MATH 152 Exam III Formula Recognition

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Last updated 8:20 AM on 5/4/26
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46 Terms

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sin x Maclaurin series

sin x = sum from n=0 to infinity of (-1)^n x^(2n+1)/(2n+1)!

<p>sin x = sum from n=0 to infinity of (-1)^n x^(2n+1)/(2n+1)!</p>
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cos x Maclaurin series

cos x = sum from n=0 to infinity of (-1)^n x^(2n)/(2n)!

<p>cos x = sum from n=0 to infinity of (-1)^n x^(2n)/(2n)!</p>
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e^x Maclaurin series

e^x = sum from n=0 to infinity of x^n/n!

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Geometric series

1/(1-x) = sum from n=0 to infinity of x^n, valid for |x| < 1

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ln(1+x) series

ln(1+x) = sum from n=1 to infinity of (-1)^(n+1) x^n/n

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arctan x series

arctan x = sum from n=0 to infinity of (-1)^n x^(2n+1)/(2n+1)

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Sine vs arctan cue

Both alternate and use odd powers, but sine has factorial (2n+1)! while arctan has only (2n+1).

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Series recognition: factorial in denominator

Think e^x, sin x, or cos x depending on powers/signs.

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Series recognition: no factorial, plain powers

Think geometric series or ln/arctan depending on denominator and powers.

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Substitution in a known series

Replace every x in the base series with g(x), then simplify only if needed.

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Arctan disguise pattern

sum (-1)^n a^(2n+1)/(b^(2n)(2n+1)) = b arctan(a/b)

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Power series interval first step

Rewrite into inside^n form, solve |inside| < 1, then check endpoints separately.

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Endpoint: alternating 1/sqrt(n)

sum (-1)^n/sqrt(n) converges by Alternating Series Test.

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Endpoint: positive 1/sqrt(n)

sum 1/sqrt(n) diverges because it is p-series with p = 1/2 < 1.

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Alternating Series Test conditions

a_n decreases and a_n approaches 0.

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Absolute value inequality rule

|A| < c means -c < A < c.

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Binomial series formula

(1+x)^p = sum from n=0 to infinity of binomial(p,n) x^n

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Generalized binomial coefficient

binomial(p,n) = p(p-1)(p-2)…(p-n+1)/n!

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Binomial series first terms

(1+x)^p = 1 + px + p(p-1)x^2/2! + p(p-1)(p-2)x^3/3! + …

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Binomial series convergence

For non-integer p, use |x| < 1 first, then check endpoints separately.

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Binomial substitution cue

If the expression is (1 + something)^p, plug that something in for x.

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Parabola horizontal form

(y-k)^2 = 4p(x-h)

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Parabola vertical form

(x-h)^2 = 4p(y-k)

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Parabola vertex

Vertex is (h,k).

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Parabola: y squared cue

If y is squared, the parabola opens left or right.

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Parabola: x squared cue

If x is squared, the parabola opens up or down.

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Horizontal parabola focus and directrix

For (y-k)^2 = 4p(x-h): focus (h+p,k), directrix x = h-p.

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Vertical parabola focus and directrix

For (x-h)^2 = 4p(y-k): focus (h,k+p), directrix y = k-p.

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Completing the square rule

For y^2 + by, add and subtract (b/2)^2.

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Ellipse cue

Both x^2 and y^2 appear, same sign, sum equals 1.

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Horizontal ellipse form

(x-h)^2/a^2 + (y-k)^2/b^2 = 1, bigger denominator under x.

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Vertical ellipse form

(x-h)^2/b^2 + (y-k)^2/a^2 = 1, bigger denominator under y.

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Ellipse center

Center is (h,k).

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Ellipse vertices

Move a units from the center along the major axis.

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Ellipse foci relationship

c^2 = a^2 - b^2.

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Ellipse direction cue

Bigger denominator tells the major axis direction.

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Hyperbola cue

Both x^2 and y^2 appear with opposite signs.

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Horizontal hyperbola form

(x-h)^2/a^2 - (y-k)^2/b^2 = 1.

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Vertical hyperbola form

(y-k)^2/a^2 - (x-h)^2/b^2 = 1.

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Hyperbola direction cue

The positive fraction tells the opening direction.

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Hyperbola vertices

Move a units from the center in the opening direction.

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Hyperbola foci relationship

c^2 = a^2 + b^2.

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Horizontal hyperbola asymptotes

y-k = plus/minus (b/a)(x-h).

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Vertical hyperbola asymptotes

y-k = plus/minus (a/b)(x-h).

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Ellipse vs hyperbola c formula

Ellipse: c^2 = a^2 - b^2. Hyperbola: c^2 = a^2 + b^2.

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Conic quick classifier

Parabola has one squared variable; ellipse has same-sign squared terms; hyperbola has opposite-sign squared terms.