Simple Pendulum

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Last updated 9:56 PM on 10/25/25
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43 Terms

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Yes, it is true

Is it true that a pendulum can be used to measure the acceleration due to gravity?

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simple harmonic oscillator.

For small displacements, a pendulum is a…

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θ

(1)

<p>(1)</p>
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L

(2)

<p>(2)</p>
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F_T

(3)

<p>(3)</p>
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+y

(4)

<p>(4)</p>
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+x

(5)

<p>(5)</p>
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m

(6)

<p>(6)</p>
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s

(7)

<p>(7)</p>
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-mgsin(θ)

(8)

<p>(8)</p>
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-mgcos(θ)

(9)

<p>(9)</p>
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w = mg

(10)

<p>(10)</p>
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Simple Pendulum

  • Consists of a point mass (bob)

  • Bob is suspended from a massless, inextensible string of length L

  • Swings back and forth under the influence of the gravity.

  • Experiences only two forces (tension and weight)

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Weight and Tension

What are the two only forces that the bob in a simple pendulum experience?

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Pendulum Bob

The small, dense point mass at the end of the pendulum string that moves along an arc during oscillation.

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Linear Displacement (s)

The arc length that measures how far the pendulum bob is displaced from its equilibrium position.

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Restoring Force in a Pendulum

The component of gravity that acts along the arc, pulling the bob back toward equilibrium.

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F = -mgsin(θ)

Mathematical representation of the Restoring Force in a Pendulum

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Restoring Torque

The torque due to the restoring force acting at a distance L from the pivot. It always acts to return the bob towards its equilibrium position.

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τ = -L(mgsin(θ))

Mathematical representation of the Restoring Torque

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Moment of Inertia (I)

A measure of an object's resistance to changes in its rotational motion about a specified axis. It depends on the object’s mass and the distribution of that mass relative to the axis of rotation.

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I = ∑m(r^2)

Mathematical representation of the Moment of Inertia for the discrete particles.

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I = ∫(r^2) dm

Mathematical representation of the Moment of Inertia for the continuous objects.

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Torque

A measure of the tendency of a force to rotate an object about an axis. It depends on both the magnitude of the force and the perpendicular distance from the axis of rotation

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τ = rFsin(θ)

Mathematical representation of the torque.

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Angular Acceleration

The rate of change of angular velocity of an object with respect to time. It describes how quickly an object speeds up or slows down its rotational motion.

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α = dω/dt

Mathematical representation of the Angular Acceleration

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Newton’s Second Law for Rotation

  • Law that relates torque, moment of inertia, and angular acceleration

  • States that the torque applied to an object is equal to its moment of inertia multiplied by its angular acceleration.

  • The rotational analog of F=ma in linear motion.

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τ = Iα

Mathematical representation of “Newton’s Second Law for Rotation“

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Iα = -L(mgsin(θ))

Equation for the Restoring Torque after substituting the Newton’s Second Law for Rotation

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I = m(L^2)

Formula for the Moment of Inertia for the Pendulum Bob

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((d^2)(θ​))/(dt^2) = -(g/L)sin(θ)

Equation for the Restoring Torque (final form) [Equation of the motion]

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It indicates that the torque acts in the opposite direction to the angular displacement, always trying to restore the pendulum to equilibrium.

What does the negative sign in the torque equation τ = -L(mgsin(θ)) indicate?

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Small-Angle Approximation

  • Used for small angles (θ < 15 degrees or 0.26 radians)

  • sin(θ) gets approximated to θ

  • Simplifying the motion to Simple Harmonic Motion

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((d^2)(θ​))/(dt^2) = -(g/L)θ

Equation for the Restoring Torque (final form with Small-Angle Approximation) [Equation of the motion]

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ω = (g/L)^1/2

Formula for the angular frequency of a simple pendulum

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T = 2π((L/g)^1/2)

Formula for the period of a simple pendulum

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Because both the restoring force and inertia depend on the mass m, which cancels out in the equation of motion. Leaving the period only depend on the length L and the acceleration due gravity g.

Why does the period of a simple pendulum not depend on its mass?

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For small amplitudes (θ < 15 degrees), the period is almost independent of amplitude. For larger angles, small nonlinear deviations occur.

Does the period of a simple pendulum depend on its amplitude?

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It ensures that the restoring force is directly proportional to the displacement, making the motion linear and simple harmonic rather than complex and nonlinear.

Why is the small-angle approximation important?

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g = (4(π^2)L)/T^2

Formula to measure the gravity that we get after rearranging the T = 2π((L/g)^1/2) equation

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The string is massless and inextensible, the bob is a point mass, air resistance is negligible, and oscillations are of small amplitude.

What assumptions make a pendulum “simple”?

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A stronger (as at the poles) shortens the period, while a weaker g (as near the equator or at higher altitudes) makes the pendulum swing more slowly.

How does the local acceleration due to gravity affect the pendulum’s period

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