Linear Algebra: Vector Spaces, Transformations, and Matrices

0.0(0)
Studied by 0 people
call kaiCall Kai
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
Card Sorting

1/25

encourage image

There's no tags or description

Looks like no tags are added yet.

Last updated 4:06 AM on 4/19/26
Name
Mastery
Learn
Test
Matching
Spaced
Call with Kai

No analytics yet

Send a link to your students to track their progress

26 Terms

1
New cards

Vector Space

A set V with vector addition and scalar multiplication satisfying closure, associativity, commutativity, identity, inverses, and distributive properties.

2
New cards

Subspace

A subset W of V such that 0∈W, closed under addition and scalar multiplication.

3
New cards

Linear Transformation

A map T:V→W satisfying T(x+y)=T(x)+T(y) and T(kx)=kT(x).

4
New cards

Source & Target

For T:V→W, V is the source (domain), W is the target (codomain).

5
New cards

Standard Matrix

Matrix A where Ax=T(x) for all x in R^n.

6
New cards

Transpose

AT has entries (i,j) = (j,i) of A.

7
New cards

Symmetric Matrix

A matrix where A^T = A.

8
New cards

Skew-Symmetric Matrix

A matrix where A^T = -A.

9
New cards

Diagonal Matrix

A(i,j)=0 for i≠j.

10
New cards

Upper Triangular Matrix

A(i,j)=0 for i>j.

11
New cards

Lower Triangular Matrix

A(i,j)=0 for i

12
New cards

Injective

f(x)=f(x') implies x=x'.

13
New cards

Surjective

For all y in Y, ∃x in X s.t. f(x)=y.

14
New cards

Bijective

f is both injective and surjective.

15
New cards

Isomorphism

A bijective linear transformation between vector spaces.

16
New cards

Inverse Mapping

For bijective f:X→Y, f⁻¹:Y→X satisfies f∘f⁻¹=I and f⁻¹∘f=I.

17
New cards

Invertible Transformation

∃S s.t. S(T(v))=v and T(S(w))=w.

18
New cards

Invertible Matrix

A has inverse A⁻¹ satisfying AA⁻¹=A⁻¹A=I.

19
New cards

Kernel

ker(T)={v∈V | T(v)=0}.

20
New cards

Image

im(T)={T(v)|v∈V}.

21
New cards

Linear Combination

c₁v₁+...+cₙvₙ for scalars cᵢ.

22
New cards

Span

All linear combinations of a set of vectors.

23
New cards

Linear Relation

Equation c₁v₁+...+cₙvₙ=0.

24
New cards

Linearly Dependent

∃nonzero cᵢ such that Σcᵢvᵢ=0.

25
New cards

Linearly Independent

Σcᵢvᵢ=0 implies all cᵢ=0.

26
New cards

Basis

Linearly independent set that spans V.