3.1.1.3 electronic configuration

0.0(0)
Studied by 0 people
call kaiCall Kai
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/33

encourage image

There's no tags or description

Looks like no tags are added yet.

Last updated 6:03 PM on 4/14/26
Name
Mastery
Learn
Test
Matching
Spaced
Call with Kai

No analytics yet

Send a link to your students to track their progress

34 Terms

1
New cards

explain how electrons are arranged?

in principal energy levels (electron shells) which themselves have sub-levels (sub-shells)

2
New cards

what letters are the sub-levels assigned?

s, p, d + f

3
New cards

what sub-levels do each of the principal energy levels contain?

knowt flashcard image
4
New cards

describe the energy of the sub-levels

  • each of the sub-levels has a different energy

  • the energy of them increases from s → p → d → f

5
New cards

give the order of increasing energy in the sub-levels

1s 2s 2p 3s 3p 4s 3d 4p 5s 4d 5p 6s…

<p>1s 2s 2p 3s 3p 4s 3d 4p 5s 4d 5p 6s…</p>
6
New cards

a. what are orbitals?

b. how are orbitals represented?

c. how many electrons does each orbital hold?

a. they are sublevels within sublevels → sub-levels are divided into orbitals

b. by boxes

c. each one holds a maximum of 2 electrons

7
New cards

give the number of orbitals in + maximum number of electrons held in each sub-level

knowt flashcard image
8
New cards

a. why does 4s fill before 3d?

b. but what happens regarding 4s + 3d when atoms are ionised?

a. because it is lower in energy → electrons fill the orbital of lowest energy first

b. electrons are removed from 4s before they’re removed from 3d

9
New cards

what does each number/letter represent in electronic configurations eg 2p³

knowt flashcard image
10
New cards

write the electron configuration for:

  1. Na

  2. Oxygen

  • 1s²2s²2p⁶3s¹

  • 1s²2s²2p⁴

11
New cards

explain what noble gas configuration is

a short hand electronic configuration that uses the electronic configurations of the noble gases

  • the electron configuration of a noble gas can be used to represent part of any other elements’ configuration

<p>a short hand electronic configuration that uses the electronic configurations of the noble gases </p><ul><li><p>the electron configuration of a noble gas can be used to represent part of any other elements’ configuration </p></li></ul>
12
New cards

give the electronic configuration of the noble gases:

a. He

b. Ne

c. Ar

d. Kr

knowt flashcard image
13
New cards

what are the two exceptions when it comes to writing the electronic configuration of elements? + explain the reasons for these exceptions

  • chromium (Cr)

  • copper (Cu)

<ul><li><p>chromium (Cr)</p></li><li><p>copper (Cu)</p></li></ul>
14
New cards

what’s the rule regarding 4s + 3d when atoms ionise? + why?

4s fills before 3d as it is lower in energy → removal of electrons occurs from the highest principle energy level

15
New cards

a. what is an energy level diagram?

b. draw one

a. a pictoral representation of an electronic configuration

b. look at image

<p>a. a pictoral representation of an electronic configuration</p><p>b. look at image</p>
16
New cards

in an energy level diagram…

a. how many electrons does each orbital contain?

b. how are electrons represented/drawn in each orbital?

c. what represents the spin of the electrons?

d. how do the electrons occupy each orbital + why?

a. a maximum of 2

b. arrows represent electrons

c. direction of arrows represents spin of electrons

d. the electrons occupy orbitals as unpaired electrons rather than paired electrons until they have to be paired up → paired electrons have opposite spin as this reduces the repulsion between the paired electrons

<p>a. a maximum of 2</p><p>b. arrows represent electrons</p><p>c. direction of arrows represents spin of electrons</p><p>d. the electrons occupy orbitals as unpaired electrons rather than paired electrons until they have to be paired up → paired electrons have opposite spin as this reduces the repulsion between the paired electrons</p>
17
New cards

what are the three principles/rules of electron configuration?

  1. Aufbau principle → electrons fill the lowest energy orbital first

  2. Pauli principle → electrons in the same orbital have the opposite spin

  3. Hund’s rule → electrons will be unpaired wherever possible

18
New cards

what can the periodic table be used to do regarding electron configuration? how?

to find the location of the outer electron in any atom → there is a link between the position of the atom on the table + its principal energy level + sublevel

19
New cards

what does each row on the periodic table represent?

a principal energy level

20
New cards

the block each element is in determines what?

which sub-level their outer most electron will be in

21
New cards

for each block on the periodic table, give the groups it contains the the sub-level it represents

  • s-block → group 1 + 2 → s sub-level

  • p-block → group 3 to 8 → p sub-level

  • d-block → transition metals → d sub-level

<ul><li><p><strong>s-block</strong> → group 1 + 2 → s sub-level </p></li><li><p><strong>p-block </strong>→ group 3 to 8 → p sub-level</p></li><li><p><strong>d-block </strong>→ transition metals → d sub-level </p></li></ul>
22
New cards

what will the columns within each block show? + give the no. of columns in each of the 3 blocks

  • it will give number of electrons on the sub-level ie Mg is in the second column of s-block so it had 2 electrons in its last sub-level

  • s block = 2

  • p block = 6

  • d block = 10

23
New cards

so how can you determine the electronic configuration of an element using the periodic table?

  1. find which period its in (becomes principal energy level) *for d-block elements this number is ‘period minus one’

  2. which block is it in (s, p, d or f)? (this becomes your sub level)

  3. which column is it in within that block? (this is your no. of electrons/the electron ‘power of’ number)

  4. fill the rest of the configuration before it

24
New cards

what do ionisation energies give evidence for?

for the existence of principal energy levels + the sub levels

25
New cards

what does the ionisation of an atom involve?

the loss of an electron to form a positive ion (not talking about the gain of an electron!!)

26
New cards

define first ionisation energy

the minimum amount of energy required to remove an electron from a gaseous atom

27
New cards

a. what is the trend in the first ionisation energies when you go down the groups eg group 2?

b. explain why

a. it decreases

b.

  • the electron is removed from a higher principal energy level so its removed further from the nucleus

  • there is more shielding

  • less energy is required to remove the electron as there is a weaker attraction between the nucleus + outer electron

<p>a. it decreases</p><p>b. </p><ul><li><p>the electron is removed from a higher principal energy level so its removed further from the nucleus </p></li><li><p>there is more shielding </p></li><li><p>less energy is required to remove the electron as there is a weaker attraction between the nucleus + outer electron</p></li></ul>
28
New cards

a. describe the trend of the first ionisation energies across the periods ie period 3

b. explain the reason for this trend

a. ionisation energy increases

b.

  • the number of protons increase + so does the positive charge of nucleus

  • atomic radius decreases but shielding stays constant

  • more energy is required to remove the electron as there is a stronger attraction between nucleus + outer electron

<p>a. ionisation energy increases</p><p>b.</p><ul><li><p>the number of protons increase + so does the positive charge of nucleus</p></li><li><p>atomic radius decreases but shielding stays constant</p></li><li><p>more energy is required to remove the electron as there is a stronger attraction between nucleus + outer electron</p></li></ul>
29
New cards

what can we see in the ionisation energies when we go across the period?

deviations in the energies increasing

30
New cards

explain two reasons for deviations in ionisation energies increasing across the period using the examples of Al + Mg and S + P

  1. the first ionisation energy of Al is less than that of Mg because:

    • when you look at the electronic configurations of the two elements → Mg: 1s²2s²2p⁶3s²

      Al: 1s²2s²2p⁶3s²3p¹

    • the electron is removed from a higher energy sub-level (p) in Al

    • which means less energy is required to remove the outer electron as there is a weaker attraction between nucleus + outer electron

  2. the first ionisation energy of S is less than that of P because:

    • when you look at the electronic configurations for the two elements →

      S: 1s²2s²2p⁶3s²3p³

      P: 1s²2s²2p⁶3s²3p⁴

    • there is a pair of electrons in the p-orbital in P

    • this extra repulsion between the paired electrons means less energy is required to remove the electron

31
New cards

write the equations for first, second + third successive ionisation energies

  1. X(g) → X⁺(g) + e⁻

  2. X⁺(g) → X²⁺(g) + e⁻

  3. X²⁺(g) → X³⁺(g) + e⁻

*always in the gaseous state

32
New cards

explain why successive ionisation energies will always increase

  • the positive charge on ion increases

  • the ionic radius decreases + shielding stays constant

  • nuclear attraction on the outer electron increases

33
New cards

when you look at the successive ionisation energies of an element what will there always be? + why?

a significant jump in ionisation energy between two of the successive IEs eg between the 3rd + 4th one → due to the electron now being removed from a lower principle energy level (one that is much closer to the nucleus)

34
New cards

what does this large jump in ionisation energy be used to do + how?

  • can be used to find the group in which an element belongs

  • eg if the large jump is between 3rd + 4th IE there must have been 3 outer electrons hence the group must be in group 3

<ul><li><p>can be used to find the group in which an element belongs </p></li><li><p>eg if the large jump is between 3rd + 4th IE there must have been 3 outer electrons hence the group must be in group 3 </p></li></ul>