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Series circuit
A string of two or more components connected end-to-end in the same loop to a power supply
Parallel circuit
Two or more components attached along separate branches of the circuit
Current in a series circuit
Same at all points around the loop
PD in a series circuit
Shared between the individual components; the sum of PDs across components equals the PD of the power supply
Two disadvantages of series circuits
(1) If one component breaks, all others stop working.
(2) Components cannot be controlled (switched on/off) separately
Advantages of parallel circuits
Components can be individually controlled using their own switches; if one component stops working, others continue to function
Current in a parallel circuit
Current splits at junctions — some goes one way, rest goes the other; current in each branch is smaller than the current from the power supply
PD in a parallel circuit
Voltage across each component in parallel is the same
Summary: Series vs Parallel
Series — current: same; voltage: shared; resistance: R_total = R₁ + R₂ + R₃. Parallel — current: splits; voltage: same across each branch; resistance: R_total < smallest individual R
Combined resistance in series
R = R₁ + R₂ + R₃ + … — total resistance is the SUM of individual resistances
Why does adding resistors in series INCREASE total resistance?
More resistors means charge has more to pass through → greater overall opposition to current
Combined resistance in parallel
Total (net/combined) resistance DECREASES — always LESS than the smallest individual resistor
Why does adding resistors in parallel DECREASE total resistance?
Each resistor creates an extra path along which charge can flow → more charge can flow overall → smaller overall resistance
Total voltage in series (equation)
V_total = V₁ + V₂ + V₃ (sum of PDs across each component)
Total current in parallel (equation)
I_total = I₁ + I₂ + I₃ (sum of currents in each branch)
Worked example: finding R₂ in series
Step 1: Write equation for combined resistance (R = R₁ + R₂ + R₃).
Step 2: Substitute values.
Step 3: Rearrange for unknown (R₂ = R − R₁ − R₃)
[PAG] Aim: Investigating Series & Parallel Circuits
Use resistors and filament lamps to test series and parallel circuits; start with a single resistor/lamp in series with a cell, then build with additional resistor in series OR parallel
[PAG] Independent variable
Potential difference, V
[PAG] Dependent variable
Current, I
[PAG] Control variables
PD of power supply; use of the same equipment (wires)
[PAG] Equipment
Cell/battery, ammeter, voltmeter, fixed resistors, filament lamp, switch, connecting wires
[PAG] Method (step-by-step)
(1) Set up circuit with single fixed resistor. (2) Record voltage (voltmeter) and current (ammeter). (3) For each pair of V and I, calculate resistance and record. (4) Change resistor, repeat steps 2-3. (5) Arrange two resistors in SERIES, repeat. (6) Arrange two resistors in PARALLEL, repeat. (7) Replace fixed resistor with filament lamp, repeat from step 1
[PAG] Analysis equation
R = V ÷ I (calculate resistance for each voltage/current reading)
[PAG] Expected results: series
Total resistance of two resistors in series = SUM of their individual resistances
[PAG] Expected results: parallel
Total resistance of two resistors in parallel = LESS than either of the individual resistances
[PAG] Systematic errors
Voltmeter and ammeter should start from zero — avoid zero error
[PAG] Random errors
Voltmeter and ammeter have small resistance → readings slightly inaccurate; temperature of equipment could affect resistance (must be controlled); take multiple readings to reduce uncertainty
[PAG] Safety considerations
(1) High current through thin wire makes it very hot — don't touch when on. (2) Switch off power supply if burning smell detected. (3) No liquids near equipment. (4) Components get hot at high voltage — careful handling, especially filament lamp. (5) Disconnect between readings to avoid overheating
Current at a junction rule
Current flowing INTO a junction = current flowing OUT of junction (charge is conserved)
Direction of conventional current
From POSITIVE terminal to NEGATIVE terminal of cell/battery (through external circuit)
Direction of electron flow
From NEGATIVE terminal to POSITIVE terminal — OPPOSITE to conventional current
Why are conventional current and electron flow opposite?
Conventional current was defined as positive charge flow before electrons were discovered; actually electrons (negative) move the other way
Worked example: finding missing current at a junction
Step 1: Recall current is conserved at a junction. Step 2: Identify total current flowing IN. Step 3: Subtract the known branch current(s) from total to find the missing one
Testing resistance: components investigated
Filament lamps, diodes, thermistors, LDRs — all have variation of resistance that needs testing
Circuit for testing resistance (universal setup)
Voltmeter in PARALLEL across component being tested; ammeter in SERIES with rest of components; variable resistor in series to control current
Equation for calculating resistance in PAG
R = V ÷ I
Testing filament lamp / diode
Current (independent variable) changed using variable resistor; voltage across component measured with voltmeter; resistance calculated for each reading
Testing LDR: method
(1) Begin with lamp turned off — dark room.
(2) Record voltmeter and ammeter readings.
(3) Slowly increase light intensity using dimmer switch.
(4) Record readings at each step
Testing thermistor: method
(1) Begin with heater turned off.
(2) Record voltmeter and ammeter readings.
(3) Slowly increase temperature using dimmer switch.
(4) Record readings at each temperature
Testing LDR/thermistor: important rule
Lamp/heater must be CLOSE but NOT TOUCHING the component; wait a few seconds for LDR/thermistor to react to the environmental change before taking readings
Exam tip: circuit diagrams for testing resistance
(1) Ammeter in series. (2) Voltmeter in parallel across component. (3) Use correct circuit symbol. (4) Include variable resistor to vary current. (5) Connect to power supply (below 15 V) to avoid affecting component resistance
What is electrical power?
The rate of energy transfer, or the amount of energy transferred per second
What does power of a device depend on?
The voltage (PD) of the device; the current through the device
Unit of power
Watt (W); 1 W = 1 joule per second (1 J/s)
Power equation 1
P = I × V; where P = power (W), I = current (A), V = potential difference (V)
Power equation 2 (in terms of resistance)
P = I² × R (derived by combining P = IV with V = IR)
Power equation 3 (in terms of resistance)
P = V² ÷ R (derived by combining P = IV with I = V/R)
When to use P = I²R vs P = V²/R
P = I²R if you know current and resistance; P = V²/R if you know voltage and resistance; P = IV if you know current and voltage
Worked example: P = IV
Step 1: List known quantities. Step 2: Write equation. Step 3: Rearrange if needed. Step 4: Substitute and calculate
Mnemonic for power equations
"Twinkle Twinkle Little Star, Power equals I squared R" — helps remember P = I²R; use this when you know current and resistance
What is "work done" in a circuit?
Work is done when charge flows through a circuit; work done = energy transferred
What does energy transferred by electrical work depend on?
Current (I); potential difference (V); time (t)
Energy transferred equation 1
E = P × t; where E = energy (J), P = power (W), t = time (s)
Energy transferred equation 2
E = I × V × t (derived by substituting P = IV into E = Pt)
Energy transferred equation 3 (in terms of charge)
E = Q × V; where Q = charge (C), V = potential difference (V)
Energy conservation in a circuit
Energy supplied by battery = energy transferred to all components in the circuit (over a given time)
Worked example: E = IVt
Step 1: List known quantities (convert time to seconds). Step 2: Write equation (E = IVt). Step 3: Substitute and calculate
Exam tip: "energy transferred" vs "work done"
Used interchangeably in exam equations — mean the same thing
Exam tip: units for time in energy/power equations
Always convert time to SECONDS before using in equations (e.g. 1 minute = 60 s)