Crystal Structures and Packing Fractions

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Vocabulary-style flashcards covering crystal structure properties, including atom contributions, geometric relationships, and packing fractions for SC, BCC, and FCC systems.

Last updated 3:24 PM on 6/3/26
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19 Terms

1
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Simple Cubic (SC) structure packing fraction

52%52\%

2
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Number of corner atoms in a BCC structure

88 atoms at the corners

3
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Number of center atoms in a BCC structure

11 atom exactly in the center

4
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Contribution of corner atoms to a BCC unit cell

8×(18)=18 \times (\frac{1}{8}) = 1 atom

5
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Contribution of the center atom to a BCC unit cell

11 atom (since it is not shared by neighboring cells)

6
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Total number of atoms per unit cell in a BCC structure

22 atoms

7
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Formula for the volume of a single spherical atom

43×π×R3\frac{4}{3} \times \pi \times R^3

8
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Formula for total volume occupied by atoms in a unit cell

Number of atoms (Z)×(43×π×R3)\text{Number of atoms } (Z) \times (\frac{4}{3} \times \pi \times R^3)

9
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Formula for the volume of a cubic unit cell

a3a^3

10
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Packing fraction

Ratio of total volume occupied by atoms in a unit cell to the total volume of the unit cell

11
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Relationship between edge length (aa) and atomic radius (RR) for BCC

a=4R3a = \frac{4R}{\sqrt{3}}

12
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Packing fraction of a Body-Centered Cubic (BCC) structure

68.0%68.0\%

13
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Number of corner atoms in an FCC structure

88 atoms at the corners

14
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Number of face atoms in an FCC structure

66 atoms (one on each of the 66 faces)

15
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Contribution of face atoms to an FCC unit cell

6×(12)=36 \times (\frac{1}{2}) = 3 atoms (since each face is shared by 22 cells)

16
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Total number of atoms per unit cell (ZZ) in an FCC structure

44 atoms (1 from corners + 3 from faces)

17
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Relationship between edge length (aa) and atomic radius (RR) for FCC

a=4R2a = \frac{4R}{\sqrt{2}}

18
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Formula for total volume occupied by atoms in an FCC unit cell

163×π×R3\frac{16}{3} \times \pi \times R^3

19
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Packing fraction of a Face-Centered Cubic (FCC) structure

74.0%74.0\%