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∫kf(u)du
k∫f(u)du
∫du
u+C
∫[f(u)±g(u)]du
∫f(u)du ± ∫g(u)du
∫(u^n)du
[u^(n+1)] / (n+1) +C
To find the integral of ∫(u^n)du, n≠___.
-1
∫du/u
ln|u|+C
∫(e^u)du
(e^u)+C
∫(a^u)du
[1/ln(a)](a^u)+C
∫sin(u)du
-cos(u)+C
∫cos(u)du
sin(u)+C
∫sec²(u)du
tan(u)+C
∫csc²(u)du
-cot(u)+C
∫sec(u)tan(u)du
sec(u)+C
∫csc(u)cot(u)du
-csc(u)+C
∫cot(u)du
ln|sin(u)|+C
∫sec(u)du
ln|sec(u)+tan(u)|+C
∫csc(u)du
-ln|csc(u)+cot(u)|+C
∫du/√(a²-u²)
arcsin(u/a)+C
∫du/u√(u²-a²)
(1/a)arcsec(|u|/a)+C
∫du/(a²+u²)
(1/a)arctan(u/a)+C
∫tan(u)du
-ln|cos(u)|+C