BG 3 Lytic Bacteriophage

0.0(0)
Studied by 0 people
call kaiCall Kai
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/71

encourage image

There's no tags or description

Looks like no tags are added yet.

Last updated 1:14 AM on 4/13/26
Name
Mastery
Learn
Test
Matching
Spaced
Call with Kai

No analytics yet

Send a link to your students to track their progress

72 Terms

1
New cards

binding of the phage to a specific receptor on cell surface

adsorption

2
New cards

early genes transcribed after injection of dna are

encodes mostly enzymes for dna synthesis

3
New cards

mrna is trancribed from ____ genes- encode proteins involved in ____

late, assembly of heads and tails (structure proteins)

4
New cards

how are phage genes regulated

transcription and post transcriptional regulation

5
New cards

regulatory cascades can easily identify a mutation how

able to see how one gene effects another. if something is mutated, you can see what’s being regulated more/less

6
New cards

in T7, RNA polymerase is a ________ gene. it recognized _______ promoters

late

7
New cards

what is the purpose of the pet system

to use T7, a pET vector, and IPTG to make large amounts of the target gene in the vector to produce lots of protein

8
New cards

which promoter is utilized in the pet system to make the pet vector

head protein 10

9
New cards

what transcribes the pet vector

t7 rna polymerase

10
New cards

what is needed to make the t7 rna polymerase to make more protein

a lac promoter, IPTG

11
New cards

how does iptg induction work

it mimics lactose and turns the system on, messing up repressor

12
New cards

where is your gene of interest inserted in the pet system

downstream of t7 promoter

13
New cards

if there was no lac operon in the pet system,

the lac operon keeps things off and controls production of t7, so if it wasn’t there, t7 would be made constantly

14
New cards

how would u use the pet system to ensure you get a lot of protein

let cells grow for a while, then induce with iptg so that all of those masses of cells will grow more

15
New cards

stop mutations can be used to identify gene products that ________ late genes

turn on

16
New cards

the promoter of head protein 10 in e.coli encodes what

a capsid, that makes it strong and protects it. helps it make thousands of genomes

17
New cards

proteins are separated by ______ in seeing infection times

gel electrophoresis

18
New cards

the phage polypeptide product runs towards its _______ on electrophoresis

molecular weight

19
New cards

early genes will be expressed on the ______ band with ______. and late genes willbe expressed on the ____ band with _____

first, late disintegration. last band buildup

20
New cards

why would two bands on GE be missing if there’s a stop mutation in a gene

one could possible regulate the other

21
New cards

what is the difference between a protein and the same protein with an asterick

they both came from one large protein, and it was eventually cleaved

22
New cards

in T4 genes, mutations in ___ and ))))) prevent middle genes

motA and asiA

23
New cards

mutations in genes ___ and ____ in T4 dna rep prevent late genes

33, 55

24
New cards

in t4, delayed early genes are transribed from

normal sigma 70 promoters

25
New cards

rna polymerase will stop before it transcribed delayed early genes unless

t4 produced antitermination factors, whcih are products of immediate early genes

26
New cards

transcripiton of promoters for middle genes are encoded by

motA and asiA

27
New cards

products of late genes

head, tail, enzymes to lyse the cell

28
New cards

how is the late gene promoter different than a usual promoter

it has a tataaata sequence and they lack a -35 sequence

29
New cards

what does gene 55 do in T4

alternative sigma factor taht binds to rna polymerase and causes it to recognize the true late promoter

30
New cards

the phage has its own proteins to make ______ translate it. you need ___ ____ and ____ to get late genes

rna polymerase. gene 55, gene 33, gp45

31
New cards

mota and asia on the sigma 70 MIDDLE GENE PROMOTERS give. _____ -35 sequence and a ______ -10 sequence

longer, normal

32
New cards

the late promoter has ____ -35 sequence and a ____ -10

no, longer

33
New cards

making things in lytic bacteria is based on

promoter recognition

34
New cards

phage replication is not correlated with ______

cell division

35
New cards

how do phages stop the primer problem from the lagging strands

telomeres, primers, terminal redundancies, and hairpin ends (concatamers)

36
New cards

what is the purpose of concatamers

make more dna, don’t lose genetic info, ensures full genomes are packed

37
New cards

in t7 concatamer formation, replication begins at the ori and replicates toward both ends while leaving _______

3’ ends because you can’t prime them

38
New cards

t7 has ____ at the ends of the dna so that they can ______ and form the concatamer

terminal redundancies, complement

39
New cards

in t7 concatamers, genomes are cut out at ______ sites and packed into ____

pac, phage heads

40
New cards

t4 encodes all of its ______ proteins, and contamers form in ____ stages

replication, two

41
New cards

in stage 1 t4 concat, it leaves _____ ends. in stage 2, it forms _____ to prime replication to make large branches. this is called

3’, loops. recombination-dependent replication

42
New cards

t4 is cut out of concatamers in _____. terminal redundancies are created since each t4 phage holds ____ more than the length of the genome

headfuls. 3%

43
New cards

in t4, each molecule cut off contains sequences of

the next genome

44
New cards

cyclic permutations

shifts all elements of a set by a fixed offset, so you’re getting dna from the next genome too. this is why the genetic map is shown as circular for t4. there’s no SPECIFIC start and stop

45
New cards

high moi means

more phage

46
New cards

to do phage crosses, you have to first

isolate mutant phage with desired mutations. mutated dna of the same species can be put together in the same cell for crossing

47
New cards

for phage crosses, the two dnas _______, after you infect the saem cell with different strains of the virus at the same time

recombine

48
New cards

how can we ensure that most of the cells get both viruses

there needs to be a high moi

49
New cards

for phage crosses, you’ll end up with ______ of one mutation, _______ of the other, _____ in two heads

parental, parental, recombinants x 2

50
New cards

why does complementation matter

sees if two muations can complement under conditions nonpermissive for one alone

51
New cards

in complementation tests, if both mutations are in the same gene, you’ll get _______. it’s good if the mutations are in _____ genes so that one can be ____

no phage. different, expressed

52
New cards

recombination tests are done under _____ conditions. combination tests are done in ______ conditions

permissive, nonpermissive

53
New cards

rII genes are

rapid lysis mutatnts type 2

54
New cards

r2 genes make a cell ____ quicker. they cannot multiply in strains of _____ taht are lysogenic for lambda prophage

lyse. e. coli

55
New cards

rII cannot multiply on

K lambda phage

56
New cards

recombination of rII was shown through

injecting e. coli with two different rII mutatns and letting htem multiply then plating them to see frequency of recombinatin

57
New cards

if recombination occurs with the two rII mutants what will you get

double mutants with both or wild type

58
New cards

total number of recombinant types is _____ x 2

wild type r because it grew on k lambda

59
New cards

how do you ensure e. coli that’s being plated on doesn’t die

need to do serial dilutions

60
New cards

why do you dilute total progeny more than when diluting r+ recombinants

you’ll account for recombinants and wild type

61
New cards

if you have 108 plaques on e. coli k lambda plates, what do you do to find total recombinants

108 × 2 = 216 × 10^5 (dilution)

62
New cards

if you have 144 on e. coli, how do you get total progeny

144 × 10^7

63
New cards

recombination frequency equation

recombinant progeny/total

64
New cards

multiply RF by ___ for map units to see how close together mutants are

100

65
New cards

to calculate moi, divide

phage added/bacteria present

66
New cards

high moi means

phage outnumber cells

67
New cards

how can poisson distribution be used for moi and what does that tell us

use e^-moi then multiply times 100 for percentage UNINFECTED

68
New cards

what if one parent strain had both mutations and the other had neither?

none, both, right, left

69
New cards

how do terminal redundancies help the primer problem

it acts as a buffer so that even if a few nucleotides are lost in replication, it’s nothing important.

70
New cards

t7 linear dna doens’t _____, just forms concatamers through

cyclize, joining end to end

71
New cards

t7’s terminal redundancies _____ and form the concatemer

pair

72
New cards

how do the phage heads get packed dna in t7 concatamers

cut at pac sites at the ends of dna and put in