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mole
counting unit → can count atoms, molecules and ions
the mole connects
Mass → substances in grams
number of particles → 1 mole always contains 6.022×10²³ particles
gas volume → 1 mole occupies a certain volume (at RTP: 24dm³)
quantitative chemistry
calculating amounts in chemistry (allows to predict how much product forms, how much reactant is needed, how efficient a reaction is)
Avogadro`s Constant
NA=6.02×10²³mol^-1
→ mol^-1 = per mole
represents the number of particles in one mole
Mole Calculations
n=N/NA → particles to moles
n=number of moles
N=number of particles
NA=Avogadro`s constant
N=nxNA → moles to particles
Molar Mass
mass of one mole of a substance, measured in g mol^-1
how to calculate moles from mass
n=m/M
n=number of moles
m=mass(g)
M=molar mass(g mol^-1)
Molar Volume of Gases
at RTP (room temperature and pressure): one mole of any gas occupies 24dm³
at STP (standard temperature and pressure): one mole of any gas occupies 22.4dm³
Gas Volume Equation
n=V/24
n=moles
V=gas volume in dm³
divided by 24 because gas at RTP is always 24dm³
Composition of Substances
compounds contain elements chemically bonded together in fixed ratios by mass
Law of Conservation of Mass
Mass cannot be created or destroyed → total mass of reactants = total mass of products
Rules for balancing chemical equations
only coefficients can change
subscripts must never be changed
equations must balance for atoms and overall charge
Mole Ratios
stoichiometry uses balanced equations to determine quantities of reactants and quantities of products, the coefficients in an equation represent mole ratios
Limiting Reactants
limiting reactant is completely used up first and limits the amount of product formed
theoretical yield
maximum possible product predicted from stoichiometry
actual yield
amount of product actually obtained
percentage yield
real reactions rarely produce 100% yield
equation: %yield=actual yield/theoretical yieldx100
Concentration
measures amount of solute dissolved in a volume of solution → standard unit: mol dm³
Concentration Equation
c=n/V
c= concentration (mol dm³)
n=moles
V=Volume in dm³
Percentage by Mass
mass of solute in total mass of solution
%by mass=(mass of solute/total mass of solution)x100
%element=(mass of element in compound/molar mass of compound)x100
Dilution Calculations
moles remain constant, concentration decreases, volume increases
Dilution Equation
C1V1=C2V2
C1= initial concentration
V1= initial volume
C2= final concentration
V2= final volume
Empirical Formula
simplest whole number ratio of atoms
Molecular Formula
actual number of atoms in a molecule
Significant Figures
reflect precision of measurements
→ non-zero digits are always significant
→ leading zeros are not significant
→ trailing zeros after decimal are always significant
the final answer should usually match the least precise measurement
Uncertainty
all measurements contain uncertainty because of
instrumential limitations
human error
environmental factors
absolute uncertainty
absolute uncertainty = instrument limit (+- value)
Percentage Uncertainty
%uncertainty=(absolute uncertainty/measured value)x100
→ helps compare measurements fairly
chemists analyze data to
identify patterns
determine reliabilty
evaluate precision and accuracy
accuracy
how close results are to the true value
precision
how close repeated measurements are to each other
common sources of experimental error
heat loss
incomplete reactions
reading errors
contamination
instrument calibration errors