Iso-profits and their slopes.

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7.4.1 of The Economy 1.0 & The Economy #4

Last updated 4:06 PM on 5/12/26
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6 Terms

1
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How can profit be mathematically formed? Assume that the firm’s cost production function is C(Q).

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2
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How can an iso-profit curve be seen mathematically?

Also seen as:

PQ - C(Q) = k.

And also seen as:

P = AC + k/Q

<p>Also seen as:</p><p>PQ - C(Q) = k. </p><p>And also seen as:</p><p>P = AC + k/Q</p>
3
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What is the formula then for the zero economic iso-profit curve?

-When k=0, then P = AC. Hence, it can be seen as the AC curve.

-Thus, whether the AC is a straight line (costs are constant for all quantities produced) or a curve (marginal cost increases/decreases) determines the shape of the zero-economic iso-profit curve.

4
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<p>Talk more about the k/Q quality</p>

Talk more about the k/Q quality

-The shape of iso-profit curve is also affected by k/Q, though when Q is large, it makes little difference

-Differentiating with respect to Q reveals that it has a negative gradient, so it is downward sloping, and it is accelerating downwards

<p>-The shape of iso-profit curve is also affected by k/Q, though when Q is large, it makes little difference</p><p>-Differentiating with respect to Q reveals that it has a <em>negative </em>gradient, so it is downward sloping, and it is <em>accelerating </em>downwards</p>
5
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Why does the iso-profit curve, when Q is large enough, slope the same as the AC?

-The derivative of k/Q is close to 0, meaning the slope of the iso-profit curve only has the derivative of AC to influence. Thus, it then closely reflects the slope of the AC curve.

6
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How can we prove that the marginal cost must pass through the minimum of the iso-profit curves?

-By showing that MC = AC always has the same sign as the slope of the AC curve

-Differentiating by Q reveals this:

dP/dQ = d/dQ(C(Q)/Q) - k/Q2

-Because the differential of C(Q)/Q = [MC-AC]/Q and k/Q = P - AC:

dP/dQ = (MC-AC)/Q - (P-AC)/Q

Which neatly simplifies to this.

-This equation states that, when the slope reaches it minimum, MC must equal P. Boom.

<p>-By showing that MC = AC always has the same sign as the slope of the AC curve</p><p>-Differentiating by Q reveals this:</p><p>dP/dQ = d/dQ(C(Q)/Q) - k/Q<sup>2</sup></p><p>-Because the differential of C(Q)/Q = [MC-AC]/Q and k/Q = P - AC:</p><p>dP/dQ = (MC-AC)/Q - (P-AC)/Q</p><p>Which neatly simplifies to this. </p><p>-This equation states that, when the slope reaches it minimum, MC must equal P. Boom. </p>