Rate Equations

as temp. increase what happens to k?

k increases - higher temp = more particles have higher Ek & likely to collide with least Ea → increased rate of reaction

as Ea increases what happens to k?

k decreases: higher Ea = fewer particles have sufficient energy = rate of reaction decreases → k decreases

what is the rate-determining step?

the slowest step that controls the rate of the reaction (is present in the rate equation)

how do you know which step is the slow step?

all the substance in their quantities are used up from the rate equation

arrhenius rearranged

ln k = ln A - E_A/(RT)

what does the gradient of 1/T x ln (rate) graph give you?

activation energy

give the y = mx + c version of the rate equation

log rate = log k + n log [Y]

n = order