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Define the term stereoisomers. (2)
(Different molecules/compounds with the) same (molecular and) structural formula (1)
Different spatial arrangement of atoms (1)
Under suitable conditions, 2-bromobutane reacts with sodium hydroxide to
produce a mixture of five products, A, B, C, D and E.
Products A, B and C are alkenes.
A is a structural isomer of B and C.
A does not exhibit stereoisomerism.
B and C are a pair of stereoisomers.
Products D and E are alcohols.
D and E are a pair of enantiomers.
Deduce the name of isomer A. Explain why A does not exhibit stereoisomerism. (2)
A = but-1-ene (1)
two groups/atoms/Hs the same on one of the C=C carbons (1)
Under suitable conditions, 2-bromobutane reacts with sodium hydroxide to
produce a mixture of five products, A, B, C, D and E.
Products A, B and C are alkenes.
A is a structural isomer of B and C.
A does not exhibit stereoisomerism.
B and C are a pair of stereoisomers.
Products D and E are alcohols.
D and E are a pair of enantiomers.
Deduce the name of isomer B and the name of isomer C. Explain the origin of the stereoisomerism in B and C. (2)
Z-but-2-ene AND E-but-2-ene (1)
lack of/restricted/no (free) rotation around C=C/double bond (1)

Compound J is one of a pair of stereoisomers
Explain:
• what stereoisomers are
• how E-Z stereoisomerism occurs
• how the Cahn-Ingold-Prelog rules can be used to decide whether compound J is an E or Z isomer. (6)
Stereoisomers are compounds with the same structural formula but a different arrangement of atoms in space.
E/Z isomerism arises due to restricted rotation around the C=C bond
When each C of C=C is attached to two different groups
CH3CH2 is higher priority than H on RHS C
as atomic number of C is higher than H or C = 6 v H = 1
(CH3)2CH is higher priority than CH3CH2 on LHS C
as atomic numbers of atoms joined to C (joined to C=C) are higher for (CH3)2CH than CH3CH2
highest priority groups on opposite sides (of C=C)
Therefore compound J is a Z isomer (6)