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Area between curves
The area of a region in the plane whose boundary is formed by two graphs; typically found using definite integrals that add up infinitesimally thin slices.
Definite integral as area accumulation
A definite integral represents the limit of a sum of areas of many thin rectangles (or slices), giving exact area when boundaries are curved.
Vertical slicing
A method for area where you use rectangles with thickness dx; each rectangle’s height is determined by y-values (top minus bottom).
Top-minus-bottom (dx)
For vertical slices, the slice height is (upper function) − (lower function), so area is ∫(top−bottom)dx over the x-interval.
Area formula with respect to x
If y=f(x) is above y=g(x) on (a,b), then the area is A=∫ab(f(x)−g(x))dx.
Bounds of integration (a and b)
The left and right x-values that define the region when integrating with dx; they come from intersection points, given vertical lines, or a mix.
Intersection points (for bounds)
Points where two curves cross; found by solving f(x)=g(x), and their x-values often serve as integration limits.
Given vertical lines
Explicit boundaries like x=1 and x=4 that set the integration limits for a dx integral, even if curves intersect elsewhere.
Top function
The curve that gives the larger y-value for a given x on the interval being used (determines the “top” in top-minus-bottom).
Bottom function
The curve that gives the smaller y-value for a given x on the interval being used (determines the “bottom” in top-minus-bottom).
Switching top/bottom
A situation where the curves cross within the interval so the upper curve changes; the area setup must be split into multiple integrals.
Splitting an integral for area
Breaking the area calculation into a sum of integrals over subintervals where the top-minus-bottom (or right-minus-left) relationship stays consistent.
Cancellation (negative area)
When you fail to split at a crossing, parts of the integral become negative and subtract from positive parts, producing the wrong result for area.
Horizontal slicing
A method for area where you use slices with thickness dy; each slice’s length is determined by x-values (right minus left).
Right-minus-left (dy)
For horizontal slices, the slice length is (right boundary) − (left boundary), so area is ∫(right−left)dy over the y-interval.
Area formula with respect to y
If x=R(y) is to the right of x=L(y) on (c,d), then the area is A=∫cd(R(y)−L(y))dy.
y-bounds (c and d)
The lowest and highest y-values of the region when integrating with respect to y; limits must match the variable dy.
Rewriting boundaries as x in terms of y
To use dy, you often solve equations to express curves as x=… (e.g., y=x2 becomes x=±y).
Branch (left/right) selection
Choosing the correct solution when solving for x in terms of y (e.g., using x=4−y2 for the right half of a circle).
Vertical line test (motivation for dy)
If a curve is not a single-valued function y=f(x) over a region (like a circle), using dy with x as a function of y may avoid splitting.
Example: area between y=x and y=x2
Solve x=x2 to get bounds 0 and 1; on (0,1), x is above x2, so A=61.
Example: sin x vs cos x on [0,π]
They intersect at x=4π; top switches, so area is ∫04π(cos−sin)dx+∫4ππ(sin−cos)dx=22.
Example (dy): y=x2 and y=2x
Intersections at x=0,2 give y from 0 to 4; right boundary x=y, left boundary x=2y, so A=∫04(y−2y)dy=34.
Example: right half of circle x2+y2=4
Using dy: left boundary x=0, right boundary x=4−y2, y from −2 to 2; area equals semicircle area 2π.
Choosing dx vs dy
Pick dx when vertical slices give one clean top-minus-bottom expression; pick dy when horizontal slices give one clean right-minus-left expression (and avoid extra splitting).