Factoring Polynomials and Quadratic Expressions

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This set of flashcards covers polynomial factoring techniques including GCF, grouping, trinomials, perfect square identities, and the difference of squares and cubes as presented in the lecture notes.

Last updated 8:05 AM on 5/8/26
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9 Terms

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GCF (Greatest Common Factor)

The initial step in factoring, as seen in the expression 2x2+20x+482x^2 + 20x + 48 where 22 is pulled out to leave 2(x2+10x+24)2(x^2 + 10x + 24), which then factors to 2(x+6)(x+4)2(x+6)(x+4).

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Factoring by Grouping

A technique used for polynomials with four terms, such as 2x36x2+5x152x^3 - 6x^2 + 5x - 15, which is grouped into 2x2(x3)+5(x3)2x^2(x-3) + 5(x-3) to result in (x3)(2x2+5)(x-3)(2x^2 + 5).

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Trinomial Factoring (x2+7x+12x^2 + 7x + 12)

A quadratic expression that simplifies into the product of two binomials: (x+3)(x+4)(x+3)(x+4).

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Coefficient Multiply Method

A process for factoring trinomials where the leading coefficient is multiplied by the constant (e.g., 15×6=9015 \times -6 = -90) to split the middle term, as shown in 15x29x+10x6=(3x+2)(5x3)15x^2 - 9x + 10x - 6 = (3x+2)(5x-3).

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Perfect Square Trinomial Formula

An algebraic identity where A2+2AB+B2=(A+B)(A+B)=(A+B)2A^2 + 2AB + B^2 = (A + B)(A + B) = (A + B)^2, exemplified by 4x2+12x+9=(2x+3)24x^2 + 12x + 9 = (2x + 3)^2.

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Difference of Squares Formula

A factoring rule stated as A2B2=(A+B)(AB)A^2 - B^2 = (A + B)(A - B), which can be applied to terms like x225=(x5)(x+5)x^2 - 25 = (x-5)(x+5) or 3x248=3(x4)(x+4)3x^2 - 48 = 3(x-4)(x+4).

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Factoring Higher Power Difference of Squares

The breakdown of expressions like 16x481y416x^4 - 81y^4 into (4x29y2)(4x2+9y2)(4x^2 - 9y^2)(4x^2 + 9y^2) and further into (2x3y)(2x+3y)(4x2+9y2)(2x - 3y)(2x + 3y)(4x^2 + 9y^2).

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Difference of Cubes Formula

The algebraic rule for cubes defined as A3B3=(AB)(A2+AB+B2)A^3 - B^3 = (A - B)(A^2 + AB + B^2), used for examples like 8x3278x^3 - 27.

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Grouping with Perfect Squares

A method used to solve complex expressions like 4x2+20x+25(9y2+24y+16)4x^2 + 20x + 25 - (9y^2 + 24y + 16), which converts to (2x+5)2(3y+4)2(2x+5)^2 - (3y+4)^2 and is then solved using the difference of squares: [(2x+5)+(3y+4)][(2x+5)(3y+4)][(2x+5) + (3y+4)][(2x+5) - (3y+4)].