Benzene Structure and Azo Dyes

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Last updated 2:50 PM on 5/20/26
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29 Terms

1
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Draw the kekule’s structure of benzene and the accepted structure and list the simularities and differences

Both

  • All bond angle are 120

  • Planar structure

  • 3 sets of electrons repelled

Kekule Structure

  • Alternating single and double bonds (suggesting different bond lengths)

  • Two dimethyl isomers expected

  • Hydrogenation enthalpy 3x that on cyclohexene due 3 double bonds instead of 1

  • Undergoes addition reactions

  • Should decolourise bromine water

Actual Benzene

  • C-C all the same length

  • Only 1 isomer of dimethyl

  • Hydrogenation enthalpy is less than 3x that of cyclohexene - less energy released so more stable due to delocalisation

  • Undergoes substitution reactions

  • Won’t decolourise bromine water

<p>Both </p><ul><li><p>All bond angle are 120</p></li><li><p>Planar structure </p></li><li><p>3 sets of electrons repelled </p></li></ul><p>Kekule Structure </p><ul><li><p>Alternating single and double bonds (suggesting different bond lengths)</p></li><li><p>Two dimethyl isomers expected </p></li><li><p>Hydrogenation enthalpy 3x that on cyclohexene due 3 double bonds instead of 1</p></li><li><p>Undergoes addition reactions</p></li><li><p>Should decolourise bromine water </p></li></ul><p>Actual Benzene</p><ul><li><p>C-C all the same length</p></li><li><p>Only 1 isomer of dimethyl </p></li><li><p>Hydrogenation enthalpy is less than 3x that of cyclohexene - less energy released so more stable due to delocalisation</p></li><li><p>Undergoes substitution reactions</p></li><li><p>Won’t decolourise bromine water </p></li></ul><p></p>
2
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Explain, using a diagram, how benzene is delocalised

  • Each carbon atom forms 3 sigma bonds

  • This leaves the 4th electron in the p orbital of each carbon

  • The 6 p orbitals overlap forming a pi cloud of electron density

  • This is two rings of electrons one above and below the plane of the carbon atoms

  • The electrons move freely within this pi system. They are delocalised

<ul><li><p>Each carbon atom forms 3 sigma bonds</p></li><li><p>This leaves the 4th electron in the p orbital of each carbon</p></li><li><p>The 6 p orbitals overlap forming a pi cloud of electron density </p></li><li><p>This is two rings of electrons one above and below the plane of the carbon atoms </p></li><li><p>The electrons move freely within this pi system. They are delocalised </p></li></ul><p></p>
3
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What is the difference between an aromatic compound and an arene

Aromatic compounds - contain a ring of delocalised electrons

Arenes - contain a benzene ring

4
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Show the general mechanism for the electrophilic subsitution of benzene with elctrophile, E+

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5
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Give the reagents, conditions, electrophile, equations (generation of electrophile and regeneration at catalyst) and mechanism for the halogenation of benzene

Reagents - Cl2 or Br2

Conditions - Anhydrous AlFe3/AlBr3/FeCl3/FeBr3 Catalyst

Electrophile - Cl+ or Br+

Generation of electrophile - AlCl3 + Cl2 → AlCl4- + Cl+

Regeneration of catalyst - AlCl4- + H+ → AlCl3 + HCl

<p>Reagents - Cl<sub>2</sub> or Br<sub>2</sub></p><p>Conditions - Anhydrous AlFe<sub>3</sub>/AlBr<sub>3</sub>/FeCl<sub>3</sub>/FeBr<sub>3</sub> Catalyst</p><p>Electrophile - Cl<sup>+</sup> or Br<sup>+</sup></p><p>Generation of electrophile - AlCl<sub>3</sub> + Cl<sub>2</sub> → AlCl<sub>4</sub><sup>-</sup> + Cl<sup>+</sup></p><p>Regeneration of catalyst - AlCl<sub>4</sub><sup>-</sup> + H<sup>+</sup> → AlCl<sub>3</sub> + HCl</p>
6
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Give the reagents, conditions, electrophile, equations (generation of electrophile and regeneration at catalyst) and mechanism for the nitration of benzene

Reagents - Concentrated HNO3

Conditions - Concentrated H2SO4 (Catalyst and dehydrating agent) and less than 55C

Electrophile - NO2+

<p>Reagents - Concentrated HNO<sub>3</sub></p><p>Conditions - Concentrated H<sub>2</sub>SO<sub>4</sub> (Catalyst and dehydrating agent) and less than 55C</p><p>Electrophile - NO2<sup>+</sup></p>
7
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Give the reagents, conditions, electrophile and equation for the sulphonation of benzene

Reagents - Concentrated H2SO4

Conditions - Heat under reflux

Electrophile - SO3H+

<p>Reagents - Concentrated H<sub>2</sub>SO<sub>4</sub></p><p>Conditions - Heat under reflux</p><p>Electrophile - SO<sub>3</sub>H<sup>+</sup></p>
8
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Give the reagents, conditions, electrophile and equation (including the generation of electrophile) for the Friedel-Crafts Reaction (adding carbon chains to a benzene ring)

Reagents - haloalkane with correct R group

Conditions - Anhydrous AlCl3 catalyst, reflux

Electrophile - CH3+ (R+)

Generation of electrophile - AlCl3 + CH3Cl → CH3+ + AlCl4-

<p>Reagents - haloalkane with correct R group</p><p>Conditions - Anhydrous AlCl<sub>3</sub> catalyst, reflux</p><p>Electrophile - CH3<sup>+ </sup>(R<sup>+</sup>)</p><p>Generation of electrophile - AlCl<sub>3</sub> + CH<sub>3</sub>Cl → CH<sub>3</sub><sup>+</sup> + AlCl<sub>4</sub><sup>-</sup></p>
9
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Give the reagents, conditions, electrophile and equation (including the generation of electrophile) for the Friedel-Crafts Acetylation Reaction

Reagents - Acyl chloride

Conditions - Anhydrous AlCl3 catalyst

Electrophile - e.g. CH3CO+

Generation of electrophile - AlCl3 + CH3COCl → CH3CO+ + AlCl4-

<p>Reagents - Acyl chloride</p><p>Conditions - Anhydrous AlCl<sub>3</sub> catalyst</p><p>Electrophile - e.g. CH<sub>3</sub>CO<sup>+</sup></p><p>Generation of electrophile - AlCl<sub>3</sub> + CH<sub>3</sub>COCl → CH<sub>3</sub>CO<sup>+</sup> + AlCl<sub>4</sub><sup>-</sup></p><p></p>
10
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Show how benzene can be halogenated using halogen carrier

Reagents - Polarised halogen molecule, AlCl3 catalyst

<p>Reagents - Polarised halogen molecule, AlCl3 catalyst </p>
11
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Azo dyes contain an azo functional group. Draw the general structure of an azo functional group

R—N=N—R

12
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Explain, using equations, how azo dyes form

Step 1: Formation of diazonium compound

Reagents - Aromatic amine, sodium (III) nitrate, dilute HCl

Conditions - <5C

Step 2: Coupling Reaction

Reagents - diazonium compound, phenol (or phenolamine), NaOH

Conditions - alkaline (NaOH), <5C

Observations - coloured ppt of azo dye formed

<p>Step 1: Formation of diazonium compound</p><p>Reagents - Aromatic amine, sodium (III) nitrate, dilute HCl</p><p>Conditions - &lt;5C</p><p></p><p>Step 2: Coupling Reaction</p><p>Reagents - diazonium compound, phenol (or phenolamine), NaOH</p><p>Conditions - alkaline (NaOH), &lt;5C</p><p>Observations - coloured ppt of azo dye formed</p><p></p>
13
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Explain how colour arises in organic molecules and what colour depend on

  • Molecules must have an extended delocalised system (alternating single and double bonds)

  • Radiation (usually visible light) is absorbed by electrons according to the energy gap (E=hv)

  • Electrons in extended delocalised system move to higher energy levels

  • Complementary colour is transmitted

  • The energy gap and so frequencies depend upon

- Amount of delocalisation

-Size of chromophore

-Bonding and functional groups on chromophore

  • Smaller delocalised system = larger energy gap and so higher frequency absorbed (e.g. UV light which will transmit all visible colours)

14
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What is a chromophore and what are the impacts of its side groups on organic colour and solubility

Chromophore - the part of the molecule that gives it its colour i.e. all the parts with alternating double and single bonds

  • Side groups can affect the colour

  • Groups with lone pairs (e.g. OH) - delocalise in the pi system changing the energy gap and therefore the frequency absorbed

  • Acyl groups and nitro groups contain double bonds and so extend the delocalised system

  • Ionic groups like sulfonate groups allow ion-dipole bonds to form with water, increasing solubility as these are stronger than hydrogen bonds in water

15
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How can dyes stick to fabric

  • Ionic bonding - ionic bonds form between NH3+ o the fibres and the sulfonate group on dye molecules

  • Covalent bonding

- Mordanting - Functional groups with lone pairs form a complex ion by dative bonding with a metal ion

- Fibre reactive dyes - Functional groups added to the dye molecules that will allow it to react with the fibre, e.g. condensation reaction

  • Intermolecular bonding

- Hydrogen bonds form between OH on fibres and NH2 or OH groups of dye

- ID-IDs

16
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How can aldehydes be prepared from primary alcohols

Reagents - primary alcohol and K2Cr2O7/H+(aq)

Conditions - Heat under distilation

Observations - Orange → Green

Equation - CH3CH2CH2OH + [O] → CH3CH2CHO + H2O

17
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How can ketones be prepared from secondary alcohols

Reagents - secondary alcohol and K2Cr2O7/H+(aq)

Conditions - Heat under Reflux

Observations - Orange → Green

Equation - CH3CH(OH)CH3 + [O] → CH3COCH3 + H2O

18
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How can aldehydes and ketones be distinguished using K2Cr2O7/H+

Warm with K2Cr2O7/H+

Aldehyde - Orange → Green

Ketone - Stays orange as ketones can’t be oxidised further

19
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How can aldehydes and ketones be distinguished using Fehlings Solution

Warm with Fehling’s solution

Aldehyde - Blue solution forms brick red precipitate (CuO)

Ketones - Solution stays blue

20
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How can aldehydes and ketones be distinguished using Tollens Reagent

Warm with Tollens Reagent

Aldehyde - Silver mirror forms

Ketones - No change

21
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Show the mechanism for the reaction between an aldehyde and HCN/KCN. Give the type of reaction, reagents and equation

Nucleophillic Addition

Reagents - acidified HCN or KCN

Equation - CH3CH2CHO + HCN → CH3CH2CH(OH)CN

Hydroxynitrile formed

<p>Nucleophillic Addition</p><p>Reagents - acidified HCN or KCN</p><p>Equation - CH<sub>3</sub>CH<sub>2</sub>CHO<sub> </sub>+ HCN → CH<sub>3</sub>CH<sub>2</sub>CH(OH)CN</p><p>Hydroxynitrile formed </p>
22
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Show how triesters (triglycerides) from glycerol and 3x fatty acids

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23
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What are saturated and unsaturated fatty acids

Saturated - single bonds only

Unsaturated - contains C=C

24
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Unsaturated fatty acids can be cis (z) or trans (E), what does this mean

Cis (Z) - adjacent parts of chain are next to each other across the double bond

Trans (E) - adjacent parts of chain are on opposite sides across the double bond

25
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Show how a triglyceride can be hydrolysed, give the reagents and conditions

Reagents - Concentrated NaOH

Conditions - heat

<p>Reagents - Concentrated NaOH</p><p>Conditions - heat </p>
26
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What is the mobile phase and stationary phase of Gas-Liquid Chromatography

Mobile - inert carrier gas, usually nitrogen

Stationary phase - high boiling point liquid on a porous support in a long capillary tube

27
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How can GLC be used to find the concentration of components

  • The area under each peak is proportional to the amount/conc of that component

  • This can be compared with a calibration curve

28
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What is retention time (GLC)

The time taken from the injection of the sample, for the component to leave to column - can be used to identify a component

29
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What types of intermolecular bonds form between triglycerides and where do they form

  • ID-IDs between fatty acid chains

  • PD-PDs between C-O/C=O on glycerol