Hardy-Weinberg Equilibrium & Allele Frequencies

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Last updated 3:05 AM on 4/28/26
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30 Terms

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Allele Frequency

Refers to how frequently a particular allele is detected (or observed) in a population

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Calculating Allele Frequency: Two Methods

Assumptions:

  • We are dealing with a single locus in a large and random mating population

  • We are dealing with diploid species

  • Can calculate allele frequency by counting or proportions

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Calculating Allele Frequency by Counting

Simply add the number of alleles in each genotype

  • Ex: in the A1A1 genotype, there’s 78 individuals, so the count of the A1 allele in that genotype is 78 + 78 = 156

<p>Simply add the number of alleles in each genotype</p><ul><li><p>Ex: in the A1A1 genotype, there’s 78 individuals, so the count of the A1 allele in that genotype is 78 + 78 = 156</p></li></ul><p></p>
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Notations for Allele Frequency

In the context of genotypes and allele frequency: the dominant allele is the most common allele in that population

  • Most common allele frequency is p

    • In this case, A1

  • Minor allele frequency (MAF) is q

    • In this case, A2

Finding frequency (see image):

  • f(A1) = 210/300 = 0.7 (this is p)

  • f(A2) = 90/300 = 0.3 (this is q)

<p>In the context of genotypes and allele frequency: the dominant allele is the most common allele in that population</p><ul><li><p>Most common allele frequency is p </p><ul><li><p>In this case, A1</p></li></ul></li><li><p>Minor allele frequency (MAF) is q</p><ul><li><p>In this case, A2</p></li></ul></li></ul><p>Finding frequency (see image):</p><ul><li><p>f(A1) = 210/300 = 0.7 (this is p)</p></li><li><p>f(A2) = 90/300 = 0.3 (this is q)</p></li></ul><p></p>
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Calculating Allele Frequencies by Proportion

Genotype frequencies: P, H, and Q

  • P is the frequency of homozygous A1 (A1A1)

  • Q is the frequency of homozygous A2 (A2A2)

  • H is the frequency of heterozygous genotype (A1A2)

When calculating, simply divide the number of individuals of that genotype out of the total number of individuals

  • Ex: P = f(A1A1) = 78/300 = 0.52

To find the frequency of A1 (p) or A2 (q), you use:

  • p = P + ½ H

  • q = Q + ½ H

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Rules & Assumptions for Calculating Allele Frequencies

  • p = P + ½ H

  • q = Q + ½ H

  • P + H + Q = 1

    • P = 1 - (H + Q)

    • Q = 1 - (H + P)

  • p + q = 1

    • p = 1 - q

    • q = 1 - p

  • Assumptions: large number and random mating (AKA hard-weinberg)

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Hardy-Weinberg Equilibrium

Occurs in a large and random mating population in the absence of migration, mutation, and selection

  • Allele frequencies and genotypic frequencies remain constant

  • Genotypic frequencies are determined by allele frequencies

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Comparing Frequencies Between Generations

If you compare the genotypic and allelic frequencies in g0 and g1 and they are not constant, that means the g0 population is not in HWE

  • Only one generation of random mating is required for g0 population to reach HWE

<p>If you compare the genotypic and allelic frequencies in g<sub>0</sub> and g<sub>1</sub> and they are not constant, that means the g<sub>0</sub> population is not in HWE</p><ul><li><p>Only one generation of random mating is required for g<sub>0</sub> population to reach HWE</p></li></ul><p></p>
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<p>Estimating Allele Frequencies Using Recessive Condition Genotypes</p>

Estimating Allele Frequencies Using Recessive Condition Genotypes

ONLY use f(bb) to estimate f(b) if f(Bb) is not available. Since we’re ignoring the contribution of heterozygotes to the q calculation, we’re assuming the population is in HWE

  • P = p2

  • H = 2pq

  • Q = q2

We know there’s 18 recessive individuals (bb), so we can find Q

  • Q = f(bb) → 18/200 = 0.09

  • If Q = q2, then take the square root of Q (AKA q2) to get q: √0.09 = 0.3

  • Now we can find p: 1 - q = p → 1 - 0.3 = 0.7

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Example: Est. Allele Frequencies Using Recessive Condition Genotypes

If you are told 6.0% of the population suffers from a recessive condition, what is the frequency of the dominant allele (rounded to three decimal places)? What is the assumption to calculate the recessive allele frequency?

  • f(aa) = 0.06

  • Assume HWE

  • q = √Q = √q2 → √0.06 = 0.24

  • p = 1 - 0.24 = 0.76

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Genotype Frequency in the Next Generation

  • f(BB) = p2

  • f(Bb) = 2pq

    • This is the carrier

  • f(bb) = q2

    • The percentage (frequency) of the individual progeny (the next generation of individuals) showing the genetic condition

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<p>Properties of Equilibrium Populations</p>

Properties of Equilibrium Populations

  1. Frequency of heterozygote: H = 2pq

  • The biggest H (Hmax) can be is 0.5

  1. H = 2√PQ or H/√PQ = 2

  • Provides a quick test for determine HWE without needing to use allele frequencies

  • If it is equal to 2, then the population is in HWE

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Detection of Carriers

Carriers are individuals of any species that carries a single allele of a genetic variant (i.e. heterozygote) that is associated with a specific genetic disorder. Can detect carriers by:

  • DNA Testing Technology

    • SNP chip that tests for several genetic conditions or disorders

    • Relatively cheap and provides lots of services

  • Test mating

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Use of HWE in Detection of Carriers

Example: we have a locus controlling coat color with genotypes: BB, Bb, and bb

  • What’s the probability of being a carrier? (Bb)

  • P(Bb) = the probability of being carrier or having a red calf

  • Level of confidence: there is an X% chance that we’d detect the bull is a carrier

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<p>Use of HWE in Detection of Carriers: Test Mating</p>

Use of HWE in Detection of Carriers: Test Mating

P(detect Bb) = 1 - P(detect Bb after n)

  • General rule: P(detect Bb after n) = 1 - [1*f(BB) + ¾ f(Bb) + ½ f(bb)]n

  • When n is the number of progeny

  • The 1, ¾ and ½ represent the respective probability of not seeing a red calf

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Example: Detection of Carriers

P(detect Bb after n) = 1 - [1*f(BB) + ¾ f(Bb) + ½ f(bb)]n

  • If all 1000 cows are BB, f(BB) = 1

    • Level of confidence = P(detect Bb) → 1-11000 = 1 - 1 = 0

    • 100% of the cows will be black

  • If mated to 10 cows, ½ are Bb and ½ are bb

    • P(detect Bb) = 1 - [ ¾ (½) + ½(½)]10 = 0.9909 or 99%

      • We’re 99% confident that a cow is not a carrier

    • We know none of these cows are BB, so we don’t include that factor in the equation

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Application of HWE

Genotypes Quality Control (QC) for genomic studies

  • If genotypes aren’t in HWE, they’re excluded before being used in further analyses as they’re considered genotyping errors

Assumption: loci not in HWE can be lethal or causing disease

  • Use HWE for deception of lethal alleles is hard because of the need to use a large number of individuals to detect rare variants and standard QC eliminates these genotypes

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HWE in Testings

  • Parentage testing (humane + livestock)

  • Forensics (wildlife + crime)

    • In these test panels, the markers (SNPs) should be in HWE and segregate in most of the breeds

    • These tests are very sensitive to genotyping errors

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HWE in the Real World

Most populations in the real world may not be in HWE, but HWE serves as a baseline model for studying the effects of many evolutionary and demographic factors on the genetic structure of the population

  • I.e. the departure from HWE

  • Genetic and genomic improvement have been done using selection or crossbreeding, so if we maintain all conditions for HWE, no genetic improvement would be achieved

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Conditions of HWE

  • A random mating population

  • A large population

  • No migration

  • No mutation

  • No selection

  • If any of these aren’t met, HWE is violated

    • Ex: no random mating would be assortative mating and autosomal and sex linkage

    • Ex: migration would be crossing/importing and exporting semen and embryos

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Random Mating

  • A mating system in which all matings are equally likely

  • To achieve HWE from a non-equilibrium population, one generation of random mating is required

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<p>Violating Random Mating: Positive Assortative Mating</p>

Violating Random Mating: Positive Assortative Mating

  • Individuals with similar phenotypes or genotypes mating with each other

  • Mating like to like

    • Based on pedigree likeness or individual likeness such as performance success, disposition, body shape, etc.

  • Leads to more homozygotes

  • Ex: purebreeding

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Violating Random Mating: Negative Assortative Mating

  • Unlike mates to unlike (i.e. different genotypes or phenotypes mating together)

  • Leads to more heterozygotes

  • Ex: crossbreeding

(+) or (-): change in genotype frequency but not allele frequency

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Recap of Assortative Matings

Assortative matings with no selection lead to change in genotype frequencies not allele frequencies (no removal; we aren’t doing selection)

  • (+) assortative matings: more to homozygotes like purebreeding

  • (-) assortative matings: more to heterozygotes like crossbreeding

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Factors Affecting HWE: Selection

Goal of selection in a breeding program:

  • To remove deleterious alleles

  • To increase frequencies of favorable genes (alleles) in a population

  • Selection for or against a particular allele changes in both genotypic and allele frequencies

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Selection Under Heterozygote Advantage

There’s an overdominance for fitness (i.e. selection favors Aa genotype

  • For any initial allele frequency, the population converges on a max heterozygosity (H = 0.5)

<p>There’s an overdominance for fitness (i.e. selection favors Aa genotype</p><ul><li><p>For any initial allele frequency, the population converges on a max heterozygosity (H = 0.5)</p></li></ul><p></p>
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Selection Under Heterozygote Disadvantage

There’s an underdominance for fitness (i.e. selection acts against Aa genotype)

  • Starting p < 0.5 pops head toward loss

  • Starting p > 0.5 pops head towards fixation

  • Populations converge at minimum heterozygosity

<p>There’s an underdominance for fitness (i.e. selection acts against Aa genotype)</p><ul><li><p>Starting p &lt; 0.5 pops head toward loss</p></li><li><p>Starting p &gt; 0.5 pops head towards fixation</p></li><li><p>Populations converge at minimum heterozygosity </p></li></ul><p></p>
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Selection Against a Recessive Homozygote

Selections acts against the aa genotype

  • Frequency of dominant allele (A) rapidly approaches fixation from any initial allele frequency

<p>Selections acts against the aa genotype</p><ul><li><p>Frequency of dominant allele (A) rapidly approaches fixation from any initial allele frequency</p></li></ul><p></p>
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Factors Affecting HWE: Migration

 

Migration is movement of alleles from one population to another

  • Animals don’t necessarily need to move but if their genetic materials moved using reproductive technology (e.g. frozen embryos, semen)

  • If allele frequencies are the same between the two populations, then the migration has no effect on allele frequency in the new population

  • If allele frequencies are different, then migration alter the allele frequency for the new pop.

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Factors Affecting HWE: Small Population

  • Sampling from a small population will lead to random genetic drift

  • Genetic drift is the random change in allele frequencies due to sampling a finite number of parents