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Given this utility function and the production function: c = g(t), solve the constrained optimisation problem.
-The FOC can be found via MRS = MRT.
MRS = v’(t) and MRT = g’(t)
-Because v’’(t) is negative (indifference curve slopes downward) and g’’(t) is negative too (feasible frontier slopes downward), only one value of t exists. Therefore:
v’(t) + g’(t) = 0
-Thus, t* exists such that we get c* = g(t*) which is the optimal consumption of grain


Given this utility function and the production function: c = g(t), solve the constrained optimisation problem.
v(t) = 4√(t)
g(t) =2√(48-2t)
-Using the FOC:
MRS = 2/√(t)
MRT = 2/√(48-2t)
-This nicely simplifies down to:
48-2t = t
-Thus leading to optimal values of:
t = 16
c = 8
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