inv trig

sin, -1<c<1

sin, -1<c<1

x= sin⁻¹c+2πn

x= π-sin⁻¹c+2πn

sin, c=1

(π/2) + 2πn

sin, c=-1

(-π/2) + 2πn

sin, -1>c>1

no solution

cos, -1<c<1

cos⁻¹c+2πn

-cos⁻¹c+2πn

cos, c=1

2πn

cos, c=-1

π+2πn