3.1.1 - atomic structure

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Last updated 7:25 PM on 4/29/26
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67 Terms

1
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relative charges of protons, neutrons and electrons

  • proton = +1

  • neutron = 0 (neutral)

  • electron = -1

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relative masses of protons, neutrons and electrons

  • proton = 1

  • neutron = 1

  • electron = 1/1840 or effectively 0

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what are isotopes

atoms with the same number of protons, but different numbers of neutrons

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  • why do isotopes have similar chemical properties

  • why do they have slightly varying physical properties

  • they have the same electron configuration

  • they have different masses

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can an ion be an isotope

Yes, an atom can be an isotope and an ion simultaneously. For instance, a specific isotope of chlorine, like Chlorine-37, can lose or gain electrons to form an ion, such as the chloride ion (Cl⁻).

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what does a time of flight (TOF) mass spectrometer measure (2)

  • how heavy the different ions formed by a sample are (this is called m/z, where m = Ar of the ion and z = charge on the ion)

  • how much of a particular ion there is (i.e. relative abundance)

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because it measures mass of isotopes and abundance of isotopes, this can be used to find the r________ a_______ m____ and therefore identify the e________.

because it measures mass of isotopes and abundance of isotopes, this can be used to find the relative atomic mass (Ar) and therefore identify the element.

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in substances made of molecules, a mass spectrometer can help us find the r_________ m____________ m____.

relative molecular mass

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what happens in TOFMS (3)

  • particles of the substance are ionised to form 1+ ions

  • these = accelerated so they all have the same Ek

  • time taken to travel a fixed distance = used to find mass of each ion in the sample 

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name the 5 steps in a TOFMS

  1. ionisation

  2. acceleration

  3. ion drift

  4. ion detection

  5. data analysis

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diagram of the TOF mass spectrometer

knowt flashcard image
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STAGE 1: IONISATION

  • what are the 2 ways the sample can be ionised

  1. electron impact

  2. electrospray ionisation

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STAGE 1: IONISATION

in electron impact, sample being ionised is v__________. then, high energy e-s are f______ at it. this usually knocks off o___ e________ from each particle, forming a ___ ion.

 

in electron impact, sample being ionised is vaporised. then, high energy e-s are fired at it. this usually knocks off 1 electron from each particle, forming a 1+ ion.

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STAGE 1: IONISATION

general eq. w/ state symbols to show ionisation of an atom

X (g) —→ X+(g) + e-

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STAGE 1: IONISATION

what fires the high energy electrons

an electron gun (a hot wire filament w/ a current running through it that emits electrons)

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STAGE 1: IONISATION

where are the 1+ ions then attracted towards

  • a negative electric plate

  • where they are accelerated

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STAGE 1: IONISATION

what elements and substances is electron impact used for

ones with a low Mr

electron impact is also used when the substance is an ELEMENT, not a molecule

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STAGE 1: IONISATION

  • when molecules are ionised with electron impact, what is the 1+ ion formed known as

  • give an example equation for this, w/ state symbols, for methane

  • a molecular ion

  • CH₄(g) → CH₄⁺(g) + e⁻

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STAGE 1: IONISATION

what happens in electronspray ionisation

(this is a perf mark scheme answer)

sample dissolved into a volatile solvent

then injected through a fine hypodermic needle at high voltage

(this gives a fine mist (aerosol))

sample gains a proton / H+

(next few flashcards are adding info to this, but this is pretty much all you need)

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STAGE 1: IONISATION

what is the tip of the needle attached to

the + terminal of a high-voltage power supply

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STAGE 1: IONISATION

how are the particles ionised

  • by gaining a proton (e.g. a H+ ion which is just 1 proton) from the solvent as they leave the needle

  • this produces XH+ ions (ions w/ a single positive charge and a mass of Mr + 1)

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STAGE 1: IONISATION

general equation for electronspray ionisation w/ state symbols

X(g) +  H —→ XH+ (g)

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STAGE 1: IONISATION

what happens to the solvent as the XH+ ions are attracted towards a negative plate (where they are accelerated)

it evaporates away

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STAGE 1: IONISATION

  • what substances is electrospray ionisation used for

  • why is this

  • ones with a high relative formula mass (including many biological molecules, e.g. proteins)

  • so the molecules do not fragment

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STAGE 2: ACCELERATION

  • the positive ions are accelerated using a…

  • why?

  • electric field (there is an attraction between the + charged ions and the - charged plates)

  • so that they all have the same Ek

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STAGE 2: ACCELERATION

you’ll need to use the kinetic energy equation. give this and the units used.

(you need to know how to rearrange this too!)

Ek = 1/2mv²

Ek in J, mass in kg, velocity in m s-1

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STAGE 2: ACCELERATION

given that all the particles have the same Ek, the velocity of each particle depends on its…

mass

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STAGE 2: ACCELERATION

l________ particles have a f________ v_________, and h_________ p___________ have a s________ v__________.

lighter particles have a faster velocity, and heavier particles have a slower velocity. (think about the equation)

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STAGE 3: FLIGHT TUBE

the positive ions travel through a h____ in the n__________ c________ p______ into a t_____.

the positive ions travel through a hole in the negatively charged plate into a tube.

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STAGE 3: FLIGHT TUBE

what does the TOF of each particle through this flight tube depend on

  • velocity of particle

  • (which in turn depends on its mass)

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STAGE 3: FLIGHT TUBE

to find time of flight, we need what 2 equations?

kinetic energy eq (Ek = 1/2mv2) and distance speed time eq (d = v x t, where d = metres, v = m s-1, and time = seconds)

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STAGE 3: FLIGHT TUBE

lighter ions t______ f________ and reach detector in l____ t_____ than the h_________ p__________ that m_____ s_________ and t____ l__________ to reach detector.

lighter ions travel faster and reach detector in less time than the heavier particles that move slower and take longer to reach detector.

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STAGE 4: DETECTION

  • what happens when the positive ions hit the detector plate

  • what does this generate

 

  • they are discharged (by gaining electrons from plate)

  • a movement of electrons, and hence an electric current that is measured

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STAGE 4: DETECTION

what does the size of the current give a measure of

no. of ions hitting the plate (and therefore abundance)

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STAGE 5: DATA ANALYSIS

a computer uses the data to produce a…

mass spectrum

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what 2 things does this show

  1. mass to charge (m/z) ratio

  2. abundance of each ion that reaches the detector

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since all ions produced by electrospray ionisation and most ions produced by electron impact = have a 1+ charge, what does this mean the m/z effectively is?

the mass of each ion (y / 1 = y)

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formula for relative atomic mass (Ar)

Ar = (mass no. of iso. 1 x relative abundance of iso. 1) + (mass no. of iso. 2 x relative abundance of iso. 2) / combined abundance of all isotopes (might be 100, might not be!)

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(the values in the Ar formula can be found on the mass spectrum. remember, don’t divide the percentages by 100!)

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how to do a TOF calculation for 2 isotope ions traveling down the same flight tube (look in notes for examples)

the ions will be accelerated to the same kinetic energy. so Ek for one ion = Ek for another ion. then set up up eqs. with the substituted values to be equal to each other (1/2 mv2 = ½ mv2). cancel out common terms on both sides (you don’t need to find masses on both sides separately). then rearrange and solve

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  • energy levels are divided into…

  • sub-levels consist of a set number of…

  • orbitals are a region of space that can hold up to…

  • you can’t say w____ an e- is in an orbital and where it’s going n___

  • sub-levels

  • orbitals

  • 2 e-

  • you can’t say where an e- is in an orbital and where it’s going next

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  • how many sub-levels are there?

  • give the names of these

  • 3

  • s, p and d

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how many orbitals does each sub-level hold

  • s = 1

  • p = 3

  • d = 5

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therefore, how many e- are in each sub-level

  • s = 2

  • p = 6

  • d = 10

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give the order of sub-levels for e- configs.

1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s…

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here is a diagram of e- configs. in boxes.

knowt flashcard image
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  • in this, what is an e-?

  • what is an orbital?

  • what is a sub-level?

  • what is an energy-level?

  • one of the arrows in a box (called a single-headed arrow, they look more like the data sign than in this diagram)

  • a box

  • a row

  • a group of sub-levels (e.g. the rows 2s and 2p make up the 2nd energy level)

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in the e- config., what do you write next to each of the sub-levels?

how many e- are in that sub-level (amnt. of orbitals x2)

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REMEMBER: when filling up the boxes, put one arrow in each box FIRST and then go back and fill them so they each have 2.

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how do you write simplified versions of e- configs.?

find the total number of e- in your config., then find a noble gas with the highest possible atomic number that could fit into that. then write the noble gas symbol in square brackets, and if there are any sub-levels left, write those afterwards too.

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  • for this diagram, give the e- config

  • then give the simplified e- config

  • then name what element this is

  • 1s2 2s2 2p6 3s2 3p6 4s1

  • [Ar] 4s1

  • potassium (K) because atomic number (Z) = 19

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  • elements in the periodic table are in different…

  • what are these blocks called?

  • where is each block on the periodic table?

  • blocks

  • s, p, d or f block

  • (see photo)

<ul><li><p>blocks</p></li><li><p>s, p, d or f block</p></li><li><p>(see photo)</p></li></ul><p></p>
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in the s-block (according to their e- configs.), what do atoms have in common in terms of their outermost e-?

the outermost e- are in an s sub-level

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in the p-block (according to their e- configs.), what do atoms have in common in terms of their outermost e-?

the outermost e- are in a p sub-level

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in the d-block (according to their e- configs.), what do atoms have in common in terms of their outermost e-?

the final e- enters a d-orbital (research this)

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how would you change the e- config. of an atom to be the e- config. of an ion?

add or subtract e- (as an ion is an atom that has lost or gained e-)

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there’s a catch for d-block elements, though. with d-block elements, it’s the ___ electrons which are lost f____.

with d-block elements, it’s the 4s electrons which are lost first (even though the 4s orbital is filled before the 3d orbital during electron configuration).

e.g. e- config. for Fe atom (Z = 26) → [Ar] 4s² 3d⁶

then e- config. for Fe²⁺ ion = [Ar] 3d⁶

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COVER IONISATION ENERGIES

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what 3 factors affect IEs

  • distance between the nucleus and the e- being removed

  • shielding (repulsion) by e-s in inner shells between nucleus and outer e-s

  • nuclear charge

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1st ionisation energy def

energy required to remove one mole of e-s from one mole of gaseous atoms

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if first IE is low

electron is lost more easily

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1st, 2nd, 3rd IE

Na (g) —→ Na+ (g) + e- (this ion is formed after the 1st IE has been measured)

Na+ (g) —→ Na2+ (g) + e-

Na2+ (g) —→ Na3+ (g) + e-

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explaining significant jumps in ionisation energies (ENERGY LEVELS AND THEIR DISTANCE FROM THE NUCLEUS)

  • (number of, e.g. 1st) e- is removed from the (number of, e.g. 3rd) energy level / (name of, e.g. 3s) sub-level

  • which is further / closer to the nucleus

  • more / less shielded by inner shells of e-s

  • and therefore more / less tightly held

  • than the (number of, e.g. 2nd) e-

  • which is removed from the (number of, e.g. 2nd) energy level / (name of, e.g. 2p) sub-level

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general trend in 1st IEs going across period 3 (INCREASING NUCLEAR CHARGE, BUT SAME SHIELDING)

as atomic no. increases —→ first IE of period 3 elements also increases

  • bc nuclear charge increases

  • outer e- has a stronger force of attraction to the nucleus

  • more and more energy is required to remove it

  • even though there is little change between distance between outer e- and nucleus and amount of shielding between them

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what are always (?) the anomalies in this trend

group 2-3 and group 5-6 (3 and 6 are lower)

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why is this (SUB LEVELS AND DISTANCE)

  • outer e- in Al is lost from the 3p sub level

  • this is further away from the nucleus

  • less shielded by inner shells of e-s

  • so the outer e- is less attracted to the nucleus than the outer e- of Mg 

  • which is removed from the 3s sub-level

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why is the 1st IE of S (grp 6) lower than P (grp 5) (ORBITALS)

  • in S, 2e-s are in 3p orbital

  • these repel each other

  • takes less energy to remove one of the electrons from this pair than it does to remove the 1st e- of P

  • where all the 3p orbitals are singly occupied