7 - Basic Science OT

Total Resistance in Parallel

Number of Lamps given Lamp Power, Voltage, and Amperes

N_lamp = Po / P

Lamp Power given Voltage and Ampere

Po = V x I

Voltage Equation

V = IR

Total Resistance in Parallel

Total Resistance in Series

Rt = R1 + R2 + R3 + … Rx

Voltage Equation

V = IR

Power given Voltage and Current

P = VI

Heat Equation and Power

Q = P = m Cp T

Energy Transfer Rate

Q/A = (k ΔT) / x

Temp Difference in F to C

ΔT_F = 9/5 ΔT_C

Temp Difference in C to F

ΔT_C = 5/9 ΔT_F

Energy Transfer Rate

Q/A = (k ΔT) / x

Enthalpy given internal energy, pressure, and volume

h = u + PV

Enthalpy given internal energy, pressure, and volume: with mass

H = U + PV ; U = U X mass

14.7 PSI = ? KPA

14.7 PSI = 101.325 KPA

101.325 KPA = ? PSI

101.325 KPA = 14.7 PSI

1 kcal = ? kJ

1 kcal = 4.187 kJ

Change in Length given Linear Expansion

ΔL = α x L x ΔT → Lf - L = α x L x ΔT

Water Heat Removed from +Temp to - Temp: Qtotal 15 C to -3 C

Qtotal = Q 15→0 + Q 0 + Q 0→-3

Water Heat Removed from +Temp to - Temp: Q 15→0

Q 15→0 = m Cp T

Water Heat Removed from +Temp to - Temp: Q 0

Q 0 = m (LHF) ; LHF = 334 kJ/kg ; LHevap = 2257 kJ/kg

Water Heat Removed from +Temp to - Temp: Q 0→-3

Q 0→-3 = m Cp T ; 2.093 kJ/kg-K

Cp of Ice

Cp ice = 2.093 kJ/kg-K

Force Formula considering Pressure and Area

F = P x A

Pressure formula

P = p x g x h

Total Salt Percent for Different Salt Percents with Different Liters

Liter1(Salt1) + Liter2(Salt2) + Liter3(Salt3) = (Liter1 + Liter2 + Liter3)(Total Salt)

Heat Formula

Q = m Cp T

Work of temp rising

Wk = Q = m Cp T

Mass given density and volume

m = p V

KE

KE = ½ mV² = 1/2 m (V1² - V2²)

Heat Formula for Air

Q = m Cv T

Mass of Air given Pressure and Volume

m = PV / RT

CV of Air

Cv = 0.718 kJ/kg-K

Pressure of Water with manometer

P = p g h = p_helium x g x h_mano

Flow Rate given Diameter and Mass Flow

Q = V A

1 ft³ = ? gal

1 ft³ = 7.48 gal