equilibrium

gen chem2

when Q > 1

the reaction is product favored

when Q < 1

the reaction is reactant favored

when Qc = Kc

it is not at equilibrium and nothing needs to occur to make the reaction at equilibrium

when Qc < Kc

it is not at equilibrium and the reactants need to be converted into products (shift RIGHT)

when Qc > Kc

it is not at equilibrium and the products need to be converted into reactants (shift LEFT)

when Qc = 0.60, what does this mean for the Kc value?

the reaction is not at equilibrium and it is smaller than the Qc value, making this reactant favored and there needs to be more products made, shifting the reaction right.

1. No

2. The reaction will shift right

3. More products will form

1. No

2. Shift left

3. Decreases

1. Qc = 0.1

2. Qc < Kc

3. The reaction will proceed right

1. Qc = 0.125

2. Shift right

3. Reactant favored

1. Qc = 0.33

2. Qc < Kc

3. Shifts right

1. Qc = 2.5

2. Shift left

3. B decreases & A

B, shift right

Le Chatiler’s Principle

equilibrium adjusts based on disturbances in pressure, temperature, or a component concentration

What CHANGES the K-value

temperature

What DOES NOT change the K-value

concentration, pressure, volume, and catalysts.

concentration and pressure/volume

shifts equilibrium left/right

catalysts

makes the reaction rate faster but does not change the k-value