Physics 10 Science: Cart Motion Revision Practice

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Vocabulary and key experimental data from the Physics 10 Cart Motion investigation involving displacement, time, and numerical modeling.

Last updated 6:05 AM on 6/15/26
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11 Terms

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Research Question

The central inquiry of the experiment: What is the relationship between the time and displacement for a cart moving down a ramp when the angle of the ramp is 15o15^\text{o} and the cart has a mass of 250g250\,g?

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Mass of the cart

The specific mass used in the experiment, which was 250g250\,g.

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Angle of the ramp

The inclination of the apparatus used in Figure 1, which was set to 15o15^\text{o}.

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Uncertainty of Time (tt)

The measurement precision for the time values recorded in Table 1, which is ±0.005s\pm 0.005\,s.

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Uncertainty of Displacement (ss)

The measurement precision for the displacement values recorded in Table 1, which is ±0.005m\pm 0.005\,m.

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Mean Average Displacement at t=1.50st = 1.50\,s

Calculated by averaging the three trials: 0.76+0.77+0.733=0.75m\frac{0.76 + 0.77 + 0.73}{3} = 0.75\,m.

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Velocity

Calculated as the gradient of the displacement-time graph (change in YChange in x\frac{\text{change in Y}}{\text{Change in x}}), which was determined to be 0.5m/s0.5\,m/s.

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Numerical Model

The mathematical representation of the cart's motion in the form y=mx+cy = mx + c, specifically: Displacement=0.5×Time\text{Displacement} = 0.5 \times \text{Time}.

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Interpolated Displacement for t=1.8st = 1.8\,s

The value read from the displacement-time graph for a specific time, which is 0.9m0.9\,m.

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Interpolated Time for Displacement 0.4m0.4\,m

The value read from the displacement-time graph for a specific distance, which is 0.8sec0.8\,sec.

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Motion Description (t=0st = 0\,s to t=1.5st = 1.5\,s)

The cart moved from a starting point to a distance of 0.75m0.75\,m at a constant velocity.