Coulomb's law

0.0(0)
Studied by 1 person
call kaiCall Kai
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/39

flashcard set

Earn XP

Description and Tags

coulombs law, electrons, atomic radius, ionization, electronegativity, ions,

Last updated 5:49 AM on 3/15/26
Name
Mastery
Learn
Test
Matching
Spaced
Call with Kai

No analytics yet

Send a link to your students to track their progress

40 Terms

1
New cards

Columb’s law

The potential energy of two charged particles depends on their charges ( q1 & q2 ) and on the distance between them

2
New cards

Coulmbs law formula

is given by F = k(q1 * q2) / r²

3
New cards

F stands for

force

4
New cards

Ke stands for

coulombs constant 9×10 to the power of 9 NM squared/ C squared

5
New cards

q1 and q2 stands for

formula charges

6
New cards

r squared stands for

distance between the two charges

7
New cards

1) Alike charges

repel ( + and +, -and - )

8
New cards

2) Opposite charges

attract ( + and - )

9
New cards

3) forces of attraction and/ repulsion

-directly proportional to charge difference

-inversely proptinal to distance between

10
New cards

There are two types of electrons

valence electons and core electrons

11
New cards

valence electrons

e-s occupying the outer energy level

<p>e-s occupying the outer energy level </p>
12
New cards

core electrons

all e-s not occupying the outer energy level

<p>all e-s not occupying the outer energy level </p>
13
New cards

core electrons repel

valence electrons ( outer electrons)

14
New cards

more core electrons cause

-increase replusive forces on valence e-s

-increase shielding of + charge nucleus

15
New cards

The electron on the outer shell ( valence electrons) wont be as strong because

the first orbital of the electrons would repel the one above it

16
New cards

Atomic Raduis

half the distance between two chemically bonded homonucler atoms ( atoms of the same element)

<p>half the distance between two chemically bonded homonucler atoms ( atoms of the same element) </p>
17
New cards

On the PE the atomic radius

-decrease from left to right across a period

-same number of core electrons ( repulsive force stays constant on valence electrons )

18
New cards

If # of protons increases

atrractive forces increase

19
New cards

in the PE increases from top to bottom down a group

-inc. number of electrons ( repulsive force inc. on valence e-s)

-more energy levels

20
New cards

Ionization Energy

-energy needed to remove e-s

-increas fro left to right across a period

-decreases from top to bottom down a group

21
New cards

Ion

atom ( group of atoms that have gained/ lost e-s

22
New cards

Increas from left to right across a period

  • same number of core e-s (repulsive force stays constant on valence e-)

  • number of protons increase ( attractive forces increases)

23
New cards

Decreases from top to bottom down a groups

  • inc. remember of core e-s ( repulsive force inc. )

  • more energy levels

24
New cards

Electron negativity

atrractiveness to an e- in a bond

  • increases from left to right across a period

  • decrease from top to bottom down a group

25
New cards

Every single element in row

18 has 0 electronegativity

26
New cards

Ions

an atom that has an electric charge

27
New cards

ions can not lose of

gain protons

28
New cards

ions valence e-s can be

lost or gained Ca

29
New cards

Cations ( Cat-ion)

  • lost e-

  • metals from cations

  • postively charged ion

30
New cards

metals tend to lose

e- ( oxidize)

31
New cards

non metals tend

to gain e- ( reduce))

32
New cards

Anions ( an-ion )

  • negativly charged ion

  • gained electron

    • non-metals from an-ions

33
New cards

metals gain/lose electrons to become a noble gases

in order to gain a valence electron

34
New cards

deterine charge

charge = # protons- # electrons

35
New cards

Atoms want a full valence shell

in other words a noble gas configuration

36
New cards

neon gases do not form ions

because already have a full valence shell

37
New cards

electron configuration can b determined

by the location of an element on the PT

38
New cards

period #

represents highest occupied EL ( for representive element )

39
New cards

block

reprsents last occupied sublevels ( S, p, d, f)

40
New cards

group

reresent number of e in the valence shell