Geometry Semester 2 Final

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Last updated 4:14 PM on 5/22/26
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41 Terms

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a² +b² = c²

Right Triangle

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a² + b² > c²

Acute Triangle

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a² + b² < c²

Obtuse Triangle

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Whats the legs in a 45 - 45 - 90 degree special right triangle

x

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Whats the hypotenuse in a 45 - 45 - 90 degree special right triangle

x square root of 2

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Whats the hypotenuse in a 30 - 60 - 90 degree special right triangle

2x

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Whats the smallest leg in a 30 - 60 - 90 degree special right triangle

x

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Whats the longest leg in a 30 - 60 - 90 degree special right triangle

x square root of 3

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Trigonometry

Sin, Cos, and Tan

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Sin

Opposite/Hypotenuse

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Cos

Adjacent/Hypotenuse

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Tan

Opposite/Adjacent

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Law of Cos

a² = b² + c² - 2 x b x c x cos A

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Law of Sins

SinA / a = SinB / b

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Perpendicular Bisector

Intersects at the Circumcenter

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What does a Perpendicular Bisector do?

Makes 90 degrees, cuts line segment in 2 equal parts

<p>Makes 90 degrees, cuts line segment in 2 equal parts</p>
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Angle Bisector

Intersects at the Incenter

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What does a Angle Bisector do?

Cuts angles in half

<p>Cuts angles in half</p>
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Medians

Intersects at the Centroid

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What does a Median do?

Line segment that joins a vertex of a triangle to the midpoint of the opposite side

<p>Line segment that joins a vertex of a triangle to the midpoint of the opposite side</p>
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Altitude

Intersects at the Orthocenter

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What does a Altitude do?

Line segment joining a vertex of a triangle to the opposite side so it’s perpendicular to that side

<p>Line segment joining a vertex of a triangle to the opposite side so it’s perpendicular to that side</p>
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Area of a triangle/Rhombus/Kite

A = L x W /2

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Area of Rectangle/Square/Parallelogram

A = L x W

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Area of a Trapezoid

A = (b1 + b2 /2) x H

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Area of a circle

A = Pi x r²

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Area of a semicircle

A = Pi r² /2

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Sector of a circle

(x degrees/360 degrees) x Pi r²

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Area of a Regular Polygon

A = Pa /2

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Surface Are of a Prism

SA = 2Ab + PH

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Surface Are of a Rectangular Prism

SA = 2 (L x W + L x H + W x H)

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Surface Area of a Cylinder

SA = 2Pi x r² + 2Pi x r x H

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Surface Area of a Pyramid

SA = l x P /2 + Ab

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Surface Area of a Cone

SA = Pi x r x l + Pi x r²

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Surface Area of a Hemisphere

SA = 3 x Pi x r²

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Surface Area of a Sphere

SA = 4 x Pi x r²

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Volume of Prisms/Cylinder

Ab x H

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Volume of Pyramid/Cone

Ab /3 x H

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Volume of a Sphere

4/3 Pi x r³

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Volume of a Hemisphere

2/3 Pi x r³