SRS Unit 1.2 ATAR Physics - Ionising Radiation & Nuclear Reactionc

0.0(0)
Studied by 0 people
call kaiCall Kai
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/45

flashcard set

Earn XP

Description and Tags

WIP - til Decay Series

Last updated 3:53 AM on 4/22/26
Name
Mastery
Learn
Test
Matching
Spaced
Call with Kai

No analytics yet

Send a link to your students to track their progress

46 Terms

1
New cards

Bohr’s Atomic Model

  • The nuclear model where protons and neutrons are contained in a nucleus and electrons are orbiting it in shells

<ul><li><p>The nuclear model where protons and neutrons are contained in a nucleus and electrons are orbiting it in shells</p></li></ul><p></p>
2
New cards

Proton

Charge:

  • + 1.602×10−19 𝐶

  • +1 𝑒

Location:

  • Nucleus

Mass:

  • 1.6726 ×10−27 𝑘𝑔

  • 1.007276 𝑎𝑚𝑢

3
New cards

Neutron

Charge:

  • 0C

  • 0 e

Location:

  • Nucleus

Mass:

  • 1.6749 ×10−27 𝑘𝑔

  • 1.008665 𝑎𝑚𝑢

4
New cards

Electron

Charge:

  • −1.602×10−19 𝐶

  • −1 𝑒

Location:

  • Outside nucleus

Mass:

  • 9.1094 ×10−31 𝑘𝑔

  • 0.000549 𝑎𝑚𝑢

5
New cards

Nucleons

  • A collective term for protons and neutrons found in the nucleus.

6
New cards

Nuclides

  • The range of atomic nuclei associated with a particular atom, which is defined by the atomic number and the various isotopes of that atom as identified by the mass number.

7
New cards

Isotopes

  • Two or more types of atoms that have the same atomic number and position in the periodic table but different number of neutrons.

8
New cards

Atomic Number (Z)

  • The number of protons that defines the element

9
New cards

Atomic Mass Number

  • The total mass of protons (Z) and neutrons (N) of an atom in Atomic Mass Units (amu)

10
New cards

Neutron Number (N)

  • Atomic Mass Number (rounded) - Atomic Number

11
New cards

Electrostatic Force (EF)

  • An attractive and repulsive force between particles caused by their electric charges

  • Like charges repel, opposites attract

  • Also referred to as Coulomb’s force

12
New cards

Strong Nuclear Force (SNF)

  • The “glue” holding protons and electrons together in the nucleus together

  • Exists within quarks, which form protons and neutrons

13
New cards

SNF > EF

  • If the Strong Nuclear Force is stronger than the Electrostatic Force, nuclei will be stable

  • However, if this delicate balance is interfered with, nuclei will become unstable and decay

14
New cards

Stable nuclide

  • A nuclide that will never (or close to never) decay

15
New cards

Unstable nuclide

  • A nuclide that will decay

  • It will keep decaying until the balance of protons and neutrons is stable

16
New cards

Radioactive decay

  • The process by which an unstable atomic nucleus loses energy by radiation and the emission of subatomic particles

17
New cards

Radioisotope

  • A radioactive isotope

18
New cards

Beta Positive/Plus Decay (β+)

  • Occurs when the nucleus has too many protons

  • Therefore the Electrostatic Force overpowers the Strong Nuclear Force

  • The proton decays into a neutron to release excess EF and stabilise the nucleus

  • Due to this, the nucleus emits a positron (anti-electron) known as a Beta Positive Particle along with a neutrino

<ul><li><p>Occurs when the nucleus has too many protons</p></li><li><p>Therefore the Electrostatic Force overpowers the Strong Nuclear Force</p></li><li><p>The proton decays into a neutron to release excess EF and stabilise the nucleus </p></li><li><p>Due to this, the nucleus emits a positron (anti-electron) known as a Beta Positive Particle along with a neutrino</p></li></ul><p></p>
19
New cards

Beta Negative/Minus Decay (β-)

  • Occurs when the nucleus has too many neutrons

  • Therefore the Strong Nuclear Force overpowers the Electrostatic Force

  • The neutron decays into a proton to gain additional EF and stabilise the nucleus

  • Due to this, the nucleus emits an electron known as a Beta Negative Particle along with an anti-neutrino

<ul><li><p>Occurs when the nucleus has too many neutrons</p></li><li><p>Therefore the Strong Nuclear Force overpowers the Electrostatic Force</p></li><li><p>The neutron decays into a proton to gain additional EF and stabilise the nucleus </p></li><li><p>Due to this, the nucleus emits an electron known as a Beta Negative Particle along with an anti-neutrino</p></li></ul><p></p>
20
New cards

Alpha Decay (α)

  • Occurs when the nucleus is too heavy to naturally be stable (every element above Bismuth)

  • The nucleus releases two protons and two neutrons at the same time - an Alpha Particle

  • An Alpha Particle is the same as a Helium-4 nucleus

<ul><li><p>Occurs when the nucleus is too heavy to naturally be stable (every element above Bismuth)</p></li><li><p>The nucleus releases two protons and two neutrons at the same time - an Alpha Particle</p></li><li><p>An Alpha Particle is the same as a Helium-4 nucleus</p></li></ul><p></p>
21
New cards

Gamma Decay (γ)

  • Occurs when nucleus has excess energy but the correct ratio of protons to neutrons

  • The nucleus emits energy Gamma Radiation - gamma waves

<ul><li><p>Occurs when nucleus has excess energy but the correct ratio of protons to neutrons</p></li><li><p>The nucleus emits energy Gamma Radiation - gamma waves</p></li></ul><p></p>
22
New cards

Segre Plot

  • A graph/visualisation of the stability in nuclei showing all known isotopes of each element and their radioactivity/stability

  • y axis is number of neutrons (N), x axis is number of protons (Z)

  • Beyond element 82 (Lead) there are no more stable isotopes

  • The number of radioactive isotopes for each element exceeds the number of stable ones

<ul><li><p>A graph/visualisation of the stability in nuclei showing all known isotopes of each element and their radioactivity/stability</p></li><li><p>y axis is number of neutrons (N), x axis is number of protons (Z)</p></li><li><p>Beyond element 82 (Lead) there are no more stable isotopes</p></li><li><p>The number of radioactive isotopes for each element exceeds the number of stable ones</p></li></ul><p></p>
23
New cards

Penetrating ability

  • How well radiation can pierce through matter

24
New cards

Ionisation ability

  • How well radiation can ionise atoms

  • Ionisation is the process by which an atom loses or gains an electron, thus resulting in a net positive or negative charge

25
New cards

Alpha Particle (α)

Mass:

  • 4.001 506 u

Charge:

  • +2e

Penetrating Ability:

  • Low

Ionisation Ability:

  • High

26
New cards

Beta Positive/Plus Particle (positron) (β+)

Mass:

  • 0.000549 u

Charge:

  • +1e

Penetrating Ability:

  • Medium

Ionisation Ability:

  • Medium

27
New cards

Beta Negative/Minus Particle (electron) (β-)

Mass:

  • 0.000549 u

Charge:

  • -1e

Penetrating Ability:

  • Medium

Ionisation Ability:

  • Medium

28
New cards

Gamma Particle (γ)

  • High energy light/electromagnetic wave

Mass:

  • 0 u

Charge:

  • 0e

Penetrating Ability:

  • High

Ionisation Ability:

  • Low

  • Can only ionise atoms if it strikes an electron directly and knocks it loose

29
New cards

Nuclear Equation formats

  • LHS → RHS

  • Reactants → Products

  • Parent Nucleus → Daughter Nucleus + decay particles + energy

30
New cards

Alpha Decay Equation

PN → DN + α + energy

<p>PN → DN + α + energy</p>
31
New cards

Beta Positive/Plus Decay Equation

PN → DN + β+ + ve + energy

<p>PN → DN + β<sup>+ </sup>+ <em>v</em><sub>e</sub> + energy</p>
32
New cards

Beta Negative/Minus Decay Equation

PN → DN + β- + ve + energy

<p>PN → DN + β<sup>-</sup> + <s>v</s><sub>e</sub> + energy</p>
33
New cards

Gamma Decay Equation

PN* → PN + γ + energy

<p>PN* → PN + γ + energy</p>
34
New cards

Decay Series

  • A graph visualising the different decays an isotope undergoes to achieve stability

  • Each isotope has their own “signature” sequence

  • y-axis: mass number

  • x-axis: atomic number

  • Diagonal line → alpha decay

  • Horizontal line → beta decay

  • Series stops at Lead-206

<ul><li><p>A graph visualising the different decays an isotope undergoes to achieve stability</p></li><li><p>Each isotope has their own “signature” sequence</p></li><li><p>y-axis: mass number</p></li><li><p>x-axis: atomic number </p></li><li><p>Diagonal line → alpha decay</p></li><li><p>Horizontal line → beta decay</p></li><li><p>Series stops at Lead-206</p></li></ul><p></p>
35
New cards

Half-life (t1/2)

  • The time required for a substance to decay to half its initial size

  • Graphically, its trend line is mathematical exponential decay

<ul><li><p>The time required for a substance to decay to half its initial size</p></li><li><p>Graphically, its trend line is mathematical exponential decay</p></li></ul><p></p>
36
New cards

Equation for half-life

N = N0 × (1/2)n

  • N = Final amount of substance / no. of remaining atoms

  • N0 = Initial amount of substance / no. of remaining atoms

  • n is the number of half-lives that have elapsed

  • n = (time elapsed)/(time of half-life) = t/t1/2

<p><em>N = N<sub>0</sub> × </em>(1/2)<em><sup>n</sup></em> </p><ul><li><p><em>N</em> = Final amount of substance / no. of remaining atoms</p></li><li><p><em>N<sub>0</sub></em> = Initial amount of substance / no. of remaining atoms</p></li><li><p><em>n</em> is the number of half-lives that have elapsed</p></li><li><p><em>n</em> = (<em>time elapsed</em>)/(<em>time of half-life</em>) = <em>t/t<sub>1/2</sub></em></p></li></ul><p></p>
37
New cards

Equation for number of half-lives elapsed

n = t/t1/2

  • n = number of half-lives elapsed

  • t = time elapsed

  • t1/2 = time of half-life

<p><em>n = t/t<sub>1/2</sub></em></p><ul><li><p><em>n </em>= number of half-lives elapsed</p></li><li><p><em>t = </em>time elapsed</p></li><li><p><em>t<sub>1/2</sub></em> = time of half-life</p></li></ul><p></p>
38
New cards

Atomic Mass Unit

  • Defined as 1/12 of the mass of a Carbon-12 nucleus

  • 1u = 1.66054 × 10-27kg

39
New cards

Electron volts

  • The preferred units of Energy on the atomic scale

  • Equal to the energy gained by an electron when passing a potential difference of 1 Volt

  • 1eV = 1.602 × 10-19J

  • 1J = 6.242 × 1018eV

  • 1 megaelectron volt is 1,000,000 eV

40
New cards

Equation for Mass-Energy Equivalence

E = mc2

  • E = energy (J or eV)

  • m = mass (kg or u)

  • c = the speed of light (299 792 458 m/s)

  • 1u = 931.6 MeV

41
New cards

Mass Defect

  • Mass of nucleons together < mass of nucleons apart

  • Mass defect (∆m) is usually measured in atomic mass units (u)

  • m = mass of nucleons − total mass of individual nucleons

  • This mass is converted into binding energy

42
New cards

Binding Energy

  • The mass of individual nucleons that is converted in energy to keep them together

  • Binding Energy = ∆m × 931.6

43
New cards

Calculating energy released from Alpha Decay

<p></p>
44
New cards

Calculating energy released from Beta Plus Decay

  • The value of 0.0010972 is twice the mass of an electron and is due to the mass of the positron released by the parent nucleus and the one fewer electron in the daughter isotope

<ul><li><p>The value of 0.0010972 is twice the mass of an electron and is due to the mass of the positron released by the parent nucleus and the one fewer electron in the daughter isotope</p></li></ul><p></p>
45
New cards

Calculating energy released from Beta Minus Decay

knowt flashcard image
46
New cards

Binding Energy Per Nucleon

  • A measurement of stability in the nucleus

  • The higher the value, the more stable the nucleus will be

<ul><li><p>A measurement of stability in the nucleus </p></li><li><p>The higher the value, the more stable the nucleus will be </p></li></ul><p></p>