Newton's Laws of Motion

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Flashcards based on lecture notes regarding Newton's First, Second, and Third Laws of Motion, including inertia, mass/force relationships, and specific numerical examples.

Last updated 11:41 PM on 6/17/26
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14 Terms

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Newton's First Law of Motion

A law stating that an object at rest remains at rest and an object in motion remains in motion (in a straight line at a constant speed - no acceleration) unless acted upon by a net force.

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Law of Inertia

Another name often given to Newton's First Law of Motion.

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Inertia

The property of an object that resists changes to its motion; it makes stationary objects difficult to move and moving objects difficult to stop.

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Mass

The physical quantity that determines the amount of inertia an object possesses.

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Newton's Second Law of Motion

A law stating that when a net force acts on an object, it accelerates in the direction of the net force.

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ΣF=ma\Sigma \vec{F} = m\vec{a}

The mathematical equation for Newton's Second Law, where units are Newtons (NN) for force, kilograms (kgkg) for mass, and m/s2m/s^2 for acceleration.

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Direct Relationship in Newton's Second Law

The principle that acceleration varies directly to the net force acting on an object.

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Inverse Relationship in Newton's Second Law

The principle that acceleration varies inversely to the mass of the object.

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Newton's Third Law of Motion

A law stating that for every action force there exists a reaction force that is equal in magnitude but opposite in direction.

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Calculated acceleration (Example 3)

The result when a net force of 4500N4500\,N acts on a 1600kg1600\,kg racecar, yielding an acceleration of 2.8m/s22.8\,m/s^2.

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Mass calculation (Example 4)

Given a force of 3.3N3.3\,N, an initial rest state, and a final speed of 5.5m/s5.5\,m/s over 12.0m12.0\,m, the calculated mass is 2.62kg2.62\,kg.

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Net Force and Acceleration (Example 5)

When a stationary 5.00kg5.00\,kg block has a friction force of 7.00N7.00\,N and an applied force of 6.20N6.20\,N, the net force is 0.80N-0.80\,N and the acceleration is 0.16m/s2-0.16\,m/s^2.

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Distance calculation (Example 6)

The distance an object moves from rest over 5.00s5.00\,s with an adjusted acceleration of 2.25m/s22.25\,m/s^2 is 28.1m28.1\,m.

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Final Speed (Example 7)

The speed of a 25.0kg25.0\,kg object after being pushed by a 17.0N17.0\,N force against 10.0N10.0\,N of friction for 5.0s5.0\,s is 1.4m/s1.4\,m/s.