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NMR spectroscopy
what it stands for
what it tells us and how
nuclear magnetic resonance spectroscopy
gives information about the position of 13C or 1H atoms in a molecule
different bond environments within a molecule absorb different amounts of energy, so show different peaks on a spectra
axes on NMR spectroscopy spectra
horizontal axis uses δ scale for recording chemical shift in parts per million (ppm)
vertical axis represents the intensity of the absorption of radio waves (/energy)
how do 13C and 1H behave as magnets?
how is this used in NMR spectroscopy?
their nuclei have nuclear spin, which generates a small magnetic field
this small magnetic field can be aligned with or against an external magnetic field
when you put 13C and 1H in a strong magnetic field and pass radio waves through them, their nuclei absorb the energy at specific frequencies which flips around their direction of spin
as the nuclei relax back, they emit signals that are detected
chemical shift
the difference in frequency / energy between the resonating nucleus and that of TMS
how far the signal is away from the signal for TMS
measured in ppm
how does the electron density around 13C or 1H affect their chemical shift?
higher electron density means greater shielding
so smaller chemical shift
how does the bond environment affect chemical shift?
greater chemical shift if 13C or 1H is closer to highly electronegative atoms or double bonds
highly electronegative atoms and double bonds attract electrons towards themselves
so decrease electron density around 13C or 1H
so less shielding
so greater chemical shift
TMS
tetramethylsilane, Si(CH3)4
used as a standard for bond environment peaks to be measured against in NMR
seen as a peak at δ = 0 ppm on the x-axis
reasons for use of TMS
used as a standard because:
it contains only one type of H environment and only one type of C environment
it only gives one signal, which is further right than most signals from organic compounds
it is inert, so won’t react with the sample or affect peaks produced
it is non-toxic, so less risk of harm to analysts
it is volatile (has low bpt) so easy to separate from the sample
deuterium
heavy hydrogen, 2H
1 neutron, 1 proton
has no nuclear spin
13C NMR spectroscopy
gives simpler spectra than 1H NMR
molecules with symmetry give fewer peaks than the number of C atoms in the molecule
peaks have no integration value
peaks have no splitting
how many peaks would benzene show in a 13C NMR spectra?
1, as all the C atoms are in the exact same environment
1H NMR spectroscopy
spectra obtained using samples dissolved in CCl4 (nonpolar) or deuterated solvents like CDCl3 (polar)
must be dissolved in a solvent that contains no 1H so that it doesn’t produce any peaks on the spectrum
integrated spectra / area under the graph gives the ratio of 1H atoms in different environments in a molecule
integration value of a peak = relative number of equivalent H atoms
in high resolution NMR, peaks have splitting
n + 1 rule
integration value = 3
3 H’s in the same environment
CH3 peak
give the integration trace on a 1H NMR spectra for propane
6 : 2 = 3 : 1
give the integration trace on a 1H NMR spectra for butane
6 : 4 = 3 : 2
why do peaks have splitting?
splitting of peak is caused by H atoms on adjacent C atom (spin-spin coupling)
only H atoms on C atoms cause splitting and are split
n + 1 rule
n non-equivalent H’s on adjacent C atom(s) will split a peak into n + 1 smaller peaks
there is no splitting when equivalent H atoms are on adjacent C atoms
e.g. in ethane CH3-CH3
splitting pattern: singlet
no splitting
no H atoms on adjacent C
H atom could be adjacent to O (—O-H)
H atom could be adjacent to N (—NH3)
splitting pattern: doublet
peak splits into 2
1 H atom on adjacent C
next to CH
splitting pattern: triplet
peak splits into 3
2 H’s on adjacent C
next to CH2
splitting pattern: quartet
peak splits into 4
3 H’s on adjacent C
next to CH3
splitting pattern: quintet
peak splits into 5
4 H’s on adjacent C
one CH2 on either side
splitting pattern: sextet
peak splits into 6
5 H’s on adjacent C
one CH3 and one CH2 on either side
triplet next to a quartet
CH2CH3
integration trace: 2 : 3
two triplets
CH2CH2
integration trace: 2 : 2
explain how and why isomers X and Y can be distinguished by comparing each of their 13C NMR spectra
compare number of peaks
compare range of δ for each peak and the corresponding type of bond environment
X will show a peak at ___ - ___ ppm, due to _____ group
Y will show a peak at ___ - ___ ppm, due to _____ group