
New cards

give 3 examples of condensation polymers and the general word eqns for their formation:

  • n(dicarboxylic acid + diamine) → polyamide

  • n(dicarboxylic acid.+ diol) → polyester

  • n(amino acid) → polypeptide

73
New cards

give the general eqn for the formation of a polyamide - name the linkage formed:

amide linkage

<p>amide linkage</p>
74
New cards

give 2 examples of polyamides and their uses:

  • Kevlar - used to make bulletproof vests

  • nylon-6,6 - used to make fibres e.g. in ropes/clothing

75
New cards

why are condensation polymers stronger than addition polymers?

  • there are H bonds (as well as VDWs and DPDPs) between C=O, N-H and O-H groups and DPDPs between polarised groups in condensation polymers

  • only VDWs between polyalkenes as the chains contain non-polar bonds

  • H bonds/DPDPs are stronger than VDWs

76
New cards

give the eqn for making Kevlar and name the organic reactants - give 1 feature of Kevlar:

Kevlar has H bonds between polymer chains

<p>Kevlar has H bonds between polymer chains</p>
77
New cards

give the eqn for making nylon-6,6 and name the organic reactants:

knowt flashcard image
78
New cards

suggest an alternative way of making polyamides and give the small molecule produced:

  • acyl chloride + amine

  • small molecule = HCl

<ul><li><p>acyl chloride + amine</p></li><li><p>small molecule = HCl</p></li></ul><p></p>
79
New cards

give the general eqn for the formation of a polyester and name the linkage:

knowt flashcard image
80
New cards

give an example of a polyester, the eqn for making it and the names of the organic products:

Terylene - remember only 1 side of trailing bonds should have an O!

<p>Terylene - remember only 1 side of trailing bonds should have an O!</p>
81
New cards

draw and name the mechanism that occurs between ethanal and acidified KCN:

nucleophilic addition

<p>nucleophilic addition</p>
82
New cards

what is the product of nucleophilic addition w/ acidified KCN?

hydroxynitrile

<p>hydroxynitrile </p>
83
New cards

which compounds can undergo nucleophilic addition?

aldehydes and ketones

84
New cards

why do asymmetrical ketones form racemates during nucleophilic addition, whereas symmetrical ketones do not?

for symmetrical ketones:

  • attack from either side of carbonyl group is still =lly likely as carbonyl is planar

  • but attack from either side would produce the same product as ketone is symmetrical

  • so product is non-chiral and ∴ optically inactive

85
New cards

draw and name the mechanism that occurs between ethanal and acidified NaBH4:

nucleophilic addition

<p>nucleophilic addition</p>
86
New cards

for which reactions does nucleophilic addition w/ NaBH4 occur?

  • reduction of aldehyde to 1o alcohol

  • reduction of ketone to 2o alcohol

87
New cards

give the functional group for an acid anhydride:

knowt flashcard image
88
New cards

give the functional group for an acyl chloride:

knowt flashcard image
89
New cards

give the functional group for an amide:

knowt flashcard image
90
New cards

what is acylation? through which mechanism does it occur?

  • addition of an acyl group

  • occurs through a nucleophilic addition-elimination reaction

<ul><li><p>addition of an acyl group</p></li><li><p>occurs through a nucleophilic addition-elimination reaction </p></li></ul><p></p>
91
New cards

draw the nucleophilic addition-elimination reaction between ethanoyl chloride and water:

knowt flashcard image
92
New cards

draw the nucleophilic addition-elimination reaction between ethanoyl chloride and ethanol:

knowt flashcard image
93
New cards

draw the nucleophilic addition-elimination reaction between ethanoyl chloride and conc ammonia:

knowt flashcard image
94
New cards

draw the nucleophilic addition-elimination reaction between ethanoyl chloride and methylamine (1o amine):

knowt flashcard image
95
New cards

what is an N-substituted amide?

amide where one of the H atoms bonded to the N has been substituted for an alkyl/aryl group

96
New cards

draw the nucleophilic addition-elimination reaction between ethanoic anhydride and ammonia:

<p></p>
97
New cards
<p>fill out the products in this table: </p>

fill out the products in this table:

knowt flashcard image
98
New cards
<p>fill out the products in this table:</p>

fill out the products in this table:

knowt flashcard image
99
New cards

what is optical isomerism? when does it occur?

  • form of stereoisomerism

  • occurs as a result of chirality in molecules

  • limited to molecules w/ a single chiral centre

<ul><li><p>form of stereoisomerism </p></li><li><p>occurs as a result of chirality in molecules</p></li><li><p>limited to molecules w/ a single chiral centre </p></li></ul><p></p>
100
New cards

what is a chiral C?

C with 4 diff groups attached

<p>C with 4 diff groups attached </p>